AQA A-Level Chemistry Paper 1, 2023: Question 8
5 marks · Medium difficulty · State/Explain/Numerical
Write electrode half-equations, calculate an electrode potential, and explain operational features and advantages of a methanol-oxygen fuel cell.
Practise this questionQuestion
Question text
08 This question is about fuel cells.
In a methanol–oxygen fuel cell, the overall reaction is
CH3OH(l) + 1 O2(g) CO2(g) + 2H2O(l) EMF = +1.20 V
08.1 At the positive electrode, oxygen reacts with hydrogen ions to form water.
Give a half-equation for this reaction.
[1 mark]
08.2 At the negative electrode, methanol reacts with water to produce
carbon dioxide and hydrogen ions.
Give a half-equation for this reaction.
[1 mark]
08.3 The standard electrode potential for the CO2 / CH3OH electrode is +0.03 V
Calculate the standard electrode potential for the O2 / H2O electrode.
[1 mark]
08.4 State why a fuel cell does not need to be electrically recharged.
[1 mark]
08.5 Suggest one advantage of using methanol, rather than hydrogen, in a fuel cell for use
in cars.
[1 mark]
Mark scheme
Show the mark scheme
Question Answers Additional comments/Guidelines Mark
O + 4 H+ + 4 e- 2 H O 1
08.1
(AO1)
CH OH + H O CO + 6 H+ + 6 e- 1
32 2
08.2
(AO2)
1.23 (V) 1
08.3
(AO2)
Allow fuel continuously supplied
Reactants supplied continuously 1
08.4 Allow continuous supply of chemicals (AO1)
Methanol (is liquid so) can be stored easily or transported easily More energy can be produced from 1 cm3 of 1
methanol (liquid) than from 1 cm3 of hydrogen
(AO2)
(gas)
08.5
Ignore references to safety and cost
Do not accept no greenhouse gas emissions
How to answer it
AQA A-Level Chemistry: Methanol-Oxygen Fuel Cells
This question assesses your ability to apply core electrochemical principles to alternative fuel cells:
- Writing and balancing redox half-equations in acidic media involving organic molecules and oxygen.
- Calculating standard cell potentials using the relationship between cell EMF and individual electrode potentials: EMF = E°(positive electrode) − E°(negative electrode).
- Understanding fundamental commercial and operational features of fuel cells compared to secondary (rechargeable) batteries.
- Evaluating the physical and practical trade-offs between liquid fuels (methanol) and gaseous fuels (hydrogen) in transport applications.
Positive Electrode Half-Equation
Oxygen reduction in an acidic fuel cell
✅ Correct Answer
State symbols are not strictly required unless requested, but equations must be fully balanced for atoms and charges.
💡 Key Knowledge
- The positive electrode is the cathode in an electrochemical cell, where reduction (gain of electrons) takes place.
- In acidic fuel cells, oxygen gas is reduced by reacting with hydrogen ions (H⁺) to produce water.
- Oxygen's oxidation state decreases from 0 in O₂ to -2 in H₂O.
🧠 Exam Technique
The question explicitly tells you the reactants and products: "oxygen reacts with hydrogen ions to form water". Start with O₂ + H⁺ → H₂O , balance oxygen atoms first by doubling H₂O, then balance H with 4H⁺, and finally add 4e⁻ to balance charges.
❌ Common Errors
- Writing the alkaline half-equation ( O₂ + 2H₂O + 4e⁻ → 4OH⁻ ) instead of the acidic one, ignoring the prompt that states H⁺ ions are involved.
- Incorrect charge balancing, such as writing 2e⁻ instead of 4e⁻ .
Negative Electrode Half-Equation
Methanol oxidation in an acidic fuel cell
✅ Correct Answer
💡 Key Knowledge
- The negative electrode is the anode, where oxidation (loss of electrons) occurs.
- Methanol is oxidised to carbon dioxide. The carbon changes oxidation state from -2 in CH₃OH to +4 in CO₂ (a loss of 6 electrons).
- Water provides the extra oxygen atom needed to convert the alcohol group into carbon dioxide.
🧠 Exam Technique
- Write reactants and products given in the prompt: CH₃OH + H₂O → CO₂ + H⁺ .
- Check C and O atoms: 1 C and 2 O on both sides (already balanced).
- Count hydrogens: Left has 4 + 2 = 6 H. Therefore, produce 6H⁺ on the right.
- Balance charge: Left has 0 charge, right has +6, so add 6e⁻ to the right.
❌ Common Errors
- Forgetting to include H₂O as a reactant, making it impossible to balance the oxygen atoms.
- Writing electrons on the wrong side (reduction instead of oxidation).
- Miscounting hydrogen atoms in methanol ( CH₃OH has 4 H atoms, not 3).
Standard Electrode Potential Calculation
Determining E° for the positive oxygen electrode
📐 Step-by-Step Calculation
- Identify given data:
Overall cell EMF = +1.20 V
E°(negative electrode, CO₂ / CH₃OH) = +0.03 V - State the electrochemical relationship:
EMF = E°(positive electrode) − E°(negative electrode) - Rearrange to solve for E°(positive electrode):
E°(O₂ / H₂O) = EMF + E°(CO₂ / CH₃OH) - Substitute numerical values:
E°(O₂ / H₂O) = 1.20 + 0.03 = +1.23 V
✅ Correct Answer
Always include a positive sign or double check that the value aligns with standard electrode potential tables (the standard potential for oxygen reduction in acid is known to be +1.23 V).
❌ Calculation Traps
- Subtraction error: Subtracting incorrectly: 1.20 − 0.03 = 1.17 V . Remember that the positive electrode must have the more positive potential!
- Sign confusion: Assigning a negative sign ( -1.23 V ) — spontaneous cells must result in a positive overall EMF.
🧠 Sanity Check
Top students recognise standard data from memory: the O₂ / H₂O reduction potential in acidic media is a textbook constant ( +1.23 V ). Knowing this helps immediately verify your arithmetic.
Operational Mechanism of Fuel Cells
Why fuel cells do not require electrical recharging
✅ Correct Answer
Any one of the following:
- Reactants are supplied continuously.
- Fuel is continuously supplied.
- Continuous supply of chemicals/reactants.
💡 Key Knowledge
- In conventional secondary (rechargeable) batteries, reactants are stored inside a closed system and are depleted until an external electrical current reverses the chemical reaction.
- In a fuel cell, the system is open: fuel and oxidant flow in continuously from an external reservoir, generating current as long as reactants are fed in.
❌ Common Errors
- Vague statements like "it produces electricity all the time" or "the reaction is spontaneous" without referencing the continuous supply of fuel/reactants.
- Saying "it runs on fuel, not electricity" without explaining that fuel is added continuously.
🧠 Exam Technique
The word "continuously" or "constant supply" is the essential examiner trigger word for AQA fuel cell questions.
Methanol vs Hydrogen in Vehicles
Practical comparison of fuels for transport
✅ Correct Answer
Any one valid point:
- Methanol is a liquid, so it is easier to store / transport (than gaseous hydrogen).
- More energy can be produced from 1 cm³ of methanol (liquid) than from 1 cm³ of hydrogen (gas) / higher energy density per unit volume.
- Existing petrol station infrastructure can be used.
💡 Key Knowledge
- Hydrogen is a low-density gas requiring either high-pressure tanks (hundreds of atmospheres) or cryogenic liquification (-253 °C).
- Methanol ( CH₃OH ) is a liquid at ambient temperature and pressure, dramatically reducing storage volume and engineering complexity in vehicles.
❌ Disallowed Answers (Mark Scheme Restrictions)
- DO NOT write "Methanol produces no emissions / no greenhouse gases" — Methanol combustion/oxidation produces CO₂!
- IGNORE generic references to "safety" or "cost" without precise explanation (hydrogen is explosive, but methanol is toxic and flammable too).
🧠 Top-Grade Tip
Always relate physical state to practical utility: state that methanol is a liquid, which makes storage and transport straightforward compared to high-pressure gas cylinders.
Topics
Physical Chemistry · 3.1.7 Oxidation, Reduction and Redox Equations · 3.1.11 Electrode Potentials
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 1, 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.