AQA A-Level Chemistry Paper 3, 2017: Question 14
1 mark · Easy difficulty · Multiple Choice
Identify which reaction step in a multi-stage synthesis occurs by nucleophilic substitution.
Practise this questionQuestion
Question text
14 The reaction sequence shows how CH3CH3 can be converted into BrCH2CH2Br
Which step occurs by nucleophilic substitution?
[1 mark]
A Step A
B Step B
C Step C
D Step D
Mark scheme
Show the mark scheme
14 B
How to answer it
Organic Reaction Mechanisms in a Synthetic Pathway
This question assesses your ability to identify fundamental organic reaction types and mechanisms across multi-step synthetic pathways. Specifically, it tests your understanding of halogenoalkane hydrolysis (nucleophilic substitution), alkane halogenation (free-radical substitution), alcohol dehydration (acid-catalysed elimination), and alkene halogenation (electrophilic addition).
Question 14 Analysis
Identifying Reaction Types Across a Multi-Step Organic Route
✅ Correct Answer
B — Step B
In Step B, chloroethane ( CH₃CH₂Cl ) reacts with hydroxide ions from aqueous sodium hydroxide ( NaOH ) to form ethanol ( CH₃CH₂OH ). The hydroxide ion ( :OH⁻ ) acts as a nucleophile, attacking the electron-deficient δ+ carbon and substituting the chloride ion.
💡 Complete Step Breakdown
- Step A: CH₃CH₃ + Cl₂ → CH₃CH₂Cl
Mechanism: Free-radical substitution (initiated by UV light). - Step B: CH₃CH₂Cl + NaOH(aq) → CH₃CH₂OH
Mechanism: Nucleophilic substitution (hydrolysis). - Step C: CH₃CH₂OH → CH₂=CH₂ (conc. H₂SO₄ )
Mechanism: Acid-catalysed elimination (dehydration). - Step D: CH₂=CH₂ + Br₂ → BrCH₂CH₂Br
Mechanism: Electrophilic addition across the C=C double bond.
🧠 Exam Technique & Strategy
- Classify the functional group change: Look at the functional group in the reactant and product for each step before reading the multiple-choice options.
- Identify attacking species: In Step B, :OH⁻ has a lone pair of electrons to donate to a δ+ carbon atom, defining it as a nucleophile.
- Use elimination: Step A starts with an alkane (saturated hydrocarbon), which only undergoes free-radical substitution. Steps C and D involve making or breaking a double bond (elimination and addition respectively), ruling them out immediately.
❌ Common Errors & Misconceptions
- Confusing Substitution with Elimination: Reacting a haloalkane with NaOH can lead to elimination (forming an alkene) if ethanolic NaOH and high heat are used. Here, the product is clearly shown as the alcohol, confirming nucleophilic substitution.
- Confusing Nucleophilic and Electrophilic Addition: In Step D, the bromine molecule is polarised by the high electron density of the C=C double bond, making the attacking species an electrophile, not a nucleophile.
- Misidentifying Step A: Step A replaces a hydrogen with chlorine, which is a substitution reaction, but it is free-radical substitution, not nucleophilic.
📐 Summary of Core Mechanism Terminology (AQA A-Level)
- Nucleophilic Substitution: Typical of halogenoalkanes reacting with aqueous OH⁻ , CN⁻ , or excess ethanolic NH₃ .
- Electrophilic Addition: Typical of alkenes reacting with halogens ( Br₂ ), hydrogen halides ( HBr ), or conc. H₂SO₄ .
- Elimination: Typical of halogenoalkanes with hot ethanolic KOH , or alcohols with hot concentrated H₂SO₄ or H₃PO₄ .
- Free-Radical Substitution: Typical of alkanes reacting with halogens in the presence of ultraviolet (UV) radiation.
Topics
Organic Chemistry · 3.3.3 Halogenoalkanes
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.