AQA A-Level Chemistry AS Paper 1, June 2025: Question 11
1 mark · Easy difficulty · Multiple Choice
Identify the diagram showing the correct arrangement and relative sizes of ions in solid sodium chloride.
Practise this questionQuestion
Question text
11 Which diagram best shows the arrangement and the relative sizes of the ions in
solid sodium chloride?
[1 mark]
A
B
C
D
Mark scheme
Show the mark scheme
11 A 1 (AO2)
How to answer it
Structure and Ionic Radii in Solid Sodium Chloride
What this question tests
This question evaluates your understanding of two core physical chemistry principles:
- Periodic trends in ionic radii: Comparing the physical size of cations (Na⁺) and anions (Cl⁻) based on electron configuration and shielding.
- Giant ionic lattice arrangement: How oppositely charged ions alternate in regular 3D crystal structures to maximise electrostatic attractions and minimise repulsions.
Question 11
Giant Ionic Crystal Lattice & Relative Ion Sizes
AQA A-Level Chemistry • Paper 1 Multiple Choice • 1 Mark (AO2)
✅ Correct Answer: A
Diagram A is the correct representation because:
- Correct relative size: The chloride ion (Cl⁻) is noticeably larger than the sodium ion (Na⁺).
- Correct alternating arrangement: Each positive ion is surrounded by and adjacent to negative ions, and vice-versa, avoiding like-charge repulsions.
📋 Mark Scheme Breakdown
Key: A
Mark allocation: 1 mark (AO2 - application of knowledge to models)
Examiner note: Requires dual deduction: relative ion radius (Cl⁻ > Na⁺) AND alternating charge packing.
Mark allocation: 1 mark (AO2 - application of knowledge to models)
Examiner note: Requires dual deduction: relative ion radius (Cl⁻ > Na⁺) AND alternating charge packing.
💡 Key Knowledge: Why is Cl⁻ larger than Na⁺?
- Electronic configurations:
- Na atom is 1s² 2s² 2p⁶ 3s¹ → loses 1 electron to form Na⁺ ( 1s² 2s² 2p⁶ ). It has only 2 occupied quantum shells.
- Cl atom is 1s² 2s² 2p⁶ 3s² 3p⁵ → gains 1 electron to form Cl⁻ ( 1s² 2s² 2p⁶ 3s² 3p⁶ ). It retains 3 occupied quantum shells.
- Shells & Shielding: Because Cl⁻ has electrons in the third quantum energy level (n = 3), its outer electrons experience greater shielding from inner shells and are further from the nucleus, giving Cl⁻ a significantly larger ionic radius (~181 pm) compared to Na⁺ (~102 pm).
- Lattice Geometry: In solid NaCl (a face-centred cubic giant lattice), each Na⁺ is octahedrally coordinated by 6 Cl⁻ ions, and each Cl⁻ is surrounded by 6 Na⁺ ions (coordination number 6:6). In any 2D plane through the lattice, positive and negative charges must strictly alternate.
🧠 Exam Technique: Systematic Elimination
For multiple choice questions featuring geometric representations:
- Filter 1: Eliminate wrong sizes
Cl⁻ has 3 shells; Na⁺ has 2 shells. Therefore, the negative sphere must be larger than the positive sphere.
→ Eliminates B (where positive is larger) and C & D (where both spheres are identical in size). - Filter 2: Verify lattice coordination
Adjacent touching ions along the lattice axes must have opposite charges to ensure strong net electrostatic attraction.
→ Confirms A and additionally rules out C (which incorrectly places like charges adjacent to one another).
❌ Common Pitfalls & Misconceptions
- Confusing atomic radius with ionic radius: Students remember that atomic radius decreases across a period, but forget that Na⁺ has lost its entire 3s outer shell, leaving it with only 2 shells compared to Cl⁻'s 3 shells.
- Assuming ions are equal in size (Options C & D): Simple ball-and-stick diagrams in textbooks often use uniform sphere sizes for clarity, misleading students into thinking all monoatomic ions have identical radii.
- Overlooking charge alignment: Option C arranges identical charges side-by-side. In an ionic crystal, like charges adjacent to one another would cause immediate lattice instability due to mutual electrostatic repulsion.
Topics
Physical Chemistry · 3.1.3 Bonding
Question and mark scheme from the AQA A-Level Chemistry examination, AS Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.