AQA A-Level Mathematics Paper 3, June 2025: Question 6
4 marks · Easy difficulty · Multi-step Problem
Find the coefficients in a binomial expansion of (2 - 3x)^5 and use it to calculate an approximation for 1.94^5.
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How to answer it
Binomial Expansion & Decimal Approximation
This question assesses your mastery of pure algebra skills in Year 1 / AS Mathematics:
- Expanding a binomial expression of the form (a + bx)ⁿ where n is a positive integer.
- Correctly dealing with negative signs and bracketed powers such as (-3x)².
- Using the command word "Hence" to evaluate a numerical power approximation by equating base terms.
- Maintaining accuracy to a specified number of decimal places without premature rounding.
Finding Coefficients p and q
Expansion of (2 - 3x)⁵ in ascending powers of x (2 Marks)
💡 Key Knowledge
The general binomial formula for a positive integer n is:
(a + b)ⁿ = aⁿ + ⁿC₁ aⁿ⁻¹b + ⁿC₂ aⁿ⁻²b² + ...
Here, identify the components carefully:
- a = 2
- b = -3x (ensure the negative sign is included!)
- n = 5
📐 Step-by-Step Calculation
1 Term in x (find p):
⁵C₁ × (2)⁴ × (-3x)¹
= 5 × 16 × (-3x) = -240x &implies; p = -240
2 Term in x² (find q):
⁵C₂ × (2)³ × (-3x)²
= 10 × 8 × (9x²) = 720x² &implies; q = 720
3 Spot Check with Given Term:
⁵C₃ × (2)² × (-3x)³ = 10 × 4 × (-27x³) = -1080x³. This matches the question, confirming the signs and powers are set up correctly.
✅ Correct Answers & Mark Allocation
p = -240
q = 720
[A1] Accuracy mark for obtaining both correct values: p = -240 and q = 720.
❌ Common Errors to Avoid
- Bracket Neglect: Writing -3x² instead of (-3x)² = +9x², resulting in q = -240 or -720.
- Lost Negative Sign: Forgetting the minus sign on the x term, giving p = +240.
- Leaving the Variable: Writing p = -240x and q = 720x². While examiners condoned this here, coefficients are constants, so strictly omit x.
Approximating 1.94⁵
Substitution and Decimal Precision (2 Marks)
🧠 Exam Technique: "Hence"
- The word "Hence" means you must use your expansion from part (a).
- Simply typing 1.94⁵ into your calculator gives 27.4793574... but earns 0 marks if the substitution is not shown!
- Equate bases to find x:
2 - 3x = 1.94
3x = 2 - 1.94 = 0.06
x = 0.02
📐 Step-by-Step Calculation
1 Substitute x = 0.02 into the expansion:
32 + px + qx² - 1080x³
= 32 - 240(0.02) + 720(0.02)² - 1080(0.02)³
2 Evaluate each term separately:
- Constant term: 32
- Linear term: -240(0.02) = -4.8
- Quadratic term: 720(0.0004) = +0.288
- Cubic term: -1080(0.000008) = -0.00864
3 Sum terms:
32 - 4.8 + 0.288 - 0.00864 = 27.47936
✅ Correct Answer
1.94⁵ ≈ 27.47936
[A1] Correct Answer Only (CAO): 27.47936 (must be stated to 5 d.p.).
💡 Examiner Insights & Tips
- Exact vs Rounded: The evaluated sum terminates naturally at 5 decimal places. Do not add trailing zeroes unless required, and do not round prematurely!
- ISW (Ignore Subsequent Working): Once the correct value of 27.47936 is seen, unnecessary further rounding won't penalise you, but always write the exact 5 d.p. value first.
Topics
Pure Mathematics · D: Sequences and series
Question and mark scheme from the AQA A-Level Mathematics examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.