AQA A-Level Chemistry Paper 3, June 2018: Question 13
1 mark · Easy difficulty · Multiple Choice
Identify which rate against concentration graph represents a reaction that is second order with respect to reactant X.
Practise this questionQuestion
Question text
13 A series of experiments was carried out to find the order of reaction with respect to
reactant X. In these experiments, only the concentration of X was changed.
Which graph would show that the reaction is second-order with respect to X?
[1 mark]
A
B
C
D
Mark scheme
Show the mark scheme
13 D
How to answer it
Rate-Concentration Graphs & Reaction Orders
This question assesses your ability to relate mathematical rate equations to graphical representations in chemical kinetics, specifically:
- Interpreting Rate vs Concentration graphs for reactants.
- Distinguishing between zero-order, first-order, and second-order relationships graphically.
- Preventing confusion between rate vs concentration graphs and concentration vs time graphs.
Question 13
Multiple Choice — Rate of Reaction vs Concentration of X
✅ Correct Answer
D
For a reaction that is second-order with respect to X, the rate equation is:
Rate = k[X]²
Plotting Rate (y-axis) against [X] (x-axis) yields a quadratic relationship ( y = kx² ), which is an upwardly curving parabola starting at the origin (0, 0).
💡 Key Knowledge: Rate vs [Reactant] Profiles
- Zero Order ( Rate = k ): Horizontal straight line. Changing [X] does not affect the rate.
- First Order ( Rate = k[X] ): Straight line with a constant positive gradient passing through the origin (Curve C).
- Second Order ( Rate = k[X]² ): Upward curve with an increasing gradient starting at the origin (Curve D).
- Negative Orders: As [X] increases, rate decreases (Curves A and B). These are not standard positive integer orders tested at A-Level.
📐 Mathematical Analysis
Consider what happens to the rate as concentration doubles from 1 to 2 units:
- First Order (Line C):
Rate₁ = k(1) = k
Rate₂ = k(2) = 2k
Gradient is constant (straight line). - Second Order (Curve D):
Rate₁ = k(1)² = k
Rate₂ = k(2)² = 4k
Rate quadruples when concentration doubles; the gradient increases as [X] increases (exponential-style upward curve).
🧠 Exam Technique: 2-Step Graph Check
Step 1: Always check the axes first!
- If y-axis = Rate and x-axis = [Concentration], rate goes up with concentration for positive orders.
- If y-axis = [Concentration] and x-axis = Time, the curve goes down as reactant is used up!
Step 2: Match order to algebraic power:
- Order 1 → Power 1 ( y = mx ) → Straight line
- Order 2 → Power 2 ( y = mx² ) → Upward curve
❌ Common Examiner Traps & Mistakes
- Selecting C instead of D: The most common error. Students remember that rate increases with concentration for both 1st and 2nd order, but fail to realise that a straight line (C) represents a directly proportional first-order relationship, not second-order.
- Selecting A: Students frequently mix up this graph with a concentration-time graph. A downward curve like A is characteristic of a concentration-time graph for a first-order or second-order reaction, but on a rate-concentration axis, it would imply a negative order.
- Selecting B: A downward straight line on a concentration-time graph represents a zero-order reaction. On this graph, it represents an inverse linear relationship.
Topics
Physical Chemistry · 3.1.9 Rate Equations
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.