AQA A-Level Chemistry Paper 3, 2024: Question 19
1 mark · Easy difficulty · Multiple Choice
Identify which statement about the Period 3 elements (sodium to chlorine) is correct.
Practise this questionQuestion
Question text
19 Consider the Period 3 elements from sodium to chlorine.
Which statement is correct?
[1 mark]
A Sodium has the smallest atomic radius.
B Aluminium has the highest melting point.
C Sulfur is the most electronegative.
D Chlorine has the highest first ionisation energy.
Mark scheme
Show the mark scheme
19 D 1 (AO2) Chlorine has the highest first ionisation energy.
How to answer it
Period 3 Trends: Identify the Correct Statement
- Applying Period 3 trends (Na → Cl): atomic radius, melting point, electronegativity, first ionisation energy.
- Recognising exceptions and common “trap” options in multiple choice.
- AO2 skill: selecting the correct statement using chemical reasoning, not memory of one trend alone.
Part (a) — Multiple choice (1 mark)
✅ Correct answer (what to write/tick)
D — Chlorine has the highest first ionisation energy (among Na to Cl).
Marks: 1/1 for selecting D. No working is required, but reasoning helps avoid traps.
💡 Key knowledge (why D is correct)
- First ionisation energy generally increases across a period because nuclear charge increases while electrons are added to the same shell, so shielding is similar and attraction increases.
- So, moving Na → Cl, the outer electron is held more strongly, making it harder to remove.
- Within Na to Cl, the highest first ionisation energy is at the right-hand end: Cl.
🧠 Exam technique (how to eliminate options fast)
- Atomic radius trend: decreases across the period → smallest radius is near Cl (not Na). So A is wrong.
- Melting point trend: rises Na → Al (stronger metallic bonding), then peaks at Si (giant covalent), then drops for P, S, Cl (simple molecular). So B is wrong.
- Electronegativity trend: increases across the period → Cl is most electronegative (not S). So C is wrong.
- Only statement left consistent with the overall trend is D.
This is exactly what “AO2” means here: using trends to decide, not recalling a single isolated fact.
❌ Common errors (examiner-style traps)
- Choosing B (Al highest melting point) because “metals have high melting points.” The peak in Period 3 is silicon due to a giant covalent structure.
- Choosing C (S most electronegative) because students confuse “more non-metallic” with a specific element. Across Period 3, electronegativity increases to Cl.
- Choosing A by mixing up trends: atomic radius decreases across the period; sodium is one of the largest.
- Overthinking ionisation energy exceptions (e.g., Al vs Mg, S vs P). These exceptions exist, but they don’t stop Cl being the highest among Na to Cl.
💡 Quick trend reminders (Na → Cl)
Atomic radius
Decreases across the period (greater nuclear charge, similar shielding).
Na (largest) → … → Cl (smallest among Na–Cl)
Melting point
Increases Na → Al (metallic bonding), then highest at Si (giant covalent), then decreases for P, S, Cl (simple molecular).
Electronegativity
Increases across the period; Cl is highest (among Na–Cl).
First ionisation energy
Generally increases across a period; small dips at Al and S, but overall highest at the right-hand side.
Highest (Na–Cl): Cl
🧠 What distinguished top responses
- They used two linked ideas: increasing nuclear charge + similar shielding → stronger attraction → higher first ionisation energy.
- They recognised the melting point peak is Si (structure/bonding argument), avoiding B.
- They knew “most electronegative” in Period 3 (Na–Cl) is Cl, avoiding C.
Topics
Inorganic Chemistry · 3.2.1 Periodicity
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.