AQA A-Level Mathematics Paper 2, June 2025: Question 1
1 mark · Easy difficulty · Short Answer
Identify the single transformation that maps the curve y = ln x onto the curve y = 2 ln x.
Practise this questionQuestion
Question text
1 Describe the single transformation which maps the curve with the equation
y = ln x
onto the curve with the equation
y = 2ln x
Tick ( ) one box.
[1 mark]
Stretch, scale factor 2, parallel to the y‑axis
Stretch, scale factor , parallel to the x‑axis
Translation
Translation
Mark scheme
Show the mark scheme
Q Marking instructions AO Marks Typical solution
1 Ticks the first 2.2a R1 Stretch, scale factor 2, parallel to the
y-axis
Question 1 Total 1
How to answer it
Single Transformation of Logarithmic Functions
This question assesses your understanding of function transformations (specification topic: Coordinate geometry and functions). Specifically, it checks whether you can:
- Distinguish between vertical transformations of the form y = a f(x) and horizontal transformations of the form y = f(ax) .
- Correctly state the type of transformation (stretch vs translation), the scale factor, and the direction/axis.
Identifying the Transformation from y = ln x to y = 2ln x
AQA A-Level Mathematics • Paper 1 • Multiple Choice
✅ Correct Answer
First Box: Stretch, scale factor 2, parallel to the y-axis
💡 Key Knowledge
Let f(x) = ln x . Then y = 2ln x is of the form y = a f(x) where a = 2 .
| Form | Transformation |
|---|---|
| y = a f(x) | Vertical stretch, scale factor a , parallel to the y-axis |
| y = f(ax) | Horizontal stretch, scale factor 1/a , parallel to the x-axis |
| y = f(x) + c | Translation by vector [0, c] |
| y = f(x - c) | Translation by vector [c, 0] |
📐 Step-by-Step Mathematical Analysis
- Identify the base function:
Let f(x) = ln x . - Express the new function in terms of f(x):
The target curve is y = 2 ln x = 2 × f(x) . - Analyze the effect on coordinates:
For any point (x, y) on the original curve, the corresponding point on the new curve is (x, 2y) . - Deduce the transformation:
Since the x-coordinate is unchanged and the y-coordinate is multiplied by 2, this represents an expansion away from the x-axis, which is described as a stretch of scale factor 2 parallel to the y-axis (or in the vertical direction).
🧠 Exam Technique & Examiner Insight
- Quick Rule of Thumb: Operations outside the function bracket affect the y-direction directly as written (e.g., ×2 multiplies y by 2). Operations inside the function affect the x-direction inversely.
- Only tick ONE box: If you change your mind, cross out the incorrect tick completely and clearly place a new tick in the correct box.
- Full Description Requirements: In non-multiple-choice questions, examiners require all three elements:
- The word Stretch
- The scale factor (e.g. 2)
- The direction (e.g. parallel to the y-axis or in the y-direction)
❌ Common Misconceptions & Distractor Breakdown
- Confusing with "Stretch, scale factor 1/2, parallel to the x-axis":
A common trap arises from logarithm laws: 2 ln x = ln(x²) , NOT ln(2x) . Even if a student thought about horizontal stretching, f(2x) = ln(2x) gives a scale factor of 1/2 parallel to the x-axis, but that equals ln 2 + ln x , which is a vertical translation, not 2 ln x ! - Confusing multiplication with translation vectors [2, 0] or [0, 2]:
Translations occur when constants are added, e.g.:
• y = ln(x − 2) is a translation by [2, 0] .
• y = ln x + 2 is a translation by [0, 2] .
Multiplication by 2 affects scale (stretch), not a rigid shift (translation).
Topics
Pure Mathematics · B: Algebra and functions · F: Exponentials and logarithms
Question and mark scheme from the AQA A-Level Mathematics examination, Paper 2, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.