AQA A-Level Chemistry Paper 3, June 2022: Question 8
1 mark · Easy difficulty · Multiple Choice
Identify which substance out of graphite, methylbenzene, poly(propene), and sodium contains no delocalised electrons.
Practise this questionQuestion
Question text
08 Which substance has no delocalised electrons?
[1 mark]
A graphite
B methylbenzene
C poly(propene)
D sodium
Mark scheme
Show the mark scheme
8 C (AO1) 1 poly(propene)
How to answer it
Delocalised Electrons Across Structure & Bonding
This question assesses your ability to recall and distinguish the bonding and electron distribution across four distinct types of chemical structures: giant covalent macromolecules, arenes (aromatic compounds), addition polymers (saturated hydrocarbons), and metallic lattices.
- Bonding Types: Identifying where delocalised π systems or electron 'seas' exist versus localised σ bonds.
- Polymer Structure: Understanding that addition polymerisation converts double bonds (with π electrons) into single σ bonds.
Identifying Substances Without Delocalised Electrons
Multiple Choice — 1 Mark (AO1)
✅ Correct Answer
C — poly(propene)
Poly(propene) is an addition polymer formed from propene. In poly(propene), the polymer chain consists entirely of single covalent C–C and C–H (σ) bonds. All valence electrons are fixed (localised) in covalent bonds, so there are no delocalised electrons.
💡 Key Knowledge: Why the Others Have Delocalised Electrons
- A graphite: Giant covalent structure where each carbon atom forms 3 σ bonds. The remaining p electron on each carbon is delocalised across the hexagonal planar sheets, allowing electrical conductivity.
- B methylbenzene: Contains a benzene ring. The 6 p-orbitals overlap side-on to form a delocalised π electron ring system above and below the plane of carbon atoms.
- D sodium: Giant metallic lattice consisting of Na⁺ cations surrounded by a sea of delocalised electrons.
🧠 Exam Technique: Elimination Strategy
For questions asking which substance has no delocalised electrons:
- Check for metals first: Sodium (D) is a group 1 metal, so it automatically possesses a metallic sea of delocalised electrons. Eliminate immediately.
- Check for standard allotropes: Graphite (A) is the classic non-metal conductor with delocalised p-electrons between layers. Eliminate immediately.
- Check for aromatic rings: Methylbenzene (B) has an aromatic benzene ring with a delocalised π cloud. Eliminate.
- Confirm the remaining choice: Poly(propene) is a long-chain alkane-like molecule. The C=C double bond in the propene monomer opened up during addition polymerisation, leaving only localised σ bonds.
❌ Common Misconceptions & Traps
- Confusing monomer with polymer: Students see the name propene and think of an alkene with a C=C double bond (which has a π bond). However, addition polymerisation breaks the π bond to form poly(propene), which is saturated.
- Overlooking the methyl group: Thinking methylbenzene's aliphatic –CH₃ group prevents delocalisation, forgetting that the aromatic ring contains the delocalised π system.
- Not reading the negative: Rushing through multiple-choice questions often leads students to read "has delocalised electrons" instead of "no delocalised electrons", prompting them to incorrectly choose A, B, or D.
Topics
Physical Chemistry · Organic Chemistry · 3.1.3 Bonding · 3.3.4 Alkenes · 3.3.10 Aromatic Chemistry
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.