AQA A-Level Chemistry Paper 3, 2023: Question 24
1 mark · Easy difficulty · Multiple Choice
Decolourisation of Potassium Manganate(VII) This question tests the ability to identify a compound that can reduce acidified potassium manganate(VII), causing it to decolourise. It focuses on recognising reducing agents among the given compounds.
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Question text
24 Which compound can decolourise acidified potassium manganate(VII) solution?
[1 mark]
A AgNO3
B CuSO4
C FeSO4
D Fe2(SO4)3
Mark scheme
Show the mark scheme
24 C 1 (AO1) FeSO4
How to answer it
Understanding Decolourisation of Acidified Potassium Manganate(VII)
Question
Which compound can decolourise acidified potassium manganate(VII) solution?
- A: AgNO3
- B: CuSO4
- C: FeSO4
- D: Fe2(SO4)3
Correct Answer: C
The correct answer is FeSO4 . Ferrous sulfate (FeSO4) contains Fe2+, which can act as a reducing agent, oxidising to Fe3+ and reducing MnO4- to Mn2+, thereby decolourising the solution.
Explanation
- Acidified potassium manganate(VII) (MnO4-) is a strong oxidising agent. It is reduced to Mn2+, which is colourless.
- Fe2+ in FeSO4 acts as the reducing agent, being oxidised to Fe3+.
Balanced ionic equation:
5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O
Why Other Options Are Incorrect
- A: AgNO3 – Silver nitrate is not a reducing agent and cannot reduce MnO4-.
- B: CuSO4 – Copper(II) sulfate contains Cu2+, which is not a reducing agent.
- D: Fe2(SO4)3 – This contains Fe3+, which is already in an oxidised state and cannot act as a reducing agent.
Teacher Tip
Final Answer
The correct choice is:
C: FeSO4
Topics
Inorganic Chemistry · 3.2.5 Transition Metals
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.