AQA A-Level Chemistry Paper 3, 2019: Question 14
1 mark · Easy difficulty · Multiple Choice
Identify which atom from H, He, Li, and Ne has the greatest first ionisation energy.
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Question text
14 Which atom has the greatest first ionisation energy?
[1 mark]
A H
B He
C Li
D Ne
Mark scheme
Show the mark scheme
14 B 1
How to answer it
Periodic Trends: Highest First Ionisation Energy
This question assesses your understanding of periodicity and atomic structure, specifically the factors determining first ionisation energy: nuclear charge, atomic radius, and electron shielding across the first two periods of the Periodic Table.
Identifying the Atom with the Greatest First Ionisation Energy
A: H | B: He | C: Li | D: Ne
✅ Correct Answer
B — Helium (He)
• Selecting B awards 1 mark.
💡 Key Knowledge
- First Ionisation Energy Definition: The energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions:
X(g) → X⁺(g) + e⁻ - The Three Core Factors:
- Atomic radius: Smaller radius = outer electrons closer to the nucleus = stronger attraction.
- Nuclear charge: More protons = greater positive charge attracting outer electrons.
- Shielding: Fewer internal electron shells = less repulsion and stronger effective nuclear pull.
- Why Helium has the highest of ALL elements: Its electron configuration is 1s² . The electrons occupy the shell closest to the nucleus (minimal atomic radius), experience zero inner-shell shielding, and are held by a nucleus with 2 protons (double that of hydrogen).
📐 Step-by-Step Element Comparison
- Compare H ( 1s¹ ) vs He ( 1s² ):
Both have electrons in the 1s orbital with no inner shielding shells. However, He has 2 protons compared to H’s 1 proton. Greater nuclear charge pulls the electrons closer, making He’s atomic radius smaller and the attraction significantly stronger (He = 2372 kJ mol⁻¹ vs H = 1312 kJ mol⁻¹). - Eliminate Period 2 Elements (Li and Ne):
Both Li ( 1s² 2s¹ ) and Ne ( 1s² 2s² 2p⁶ ) remove an electron from the second principal energy level ( n = 2 ). - Account for Shielding:
Outer electrons in Li and Ne experience shielding from the full inner 1s² core, and are located further from the nucleus. Even though Ne has 10 protons, the increased distance and shielding mean its first ionisation energy (2081 kJ mol⁻¹) is lower than Helium's (2372 kJ mol⁻¹).
❌ Common Errors & Misconceptions
- Choosing Neon (Ne): A very common error. Students see that Ne has a high nuclear charge (10 protons) and a stable full octet, forgetting that Ne’s outer electrons are in the n = 2 shell and shielded by the inner 1s² shell.
- Choosing Hydrogen (H): Confusing the fact that hydrogen is the smallest atom with it having the strongest hold on its electron, forgetting that helium has twice the nuclear charge with no additional shielding.
- Choosing Lithium (Li): Forgetting that lithium starts a new period; its outer electron is far from the nucleus and shielded, giving it one of the lowest ionisation energies among these choices (520 kJ mol⁻¹).
🧠 Exam Technique: Periodic Table "Top-Right" Rule
First ionisation energy generally increases across a period (increasing nuclear charge, similar shielding) and up a group (decreasing radius, less shielding). Following this trend to the absolute extreme leads directly to the top-right corner of the Periodic Table: Helium. Remember as a core chemistry fact: Helium has the highest first ionisation energy of all elements in the Periodic Table.
Topics
Physical Chemistry · Inorganic Chemistry · 3.1.1 Atomic Structure · 3.2.1 Periodicity
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.