AQA A-Level Physics Paper 2, June 2023: Question 10
1 mark · Medium difficulty · Multiple Choice
Estimate the ratio of the electrostatic repulsive force to the gravitational attractive force between two protons.
Practise this questionQuestion
Question text
10 Two protons are separated by a distance of 1 × 10−9 m.
electric repulsion force
Which is an estimate of for these two protons?
gravitational attraction force
[1 mark]
A 1018
B 1028
C 1036
D 1045
Mark scheme
Show the mark scheme
10 C 1036
How to answer it
Comparing Electric and Gravitational Forces Between Protons
What this question tests
This question assesses your ability to apply Coulomb's Law and Newton's Law of Gravitation to fundamental particles, recognize inverse-square law cancellations, retrieve physical constants from the data booklet, and perform order-of-magnitude estimations under timed multiple-choice conditions.
Ratio of Electrostatic Force to Gravitational Force
Two protons separated by a distance of 1 × 10⁻⁹ m
✅ Correct Answer
Option C: 10³⁶
The electrostatic repulsion between two protons is approximately 36 orders of magnitude stronger than their gravitational attraction.
💡 Key Knowledge
- Coulomb's Law: FE = (1 / 4πε₀) × (q₁q₂ / r²)
- Newton's Law of Gravitation: FG = G × (m₁m₂ / r²)
- Distance independence: Because both obey an inverse-square law ( ∝ 1/r² ), the separation distance r completely cancels out in the ratio.
- Constants from Data Booklet:
- 1 / (4πε₀) ≈ 8.99 × 10⁹ N m² C⁻²
- G ≈ 6.67 × 10⁻¹¹ N m² kg⁻²
- Proton charge e = 1.60 × 10⁻¹⁹ C
- Proton rest mass mp = 1.67 × 10⁻²⁷ kg
📐 Step-by-Step Calculation
- Set up the ratio:
Ratio = FE / FG = [ (1 / 4πε₀) × (e² / r²) ] / [ G × (mp² / r²) ] - Cancel separation r² :
Ratio = [ (1 / 4πε₀) × e² ] / [ G × mp² ]
Notice: The given distance of 1 × 10⁻⁹ m is not needed! - Estimate powers of ten (Mental / Quick Check):
- Numerator power: 10⁹ × (10⁻¹⁹)² = 10⁹ × 10⁻³⁸ = 10⁻²⁹
- Denominator power: 10⁻¹¹ × (10⁻²⁷)² = 10⁻¹¹ × 10⁻⁵⁴ = 10⁻⁶⁵
- Power ratio: 10⁻²⁹ / 10⁻⁶⁵ = 10³⁶
- Full calculation confirmation:
Numerator = (8.99 × 10⁹) × (1.60 × 10⁻¹⁹)² ≈ 2.30 × 10⁻²⁸
Denominator = (6.67 × 10⁻¹¹) × (1.67 × 10⁻²⁷)² ≈ 1.86 × 10⁻⁶⁴
Ratio = (2.30 × 10⁻²⁸) / (1.86 × 10⁻⁶⁴) = 1.24 × 10³⁶ ≈ 10³⁶
🧠 Exam Technique & Time Savers
- Spot redundant data: Examiners frequently include values (like the separation 1 × 10⁻⁹ m ) to see if you instinctively spot the cancellation. Don't waste precious minutes squaring and dividing by 1 × 10⁻⁹ twice!
- Order-of-magnitude estimation: When options differ vastly by powers of 10 ( 10¹⁸, 10²⁸, 10³⁶, 10⁴⁵ ), you only need to track the exponents: 9 - 38 - (-11 - 54) = -29 - (-65) = +36 . This solves the question in under 20 seconds.
❌ Common Errors & Pitfalls
- Forgetting to square the charges or masses: A common slips is calculating e / mp instead of e² / mp² .
- Sign errors in exponents: Subtracting negative powers incorrectly in the denominator: -29 - (-65) = +36 , not -94 .
- Using electron mass instead of proton mass: If you use me = 9.11 × 10⁻³¹ kg , you will get a ratio near 10⁴²–10⁴³ , which might tempt you to select D (10⁴⁵). Ensure you pick the proton mass!
Topics
Physics · 3.7 Fields and their consequences (A-level only)
Question and mark scheme from the AQA A-Level Physics examination, Paper 2, June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.