AQA A-Level Physics Paper 1, November 2020: Question 25

1 mark · Medium difficulty · Multiple Choice

Calculate the frequency of vertical oscillations for a mass suspended from a light spring of known stiffness.

Practise this question

Question

Multiple choice question 25. A mass of 0.90 kg is suspended from a light spring of stiffness 80 N m^-1. When the mass is displaced vertically and released, it undergoes vertical oscillations of small amplitude. What is the frequency of the oscillations? Four options are given: A 0.071 Hz, B 0.67 Hz, C 1.50 Hz, and D 14 Hz.
Question text

25 A mass of 0.90 kg is suspended from the lower end of a light spring of stiffness 80 N m−1.

When the mass is displaced vertically and released, it undergoes vertical oscillations of

small amplitude.

What is the frequency of the oscillations?

[1 mark]

A 0.071 Hz

B 0.67 Hz

C 1.50 Hz

D 14 Hz

Mark scheme

Show the mark scheme Mark scheme indicating the correct answer for question 25 is C.

25 C

How to answer it

Frequency of a Mass-Spring System

Question 25 • Multiple Choice • 1 Mark

What this question tests

This question assesses your ability to recall and apply the equation for the frequency of a mass-spring oscillating system undergoing Simple Harmonic Motion (SHM). It tests unit conversion awareness, formula manipulation (linking mass, spring constant, period, and frequency), and handling significant figures in multiple-choice calculations.

Exam Question Breakdown

Part 25 — Calculating Frequency

✅ Correct Answer

C (1.50 Hz)

Mark Awarded: 1 / 1 for selecting option C.

💡 Key Knowledge

  • The period T of a mass-spring system is given by: T = 2 π √(m / k)
  • Frequency f is the reciprocal of period: f = 1 / T
  • Combining these gives the frequency formula: f = (1 / (2 π)) √(k / m)
  • Always ensure mass is in standard SI units ( kg ) and spring constant is in N m⁻¹ .

🧠 Exam Technique

  • Check your calculator mode: Ensure you are not in gradient or radian mode unnecessarily when using trigonometric functions elsewhere, though standard constants apply here.
  • Don't stop halfway: A very common multiple-choice trap is calculating the period T and accidentally picking the option that matches that value instead of inverting it to find f .

❌ Common Errors

  • Inverting the ratio: Accidentally using √(m / k) inside the frequency equation instead of √(k / m) .
  • Forgetting 2 π: Omitting the 2 π factor, which stems from treating SHM as uniform circular motion projections.
  • Stopping at Period: Calculating T ≈ 0.67 s (Option B) and selecting it without realizing the question asked for frequency.

📐 Step-by-Step Calculation

  1. Identify given variables: Mass m = 0.90 kg , Spring constant k = 80 N m⁻¹ .
  2. State the frequency formula for a mass-spring system:
    f = (1 / (2 π)) √(k / m)
  3. Substitute the values into the equation:
    f = (1 / (2 × π)) √(80 / 0.90)
  4. Evaluate the term inside the square root:
    √(88.889) ≈ 9.428
  5. Complete the calculation and apply sig figs:
    f = 9.428 / (2 × π) = 1.5002... Hz
    Rounding to 3 significant figures (matching the precision of the input data) gives 1.50 Hz.

Topics

Physics · 3.6 Further mechanics and thermal physics (A-level only)

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.