AQA A-Level Chemistry Paper 3, June 2018: Question 18

1 mark · Easy difficulty · Multiple Choice

Identify the products of the reaction between chlorine and cold, dilute aqueous sodium hydroxide.

Practise this question

Question

Question 18: Chlorine reacts with cold, dilute, aqueous sodium hydroxide. Which is a complete list of the products? A: Sodium chloride, sodium chlorate(I) and water; B: Sodium chlorate(I) and water; C: Sodium chloride, sodium chlorate(V) and water; D: Sodium chloride and sodium chlorate(I). Worth 1 mark.
Question text

18 Chlorine reacts with cold, dilute, aqueous sodium hydroxide.

Which is a complete list of the products?

[1 mark]

A Sodium chloride, sodium chlorate(I) and water

B Sodium chlorate(I) and water

C Sodium chloride, sodium chlorate(V) and water

D Sodium chloride and sodium chlorate(I)

Mark scheme

Show the mark scheme Mark scheme table row showing question number 18 with the correct answer given as A.

18 A

How to answer it

Reaction of Chlorine with Cold, Dilute Sodium Hydroxide

📋 What this question tests

This question assesses your recall and understanding of Group 7 (Halogen) chemistry, specifically:

  • The disproportionation reaction of chlorine in cold, dilute, aqueous sodium hydroxide.
  • Correct identification of all chemical products (salts and water) formed in this reaction.
  • Distinction between the cold, dilute condition and the hot, concentrated condition.

Question 18 Analysis

Multiple Choice (1 Mark)

✅ Correct Answer: A

Sodium chloride, sodium chlorate(I) and water

Award [1 mark] for selecting option A.

📐 Balanced Chemical Equation

The reaction taking place is:

Cl₂(aq) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H₂O(l)

Products formed:

  • NaCl = Sodium chloride
  • NaClO = Sodium chlorate(I) (active ingredient in household bleach)
  • H₂O = Water

💡 Key Knowledge: Disproportionation

This is a classic disproportionation reaction (where an element is simultaneously oxidised and reduced):

  • Cl in Cl₂: Oxidation state is 0.
  • Cl in NaCl: Oxidation state is −1 (reduction).
  • Cl in NaClO: Oxidation state is +1 (oxidation).

Notice that for this redox process to be balanced, both chloride and chlorate(I) must be formed alongside water.

🧠 Exam Technique: Temperature Conditions

Always highlight the temperature and concentration specified in the stem:

  • Cold, dilute NaOH: Forms chlorate(I) → NaClO (Option A).
  • Hot, concentrated NaOH: Chlorine disproportionates further into chlorate(V) → NaClO₃ :
    3Cl₂ + 6NaOH → 5NaCl + NaClO₃ + 3H₂O

Spotting "cold, dilute" instantly rules out Option C!

❌ Common Misconceptions & Distractor Traps

  • Confusing Option C (Sodium chlorate(V)): Students often mix up the conditions. Chlorate(V) ( ClO₃⁻ ) only forms in hot, concentrated alkali.
  • Forgetting by-products (Options B & D):
    • Option B omits NaCl . The reaction is redox; chlorine cannot only be oxidised without also being reduced!
    • Option D omits H₂O . Always verify that oxygen and hydrogen atoms from hydroxide ions end up in the products.

Topics

Inorganic Chemistry · 3.2.3 Group 7(17), The Halogens

Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.