AQA A-Level Chemistry Paper 3, 2017: Question 6
1 mark · Easy difficulty · Multiple Choice
Identify the correct order of melting points for the Period 3 elements sulfur, phosphorus, chlorine, and argon.
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Question text
06 Which is the correct order of melting points of these Period 3 elements?
[1 mark]
A phosphorus > sulfur > chlorine > argon
B argon > chlorine > phosphorus > sulfur
C sulfur > phosphorus > chlorine > argon
D chlorine > phosphorus > sulfur > argon
Mark scheme
Show the mark scheme
6 C
How to answer it
Period 3 Periodicity: Melting Points of Non-Metals
This question assesses your understanding of Period 3 trends in physical properties, specifically the melting points of molecular non-metals:
- Identifying the molecular formula and structure of non-metallic Period 3 elements (P₄, S₈, Cl₂, Ar).
- Relating molecular size and electron count to the strength of van der Waals (induced dipole-dipole) forces.
- Understanding why sulfur has a higher melting point than phosphorus despite being adjacent in the periodic table.
Question 06 Breakdown
Multiple Choice: Order of Melting Points [1 mark]
✅ Correct Answer: C
sulfur > phosphorus > chlorine > argon
Sulfur exists as S₈ molecules, phosphorus as P₄, chlorine as Cl₂, and argon as individual atoms (Ar). Because melting involves breaking only weak van der Waals forces between molecules, the order directly tracks molecular size and electron count: S₈ > P₄ > Cl₂ > Ar.
💡 Key Knowledge
All four of these elements exist as simple molecular (or monoatomic) substances:
| Element | Formula | Electrons / Particle |
|---|---|---|
| Sulfur | S₈ | 128 e⁻ |
| Phosphorus | P₄ | 60 e⁻ |
| Chlorine | Cl₂ | 34 e⁻ |
| Argon | Ar | 18 e⁻ |
More electrons = larger electron cloud = greater polarisability = stronger van der Waals forces = more thermal energy needed to overcome them.
📐 Step-by-Step Comparison
- Classify the structures: None of these are giant lattices (unlike Si, which has giant covalent structure and the highest melting point in Period 3). They all have simple molecular/atomic structures.
- Identify what breaks on melting: Only intermolecular forces (van der Waals forces) are overcome, NOT covalent bonds.
- Compare particle sizes:
• S₈ has 8 atoms (128 electrons) → strongest intermolecular forces.
• P₄ has 4 atoms (60 electrons) → second strongest.
• Cl₂ has 2 atoms (34 electrons) → third.
• Ar is monoatomic (18 electrons) → weakest van der Waals forces. - Assemble descending order: S > P > Cl > Ar.
❌ Common Errors & Misconceptions
- Assuming a strict left-to-right trend: Many students pick Option A because phosphorus (atomic number 15) comes before sulfur (16), incorrectly assuming melting point steadily decreases across the non-metals.
- Confusing covalent bonds with intermolecular forces: Stating that "covalent bonds break on melting". Covalent bonds inside the S₈ or P₄ molecules remain completely intact.
- Thinking phosphorus is P₂: Nitrogen in Period 2 forms diatomic N₂, but phosphorus forms tetrahedral P₄ molecules.
🧠 Exam Technique & Examiner Insight
- The "Peak at Sulfur" rule: In Period 3 melting point graphs, silicon forms the highest peak (giant covalent). Across the molecular non-metals, the graph dips at phosphorus (P₄), jumps back up at sulfur (S₈), and then falls steeply through Cl₂ down to Ar. Remembering the "peak at sulfur" instantly eliminates options A, B, and D!
- Process of Elimination:
• Argon is a monoatomic gas at room temperature, so it must have the lowest melting point of the set. This eliminates B immediately.
• Sulfur (S₈) has a higher melting point than phosphorus (P₄). That instantly narrows the choice down to C.
Topics
Inorganic Chemistry · Physical Chemistry · 3.2.1 Periodicity · 3.1.3 Bonding
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.