AQA A-Level Chemistry Paper 1, 2023: Question 8

5 marks · Medium difficulty · State/Explain/Numerical

Write electrode half-equations, calculate an electrode potential, and explain operational features and advantages of a methanol-oxygen fuel cell.

Practise this question

Question

Question 8 about fuel cells. The overall reaction for a methanol–oxygen fuel cell is given as CH3OH(l) + 1 1/2 O2(g) -> CO2(g) + 2 H2O(l) with an EMF of +1.20 V. Sub-question 8.1 asks for a half-equation at the positive electrode where oxygen reacts with hydrogen ions to form water (1 mark). Sub-question 8.2 asks for a half-equation at the negative electrode where methanol reacts with water to produce carbon dioxide and hydrogen ions (1 mark). Sub-question 8.3 asks to calculate the standard electrode potential for the O2 / H2O electrode given that the standard electrode potential for the CO2 / CH3OH electrode is +0.03 V (1 mark). Sub-question 8.4 asks why a fuel cell does not need to be electrically recharged (1 mark). Sub-question 8.5 asks to suggest one advantage of using methanol rather than hydrogen in a fuel cell for cars (1 mark).
Question text

08 This question is about fuel cells.

In a methanol–oxygen fuel cell, the overall reaction is

CH3OH(l) + 1 O2(g) CO2(g) + 2H2O(l) EMF = +1.20 V

08.1 At the positive electrode, oxygen reacts with hydrogen ions to form water.

Give a half-equation for this reaction.

[1 mark]

08.2 At the negative electrode, methanol reacts with water to produce

carbon dioxide and hydrogen ions.

Give a half-equation for this reaction.

[1 mark]

08.3 The standard electrode potential for the CO2 / CH3OH electrode is +0.03 V

Calculate the standard electrode potential for the O2 / H2O electrode.

[1 mark]

08.4 State why a fuel cell does not need to be electrically recharged.

[1 mark]

08.5 Suggest one advantage of using methanol, rather than hydrogen, in a fuel cell for use

in cars.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for question 08. 08.1: O2 + 4H+ + 4e- -> 2H2O (1 mark, AO1). 08.2: CH3OH + H2O -> CO2 + 6H+ + 6e- (1 mark, AO2). 08.3: 1.23 (V) (1 mark, AO2). 08.4: Reactants supplied continuously; allow fuel continuously supplied or continuous supply of chemicals (1 mark, AO1). 08.5: Methanol (is liquid so) can be stored easily or transported easily; allow more energy can be produced from 1 cm3 of methanol (liquid) than from 1 cm3 of hydrogen (gas); ignore references to safety and cost; do not accept no greenhouse gas emissions (1 mark, AO2).

Question Answers Additional comments/Guidelines Mark

O + 4 H+ + 4 e- 2 H O 1

08.1

(AO1)

CH OH + H O CO + 6 H+ + 6 e- 1

32 2

08.2

(AO2)

1.23 (V) 1

08.3

(AO2)

Allow fuel continuously supplied

Reactants supplied continuously 1

08.4 Allow continuous supply of chemicals (AO1)

Methanol (is liquid so) can be stored easily or transported easily More energy can be produced from 1 cm3 of 1

methanol (liquid) than from 1 cm3 of hydrogen

(AO2)

(gas)

08.5

Ignore references to safety and cost

Do not accept no greenhouse gas emissions

How to answer it

AQA A-Level Chemistry: Methanol-Oxygen Fuel Cells

WHAT THIS QUESTION TESTS

This question assesses your ability to apply core electrochemical principles to alternative fuel cells:

  • Writing and balancing redox half-equations in acidic media involving organic molecules and oxygen.
  • Calculating standard cell potentials using the relationship between cell EMF and individual electrode potentials: EMF = E°(positive electrode) − E°(negative electrode).
  • Understanding fundamental commercial and operational features of fuel cells compared to secondary (rechargeable) batteries.
  • Evaluating the physical and practical trade-offs between liquid fuels (methanol) and gaseous fuels (hydrogen) in transport applications.
QUESTION 08.1 • 1 MARK

Positive Electrode Half-Equation

Oxygen reduction in an acidic fuel cell

✅ Correct Answer

O₂ + 4H⁺ + 4e⁻ → 2H₂O

State symbols are not strictly required unless requested, but equations must be fully balanced for atoms and charges.

💡 Key Knowledge

  • The positive electrode is the cathode in an electrochemical cell, where reduction (gain of electrons) takes place.
  • In acidic fuel cells, oxygen gas is reduced by reacting with hydrogen ions (H⁺) to produce water.
  • Oxygen's oxidation state decreases from 0 in O₂ to -2 in H₂O.

🧠 Exam Technique

The question explicitly tells you the reactants and products: "oxygen reacts with hydrogen ions to form water". Start with O₂ + H⁺ → H₂O , balance oxygen atoms first by doubling H₂O, then balance H with 4H⁺, and finally add 4e⁻ to balance charges.

❌ Common Errors

  • Writing the alkaline half-equation ( O₂ + 2H₂O + 4e⁻ → 4OH⁻ ) instead of the acidic one, ignoring the prompt that states H⁺ ions are involved.
  • Incorrect charge balancing, such as writing 2e⁻ instead of 4e⁻ .
Mark scheme: 1 mark for O₂ + 4H⁺ + 4e⁻ → 2H₂O (AO1).
QUESTION 08.2 • 1 MARK

Negative Electrode Half-Equation

Methanol oxidation in an acidic fuel cell

✅ Correct Answer

CH₃OH + H₂O → CO₂ + 6H⁺ + 6e⁻

💡 Key Knowledge

  • The negative electrode is the anode, where oxidation (loss of electrons) occurs.
  • Methanol is oxidised to carbon dioxide. The carbon changes oxidation state from -2 in CH₃OH to +4 in CO₂ (a loss of 6 electrons).
  • Water provides the extra oxygen atom needed to convert the alcohol group into carbon dioxide.

🧠 Exam Technique

  1. Write reactants and products given in the prompt: CH₃OH + H₂O → CO₂ + H⁺ .
  2. Check C and O atoms: 1 C and 2 O on both sides (already balanced).
  3. Count hydrogens: Left has 4 + 2 = 6 H. Therefore, produce 6H⁺ on the right.
  4. Balance charge: Left has 0 charge, right has +6, so add 6e⁻ to the right.

❌ Common Errors

  • Forgetting to include H₂O as a reactant, making it impossible to balance the oxygen atoms.
  • Writing electrons on the wrong side (reduction instead of oxidation).
  • Miscounting hydrogen atoms in methanol ( CH₃OH has 4 H atoms, not 3).
Mark scheme: 1 mark for CH₃OH + H₂O → CO₂ + 6H⁺ + 6e⁻ (AO2).
QUESTION 08.3 • 1 MARK

Standard Electrode Potential Calculation

Determining E° for the positive oxygen electrode

📐 Step-by-Step Calculation

  1. Identify given data:
    Overall cell EMF = +1.20 V
    E°(negative electrode, CO₂ / CH₃OH) = +0.03 V
  2. State the electrochemical relationship:
    EMF = E°(positive electrode) − E°(negative electrode)
  3. Rearrange to solve for E°(positive electrode):
    E°(O₂ / H₂O) = EMF + E°(CO₂ / CH₃OH)
  4. Substitute numerical values:
    E°(O₂ / H₂O) = 1.20 + 0.03 = +1.23 V

✅ Correct Answer

+1.23 V (or 1.23 V)

Always include a positive sign or double check that the value aligns with standard electrode potential tables (the standard potential for oxygen reduction in acid is known to be +1.23 V).

❌ Calculation Traps

  • Subtraction error: Subtracting incorrectly: 1.20 − 0.03 = 1.17 V . Remember that the positive electrode must have the more positive potential!
  • Sign confusion: Assigning a negative sign ( -1.23 V ) — spontaneous cells must result in a positive overall EMF.

🧠 Sanity Check

Top students recognise standard data from memory: the O₂ / H₂O reduction potential in acidic media is a textbook constant ( +1.23 V ). Knowing this helps immediately verify your arithmetic.

Mark scheme: 1 mark for 1.23 (V) (AO2).
QUESTION 08.4 • 1 MARK

Operational Mechanism of Fuel Cells

Why fuel cells do not require electrical recharging

✅ Correct Answer

Any one of the following:

  • Reactants are supplied continuously.
  • Fuel is continuously supplied.
  • Continuous supply of chemicals/reactants.

💡 Key Knowledge

  • In conventional secondary (rechargeable) batteries, reactants are stored inside a closed system and are depleted until an external electrical current reverses the chemical reaction.
  • In a fuel cell, the system is open: fuel and oxidant flow in continuously from an external reservoir, generating current as long as reactants are fed in.

❌ Common Errors

  • Vague statements like "it produces electricity all the time" or "the reaction is spontaneous" without referencing the continuous supply of fuel/reactants.
  • Saying "it runs on fuel, not electricity" without explaining that fuel is added continuously.

🧠 Exam Technique

The word "continuously" or "constant supply" is the essential examiner trigger word for AQA fuel cell questions.

Mark scheme: 1 mark for stating that reactants / fuel / chemicals are supplied continuously (AO1).
QUESTION 08.5 • 1 MARK

Methanol vs Hydrogen in Vehicles

Practical comparison of fuels for transport

✅ Correct Answer

Any one valid point:

  • Methanol is a liquid, so it is easier to store / transport (than gaseous hydrogen).
  • More energy can be produced from 1 cm³ of methanol (liquid) than from 1 cm³ of hydrogen (gas) / higher energy density per unit volume.
  • Existing petrol station infrastructure can be used.

💡 Key Knowledge

  • Hydrogen is a low-density gas requiring either high-pressure tanks (hundreds of atmospheres) or cryogenic liquification (-253 °C).
  • Methanol ( CH₃OH ) is a liquid at ambient temperature and pressure, dramatically reducing storage volume and engineering complexity in vehicles.

❌ Disallowed Answers (Mark Scheme Restrictions)

  • DO NOT write "Methanol produces no emissions / no greenhouse gases" — Methanol combustion/oxidation produces CO₂!
  • IGNORE generic references to "safety" or "cost" without precise explanation (hydrogen is explosive, but methanol is toxic and flammable too).

🧠 Top-Grade Tip

Always relate physical state to practical utility: state that methanol is a liquid, which makes storage and transport straightforward compared to high-pressure gas cylinders.

Mark scheme: 1 mark for ease of storage/transport due to liquid state OR higher volumetric energy density. Ignore cost and safety. Reject "no greenhouse emissions" (AO2).

Topics

Physical Chemistry · 3.1.7 Oxidation, Reduction and Redox Equations · 3.1.11 Electrode Potentials

Question and mark scheme from the AQA A-Level Chemistry examination, Paper 1, 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.