AQA A-Level Chemistry Paper 3, June 2018: Question 24
1 mark · Medium difficulty · Multiple Choice
Identify the correct order of decreasing pH for equimolar aqueous solutions of ammonia, ethylamine, and phenylamine.
Practise this questionQuestion
Question text
24 Aqueous solutions of ammonia, ethylamine and phenylamine are prepared.
Each solution has the same concentration.
Which is the correct order for the pH values of these solutions?
[1 mark]
A ammonia > ethylamine > phenylamine
B ammonia > phenylamine > ethylamine
C ethylamine > ammonia > phenylamine
D ethylamine > phenylamine > ammonia
Mark scheme
Show the mark scheme
24 C
How to answer it
Relative Base Strengths and pH of Aqueous Amines
This question tests your understanding of Brønsted-Lowry base strength in nitrogen compounds (ammonia, primary aliphatic amines, and aromatic amines). You must link base strength (the availability of the lone pair on the nitrogen atom to accept a proton, H⁺) directly to the resulting pH of equimolar aqueous solutions.
Question 24
Multiple Choice — 1 Mark
Aqueous solutions of ammonia, ethylamine and phenylamine are prepared. Each solution has the same concentration.
Which is the correct order for the pH values of these solutions?
- A ammonia > ethylamine > phenylamine
- B ammonia > phenylamine > ethylamine
- C ethylamine > ammonia > phenylamine
- D ethylamine > phenylamine > ammonia
✅ Correct Answer: C
ethylamine > ammonia > phenylamine
A stronger base accepts protons more readily from water, producing a higher concentration of hydroxide ions [OH⁻], which results in a higher pH. Therefore, the order of decreasing pH mirrors the order of decreasing base strength:
Ethylamine (strongest base, highest pH) > Ammonia > Phenylamine (weakest base, lowest pH)
💡 Key Knowledge
- Base definition: Amines act as weak Brønsted-Lowry bases by using the lone pair of electrons on the nitrogen atom to form a dative bond with a proton (H⁺).
- Ethylamine (CH₃CH₂NH₂): The ethyl group has a positive inductive (+I) electron-releasing effect. This increases the electron density on the N atom, making the lone pair more available to accept a proton than in ammonia.
- Ammonia (NH₃): Serves as the benchmark with no electron-donating or withdrawing groups.
- Phenylamine (C₆H₅NH₂): The lone pair of electrons on the nitrogen overlaps and delocalises into the benzene ring's π-electron cloud. This significantly reduces electron density on N, making the lone pair much less available to accept H⁺.
🧠 Exam Technique & Logic
- Connect pH to Base Strength: Higher base strength → greater extent of ionisation in water ( B + H₂O ⇌ BH⁺ + OH⁻ ) → higher [OH⁻] → lower [H⁺] → higher pH.
- Use the "Aliphatic vs Aromatic" rule: Primary aliphatic amine > Ammonia > Aromatic amine. Memorise this baseline hierarchy as an essential organic trend.
- Elimination method: Knowing ethylamine is stronger than ammonia immediately eliminates options A and B. Knowing phenylamine is weaker than ammonia eliminates option D.
❌ Common Errors & Misconceptions
- Inverting the pH scale: Confusing acidity and basicity—thinking that a stronger base has a lower pH (closer to 7), rather than a higher pH (closer to 14).
- Ranking phenylamine above ammonia: Forgetting that delocalisation of the nitrogen lone pair into the aromatic ring dramatically reduces basicity.
- Assuming all organic amines are stronger than ammonia: Only alkyl amines are stronger; aryl amines (like phenylamine) are considerably weaker bases than ammonia.
Topics
Organic Chemistry · Physical Chemistry · 3.3.11 Amines · 3.1.12 Acids and Bases
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.