AQA A-Level Chemistry AS Paper 1, June 2025: Question 19

1 mark · Easy difficulty · Multiple Choice

Identify which of the given molecules (BF3, CO2, CCl4, or SCl2) is polar.

Practise this question

Question

Multiple-choice question 19 asks: 'Which of these molecules is polar?' with options A: BF3, B: CO2, C: CCl4, and D: SCl2.
Question text

19 Which of these molecules is polar?

[1 mark]

A BF3

B CO2

C CCl4

D SCl2

Mark scheme

Show the mark scheme Mark scheme table row showing question 19 with answer D, 1 mark (AO2), and the molecule SCl2.

19 D 1 (AO2) SCl2

How to answer it

AQA A-Level Chemistry • Physical Chemistry

Molecular Polarity & VSEPR Theory

What this question tests

This question assesses your ability to apply VSEPR theory (valence shell electron pair repulsion) to determine 3D molecular shapes, evaluate differences in electronegativity to identify polar bonds, and deduce whether overall molecular symmetry causes individual bond dipoles to cancel out or produce a permanent dipole moment.

Question 19 Walkthrough

Identifying the Polar Molecule from Multiple Options [1 Mark]

✅ Correct Answer

D  (SCl₂)

Mark Scheme Breakdown:
• 1 mark (AO2): Selecting option D exclusively.

🧠 Exam Technique: 2-Step Polarity Rule

  1. Check for polar bonds: Does the molecule contain bonds between atoms of different electronegativities? (All options A–D have polar bonds).
  2. Check molecular symmetry: Do the individual dipoles cancel out?
    • Symmetrical shape → Dipoles cancel → Non-polar
    • Asymmetrical shape → Dipoles do not cancel → Polar

Step-by-Step Option Analysis

Deducing Electron Pairs, Shapes, and Dipole Moments

📐 Molecular Structure Breakdown

Molecule Bonding / Lone Pairs 3D Shape Symmetry & Net Dipole
A: BF₃ 3 bonding pairs, 0 lone pairs Trigonal planar (120°) Symmetrical — the three equal B–F dipoles act in opposing directions and cancel out completely. Non-polar.
B: CO₂ 2 double bond regions, 0 lone pairs Linear (180°) Symmetrical — the two equal C=O dipoles pull in directly opposite directions and cancel out. Non-polar.
C: CCl₄ 4 bonding pairs, 0 lone pairs Tetrahedral (109.5°) Symmetrical — the four equal C–Cl dipoles cancel out in 3D space. Non-polar.
D: SCl₂ 2 bonding pairs, 2 lone pairs Bent / V-shaped (~104.5°) Asymmetrical — sulfur has two lone pairs which distort the geometry. The dipoles do not cancel, giving a permanent net dipole.

💡 Key Knowledge: Why SCl₂ is Non-Linear

  • Sulfur is in Group 16 (6 valence electrons). Each Cl atom forms 1 single covalent bond, contributing 1 electron each → total 8 electrons around sulfur.
  • 8 electrons = 4 electron pairs (2 bonding pairs + 2 lone pairs).
  • Lone pair–lone pair repulsion is greater than lone pair–bonding pair repulsion, which is greater than bonding pair–bonding pair repulsion.
  • This pushes the two S–Cl bonds down into a bent or non-linear shape (isoelectronic to H₂O). Chlorine is more electronegative than sulfur, so the bond dipoles reinforce downwards rather than canceling.

❌ Common Student Errors

  • Assuming 2-coordinate atoms are always linear: Students often mistakenly sketch SCl₂ as Cl—S—Cl in a straight line (confusing it with CO₂ or BeCl₂) and incorrectly conclude the dipoles cancel. Always count lone pairs on the central atom!
  • Confusing polar bonds with polar molecules: All four molecules possess polar covalent bonds. Polar bonds do not automatically make the overall molecule polar.
  • Overlooking lone pair electron repulsion: Forgetting that non-bonding electron pairs take up more space and fundamentally break molecular symmetry.

Topics

Physical Chemistry · 3.1.3 Bonding

Question and mark scheme from the AQA A-Level Chemistry examination, AS Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.