AQA A-Level Chemistry Paper 2, 2018: Question 1
10 marks · Medium difficulty · State/Explain/Describe
Write equations and conditions for alkane combustion, catalytic cracking, free-radical chlorination of butane, and ozone depletion by CFCs.
Practise this questionQuestion
Question text
01 This question is about the reactions of alkanes.
01.1 Alkanes can be used as fuels.
Give an equation for the combustion of heptane (C7H16) in an excess of oxygen.
[1 mark]
01.2 Heptane can be obtained from the catalytic cracking of hexadecane (C16H34) at a high
temperature.
Identify a suitable catalyst for this process.
Give one condition other than high temperature.
Give an equation for the catalytic cracking of one molecule of hexadecane to produce
one molecule of heptane, one molecule of cyclohexane and one other product.
[3 marks]
Catalyst
Condition
Equation
01.3 Alkanes can be used in free-radical substitution reactions to produce
halogenoalkanes.
Give equations for the propagation steps in the reaction of butane to form
2-chlorobutane.
[2 marks]
01.4 Chlorofluorocarbons (CFCs) are a group of halogenoalkanes currently banned in
many countries. They cannot be used as solvents or refrigerants because of their
effect on the environment.
*02* The structure of a CFC is shown.
Identify the radical produced from this CFC that is responsible for the depletion of
ozone in the atmosphere.
Explain, with the aid of equations, why a single radical can cause the decomposition
of many molecules of ozone.
[4 marks]
Radical
Explanation
Mark scheme
Show the mark scheme
Question Answers Mark Additional Comments/Guidance
C7H16 + 11O2 7CO2 + 8H2O Ignore state symbols
01.1 M1
Allow multiples
Zeolite OR aluminosilicate M1 Allow porous pot / aluminium oxide / alumina / silica /
silicon dioxide
Slight/moderate pressure
01.2 M2 Slightly above atmospheric – allow 1-5 atmospheres
C H C H + C H + C H / 100-500kPa
16 34 7 16 6 12 3 6
M3
If incorrect radical or ambiguous radical lose M1 but
Cl + CH3CH2CH2CH3 CH3CH2CHCH3 + HCl can award M2 for ecf in each equation.
M1
01.3 + Cl CH CH CHClCH +
CH3CH2CHCH3 2 3 2 3 Cl M2 Allow equations in either order
Allow dot anywhere on the second carbon
Ignore extra initiation and termination steps
Cl. M1 Allow Cl or Chlorine in M1 and M4
Cl. + O ClO. + O M2 Penalise absence of dot once in the equations
Allow dot anywhere on the radical
ClO. + O Cl. + 2O M3
32 Apply the list principle in the equations and penalise
01.4
. M4 initiation from Cl2
Cl is regenerated (and causes a chain reaction in the
decomposition of ozone) Allow equations in either order.
Ignore Cl. acts as a catalyst
Total 10
How to answer it
Alkanes: Combustion, Cracking & Halogenation
This question assesses fundamental organic mechanisms and industrial chemistry for alkanes:
- Combustion Stoichiometry: Balancing complete combustion reactions in excess oxygen.
- Catalytic Cracking: Industrial conditions (zeolite catalyst, moderate pressure) and stoichiometric balance of non-branched/cyclic products.
- Free-Radical Substitution: Regioselective propagation steps targeting secondary halogenoalkanes (2-chlorobutane).
- Environmental Halogenoalkane Chemistry: Catalytic breakdown of stratospheric ozone by chlorine free radicals derived from CFCs.
Complete Combustion of Heptane
Writing balanced molecular equations for complete hydrocarbon combustion
✅ Correct Answer
C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O
🧠 Exam Technique
- Carbon balance: 7 Carbons in C₇H₁₆ → produces 7CO₂ .
- Hydrogen balance: 16 Hydrogens in C₇H₁₆ → produces 8H₂O (8 × 2 = 16).
- Oxygen balance: (7 × 2) + 8 = 22 oxygen atoms needed → 11O₂ .
❌ Common Errors
- Writing incomplete combustion products: The question states "in an excess of oxygen", so products must strictly be CO₂ and H₂O. Do not write CO or C (soot).
- Miscounting oxygens: Forgetting that O₂ is diatomic and writing 22O₂ instead of 11O₂.
Catalytic Cracking of Hexadecane
Conditions, catalysts, and balancing hydrocarbon cracking reactions
✅ Correct Answers
Catalyst: Zeolite (or aluminosilicate) [M1]
Condition: Slight / moderate pressure (or 1–5 atm / 100–500 kPa) [M2]
Equation: C₁₆H₃₄ → C₇H₁₆ + C₆H₁₂ + C₃H₆ [M3]
💡 Key Knowledge: Thermal vs Catalytic
Always distinguish the two types of cracking taught at A-Level:
- Thermal: High temperature (400–900°C), high pressure (up to 70 atm). Produces mainly alkenes.
- Catalytic: High temperature (~450°C), slight/moderate pressure, zeolite catalyst. Produces motor fuels (branched alkanes, cycloalkanes, aromatics).
📐 Deducing the Unknown Product
You are told hexadecane (C₁₆H₃₄) produces 1 heptane (C₇H₁₆) and 1 cyclohexane (cycloalkanes have general formula CₙH₂ₙ, so C₆H₁₂):
- Remaining Carbons: 16 - (7 + 6) = 16 - 13 = 3 Carbons
- Remaining Hydrogens: 34 - (16 + 12) = 34 - 28 = 6 Hydrogens
- Unknown product = C₃H₆ (propene).
❌ Common Errors
- Writing "high pressure": This is an immediate error. High pressure is required for thermal cracking, whereas catalytic cracking operates at slight/moderate pressure.
- Incorrect formula for cyclohexane: Writing C₆H₁₄ (hexane) instead of C₆H₁₂ (cyclohexane ring has 2 fewer hydrogens).
Free-Radical Substitution to Form 2-Chlorobutane
Regioselective propagation mechanisms
✅ Correct Equations
Step 1:
Cl• + CH₃CH₂CH₂CH₃ → CH₃CH₂C•HCH₃ + HCl
Step 2:
CH₃CH₂C•HCH₃ + Cl₂ → CH₃CH₂CHClCH₃ + Cl•
🧠 Exam Technique: Dot Placement
The question specifies 2-chlorobutane:
- The radical formed in the first step must be a secondary radical: the radical dot must reside on carbon-2: CH₃CH₂C•HCH₃ .
- If you place the dot on carbon-1 ( •CH₂CH₂CH₂CH₃ ), you will form 1-chlorobutane and lose M1!
❌ Common Errors
- Forming CH₃CH₂CH₂CH₂Cl: Always re-read the target halogenoalkane isomer named in the stem.
- Producing Cl• + H• instead of HCl: A chlorine radical abstracts a hydrogen atom to form stable covalent HCl , never free H• radicals.
- Missing radical dots: Failing to clearly show the unpaired electron dot (•) loses the mark immediately.
CFCs and Catalytic Ozone Depletion
Chain reactions, bond enthalpies, and ozone decomposition equations
✅ Correct Answer & Equations
Radical: Cl• (chlorine radical) [M1]
Equation 1: Cl• + O₃ → ClO• + O₂ [M2]
Equation 2: ClO• + O₃ → Cl• + 2O₂ [M3]
Explanation: Cl• is regenerated (it acts as a catalyst in a repeating chain reaction) [M4]
💡 Key Knowledge: Why Chlorine, Not Fluorine?
Although the molecule contains C-F bonds, the C-Cl bond is weaker (lower bond enthalpy) than the C-F bond:
- UV radiation in the stratosphere breaks C-Cl homolytically:
R-Cl + hν → R• + Cl• - The C-F bond is too strong to be broken by this UV radiation, so fluorine radicals are not formed.
🧠 Overall Reaction Insight
Combining the two propagation steps gives the overall stoichiometric equation:
2O₃ → 3O₂
Notice that Cl• goes in at Step 1 and comes out unchanged at Step 2. This is the definition of a homogeneous catalyst, allowing one single Cl• radical to destroy thousands of ozone molecules before termination.
❌ Common Errors
- Writing F• as the attacking radical: The C-F bond does not break under stratospheric UV light.
- Stating only "it's a catalyst": The mark scheme specifically states "Ignore Cl• acts as a catalyst" on its own for M4. You must state that Cl• is regenerated!
- Writing O instead of O₃: In AQA specifications, equations must show reaction with ozone ( O₃ ), not oxygen atoms (O).
Topics
Organic Chemistry · 3.3.1 Introduction to Organic Chemistry · 3.3.2 Alkanes · 3.3.3 Halogenoalkanes
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 2, 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.