AQA A-Level Physics Paper 1, June 2023: Question 8
1 mark · Medium difficulty · Multiple Choice
Estimate the speed of a person just after leaving the ground when jumping vertically as high as possible from a standing position.
Practise this questionQuestion
Question text
08 A person jumps as high as she can from a standing position.
What is a reasonable estimate of her speed just after she leaves the ground?
[1 mark]
A 2 m s−1
B 4 m s−1
C 8 m s−1
D 10 m s−1
Mark scheme
Show the mark scheme
08 B 4 m s−1
How to answer it
Estimating Vertical Jump Speed
This question assesses your ability to apply physical principles and order-of-magnitude estimation to everyday human biomechanics. Specifically, it tests your understanding of kinematics and energy conservation (converting kinetic energy into gravitational potential energy) to evaluate realistic physical values for human motion.
Part 08: Estimating Take-off Speed
Multiple Choice Selection
✅ Correct Answer
B: 4 m s⁻¹
💡 Key Knowledge
- A good vertical jump from a standing position lifts a person's center of mass by roughly 0.5 m to 0.8 m .
- Energy conservation links initial kinetic energy to maximum gravitational potential energy: 0.5 × m × v² = m × g × h .
- Mass ( m ) cancels out, leaving v = √(2 × g × h) .
🧠 Exam Technique
When faced with an order-of-magnitude estimation question involving human capabilities, anchor yourself to numbers you know. Think about how high you can jump (about half a meter) and work backwards using SUVAT or energy equations.
❌ Common Errors
- Choosing 10 m s⁻¹ (Option D): This is roughly free-fall acceleration or running speed, which would result in a vertical jump height of over 5 m —physically impossible for a human from a standing start!
- Guessing blindly without applying a mental physics model.
📐 Step-by-Step Physics Breakdown
- Estimate jump height ( h ): A typical athletic standing vertical jump reaches a height of about 0.8 m (or estimate using energy methods).
- State the SUVAT or Energy relation: v² = u² + 2as (where u = 0 at maximum height, moving downwards, or working upwards: final velocity at peak is 0 , so 0 = v² - 2gh ).
- Rearrange for initial velocity ( v ): v = √(2 × g × h)
- Substitute values: v = √(2 × 9.81 × 0.8) ≈ √(15.7) ≈ 4.0 m s⁻¹
This confirms option B is the only physically reasonable estimate.
Topics
Physics · 3.1 Measurements and their errors
Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.