AQA A-Level Physics Paper 1, June 2022: Question 14

1 mark · Easy difficulty · Multiple Choice

Identify the physical quantity represented by eVs in photoelectric emission, given Vs is the stopping potential.

Practise this question

Question

Multiple choice question numbered 1.4 asking what quantity eVs represents in photoelectric emission, where Vs is the stopping potential. Four options are given: A, energy of an incident photon; B, maximum kinetic energy of a photoelectron; C, threshold frequency multiplied by the Planck constant; D, work function.
Question text

14 In photoelectricity, Vs is the stopping potential.

What quantity is eVs?

[1 mark]

A energy of an incident photon

B maximum kinetic energy of a photoelectron

C threshold frequency × the Planck constant

D work function

Mark scheme

Show the mark scheme Mark scheme indicating the correct answer is B, corresponding to the maximum kinetic energy of a photoelectron.

14 B (AO2) maximum kinetic energy of a photoelectron

How to answer it

Stopping Potential and Kinetic Energy in the Photoelectric Effect

Question 1.4 • Multiple Choice • 1 Mark

What this question tests

This question tests your understanding of the definitions and key equations associated with the photoelectric effect, specifically how the stopping potential ( Vs ) relates to the maximum kinetic energy of photoelectrons.

Exam Question Breakdown

✅ Correct Answer

Option B: maximum kinetic energy of a photoelectron

Mark Awarded: 1 / 1 (AO2)

💡 Key Knowledge

  • Stopping Potential ( Vs ): The minimum potential difference required to stop the fastest moving photoelectrons from reaching the anode.
  • Energy Conservation: When a photoelectron is stopped, all its maximum kinetic energy is converted into electrical potential energy ( E = QV = e Vs ).

🧠 Exam Technique

In multiple-choice questions involving definitions, link the symbols immediately. Recognize that e is the elementary charge (charge of an electron) and Vs is the stopping potential. The product of charge and potential difference ( Q×V ) always yields energy in joules or electronvolts.

❌ Common Errors

  • Confusing stopping potential energy ( e Vs ) with the work function ( Φ ), which is the minimum energy required to liberate an electron from the metal surface (Option D).
  • Confusing it with the total energy of the incident photon ( hf , Option A).

Topics

Physics · 3.2 Particles and radiation

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.