AQA A-Level Chemistry Paper 3, 2017: Question 24
1 mark · Medium difficulty · Multiple Choice
Identify which compound among four chlorinated propane and propene derivatives does not exhibit stereoisomerism.
Practise this questionQuestion
Question text
24 Which compound does not show stereoisomerism?
[1 mark]
A 1,2-dichloropropene
B 1,2-dichloropropane
C 1,3-dichloropropene
D 1,3-dichloropropane
Mark scheme
Show the mark scheme
24 D
How to answer it
Stereoisomerism in Substituted Propanes and Propenes
This multiple-choice question assesses your ability to distinguish between compounds that show stereoisomerism (both E/Z geometric isomerism and optical isomerism) and those that do not. You need to draw and evaluate structural formulas to check for restricted rotation with two different groups on each double-bond carbon (E/Z) or a chiral centre (an asymmetric carbon atom bonded to four different groups).
Question 24 Analysis
Identification of the Molecule That Does NOT Exhibit Stereoisomerism [1 Mark]
✅ Correct Answer
Correct Option: D (1,3-dichloropropane)
- Structure: Cl-CH₂-CH₂-CH₂-Cl
- Contains only single C–C bonds (free rotation, so no E/Z isomerism).
- Carbon 1 is bonded to: 2× H, 1× Cl, 1× alkyl chain. (Not chiral)
- Carbon 2 is bonded to: 2× H, 2× identical -CH₂Cl groups. (Not chiral)
- Carbon 3 is bonded to: 2× H, 1× Cl, 1× alkyl chain. (Not chiral)
- Since there is no chiral centre and no restricted rotation with differing groups, it shows no stereoisomerism.
💡 Key Knowledge
Stereoisomers have the same structural formula but a different spatial arrangement of atoms. Two types are assessed:
- E/Z Isomerism: Requires a C=C double bond (restricted rotation) and each carbon of the C=C must be bonded to two different groups.
- Optical Isomerism: Requires a chiral centre (a carbon atom attached to four different groups), resulting in non-superimposable mirror images (enantiomers).
📐 Step-by-Step Option Breakdown
| Option | Displayed / Structural Formula | Type of Stereoisomerism | Explanation |
|---|---|---|---|
| A: 1,2-dichloropropene | CH(Cl)=C(Cl)CH₃ | E/Z Isomerism | • C1 is attached to -H and -Cl (two different groups). • C2 is attached to -Cl and -CH₃ (two different groups). Shows stereoisomerism (E and Z isomers). |
| B: 1,2-dichloropropane | CH₂Cl-CH(Cl)-CH₃ | Optical Isomerism | • C2 is bonded to 4 different groups: -H, -Cl, -CH₃, and -CH₂Cl. It possesses a chiral centre and therefore shows optical isomerism. |
| C: 1,3-dichloropropene | CH(Cl)=CH-CH₂Cl | E/Z Isomerism | • C1 is attached to -H and -Cl (two different groups). • C2 is attached to -H and -CH₂Cl (two different groups). Shows stereoisomerism (E and Z isomers). |
| D: 1,3-dichloropropane | CH₂Cl-CH₂-CH₂Cl | None | • No C=C double bond (no E/Z). • C2 has two identical -H atoms and two identical -CH₂Cl groups. Cannot show stereoisomerism. |
🧠 Exam Technique
- Watch the word "NOT": Questions containing negative keywords are classic traps. Underline "not" as soon as you read it.
- Look for both types: Remember that "stereoisomerism" is an umbrella term covering both geometric (E/Z) and optical isomerism.
- Symmetry check for optical centres: In propane chains, always check Carbon 2. If the two arms are identical (like -CH₂Cl in option D), C2 cannot be chiral.
❌ Common Errors
- Forgetting Optical Isomerism: Many students instantly rule out options B and D because they are alkanes (no double bond), mistakenly assuming stereoisomerism means only E/Z. Option B is chiral!
- Misidentifying C=C substituents: Rushing to sketch 1,3-dichloropropene (C) and incorrectly thinking C2 has two identical groups, overlooking that the H atom and -CH₂Cl group are different.
Topics
Organic Chemistry · 3.3.1 Introduction to Organic Chemistry · 3.3.7 Optical Isomerism
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.