AQA A-Level Chemistry AS Paper 1, June 2022: Question 19

1 mark Β· Easy difficulty Β· Multiple Choice

Identify which given substance contains oxygen in the highest oxidation state.

Practise this question

Question

Question 19 asks: 'In which of these substances is oxygen in the highest oxidation state?' with four options: A: OF2, B: H2O, C: O2, D: H2O2. Each option has a selection lozenge beside it, worth 1 mark.
Question text

19 In which of these substances is oxygen in the highest oxidation state?

[1 mark]

A OF2

B H2O

C O2

D H2O2

Mark scheme

Show the mark scheme Mark scheme for question 19 shows the correct answer is option A (AO1), worth 1 mark, corresponding to OF2.

19 A (AO1) 1 OF2

How to answer it

Determining the Highest Oxidation State of Oxygen

πŸ“Œ What this question tests

This question assesses your understanding of rules for assigning oxidation states, the hierarchy of electronegativity (specifically fluorine being more electronegative than oxygen), and recognising common exceptions to the standard βˆ’2 rule for oxygen (such as peroxides and compounds with fluorine).

Question 19 β€’ Multiple Choice β€’ [1 Mark]

Question Analysis & Breakdown

Identifying the substance with oxygen in the highest oxidation state

βœ… Correct Answer

A: OFβ‚‚

Award 1 mark for selecting option A (AO1 recall & application).

πŸ“ Step-by-Step Evaluation

  • A (OFβ‚‚): Fluorine is always βˆ’1 in compounds.
    Oxidation state of O + 2(βˆ’1) = 0 β†’ O = +2
  • B (Hβ‚‚O): Hydrogen is +1.
    2(+1) + Oxidation state of O = 0 β†’ O = βˆ’2
  • C (Oβ‚‚): Uncombined element in its standard state.
    O = 0
  • D (Hβ‚‚Oβ‚‚): Peroxide. Hydrogen is +1.
    2(+1) + 2(O) = 0 β†’ 2(O) = βˆ’2 β†’ O = βˆ’1

Comparing values: +2 > 0 > βˆ’1 > βˆ’2

πŸ’‘ Key Knowledge: Rules for Oxygen

  • Standard rule: Oxygen is almost always βˆ’2 in compounds (e.g. Hβ‚‚O, COβ‚‚).
  • Peroxides: Oxygen is βˆ’1 (e.g. Hβ‚‚Oβ‚‚, Naβ‚‚Oβ‚‚).
  • Elemental form: Pure elements always have an oxidation state of 0 (e.g. Oβ‚‚).
  • Compounds with Fluorine: Fluorine is the most electronegative element, so F is always βˆ’1. This forces oxygen to have a positive oxidation state (+2 in OFβ‚‚).

❌ Common Misconceptions & Traps

  • Automatic "Oxygen is βˆ’2": Assuming oxygen is always βˆ’2 without checking the bonded partner.
  • Confusing "highest" with numerical magnitude: Choosing βˆ’2 (in Hβ‚‚O) because 2 looks larger than 0 or 1, forgetting that oxidation state is an algebraic scale where positive numbers are greater than negative numbers (+2 > βˆ’2).
  • Ignoring Fluorine's priority: Forgetting that fluorine outranks oxygen in electronegativity and always takes βˆ’1.

🧠 Exam Technique Tip

When asked for the "highest" or "lowest" oxidation state in multiple-choice questions, always jot down the sign and number explicitly on your paper ( +2 , βˆ’2 , 0 , βˆ’1 ) next to each option before answering. Visualising them on a number line prevents sign errors under time pressure.

Topics

Physical Chemistry Β· 3.1.7 Oxidation, Reduction and Redox Equations

Question and mark scheme from the AQA A-Level Chemistry examination, AS Paper 1, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.