AQA A-Level Chemistry Paper 2, 2021: Question 9
7 marks · Medium difficulty · State/Explain/Describe
Ozone Layer Chemistry and Radical Mechanisms This question focuses on the role of the ozone layer in protecting life from harmful UV radiation and how chlorofluorocarbons (CFCs) decompose to form chlorine radicals. It tests understanding of radical chain reactions, including catalytic ozone depletion and propagation steps in radical substitution reactions involved in forming hydrochlorofluorocarbons (HCFCs).
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Question text
09 This question is about the ozone layer in the upper atmosphere.
09.1 State why the ozone layer is beneficial for living organisms.
[1 mark]
09.2 State how chlorofluorocarbons (CFCs) form chlorine atoms in the
upper atmosphere.
[1 mark]
09.3 Give equations to show how chlorine atoms catalyse the decomposition of ozone.
[2 marks]
09.4 Hydrochlorofluorocarbons (HCFCs) have been used in place of CFCs.
In the mechanism to make an HCFC from a fluoroalkane, two incomplete steps are
shown.
Complete each step in the mechanism.
Give the name of the type of step shown by both these equations.
[3 marks]
→ ●CHF2 + HCl
●CHF2 + Cl2 →
Type of step
Mark scheme
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Question Answers Additional Comments/Guidelines Mark
09.1 Absorbs/prevents harmful uv Allow reduced risk of skin cancer from uv 1
09.2 C-Cl bonds broken (homolytically) Could show in an equation showing the bond 1
. .
Cl + O3 → ClO + O2 M1
09.3 . .
ClO + O3 → Cl + 2O2 M2
.
Cl + CH2F2 → Penalise missing dot once only M1
.
09.4 → CHClF2 + Cl M2
Propagation M3
How to answer it
Study Guide: Ozone Decomposition and Radical Mechanisms
Q1. Why Is the Ozone Layer Important?
Key point: It absorbs harmful UV radiation .
This protects living organisms from UV-related issues such as skin cancer.
Q2. How Do CFCs Form Chlorine Radicals?
Answer: C–Cl bonds are broken homolytically by UV light.
This forms chlorine radicals (Cl•), which then initiate reactions in the upper atmosphere.
Q3. Chlorine-Catalysed Ozone Breakdown
Step 1: Cl• + O3 → ClO• + O2
Step 2: ClO• + O3 → Cl• + 2O2
Overall: 2O3 → 3O2
Q4. Free Radical Propagation with HCFCs
Step 1: Cl• + CH2F2 → •CHF2 + HCl
Step 2: •CHF2 + Cl2 → CHClF2 + Cl•
Type of step: Propagation
Topics
Organic Chemistry · 3.3.2 Alkanes · 3.3.3 Halogenoalkanes
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 2, 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.