AQA A-Level Physics Paper 2, June 2023: Question 10

1 mark · Medium difficulty · Multiple Choice

Estimate the ratio of the electrostatic repulsive force to the gravitational attractive force between two protons.

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Question

Multiple choice question asking: 'Two protons are separated by a distance of 1 × 10⁻⁹ m. Which is an estimate of (electric repulsion force) / (gravitational attraction force) for these two protons?' Options: A is 10¹⁸, B is 10²⁸, C is 10³⁶, and D is 10⁴⁵.
Question text

10 Two protons are separated by a distance of 1 × 10−9 m.

electric repulsion force

Which is an estimate of for these two protons?

gravitational attraction force

[1 mark]

A 1018

B 1028

C 1036

D 1045

Mark scheme

Show the mark scheme Mark scheme table row for question 10 showing correct response key 'C' and value '10³⁶'.

10 C 1036

How to answer it

AQA A-Level Physics • Gravitational & Electric Fields

Comparing Electric and Gravitational Forces Between Protons

What this question tests

This question assesses your ability to apply Coulomb's Law and Newton's Law of Gravitation to fundamental particles, recognize inverse-square law cancellations, retrieve physical constants from the data booklet, and perform order-of-magnitude estimations under timed multiple-choice conditions.

Question 10 (1 Mark)

Ratio of Electrostatic Force to Gravitational Force

Two protons separated by a distance of 1 × 10⁻⁹ m

✅ Correct Answer

Option C: 10³⁶

Mark Scheme: Award 1 mark for selecting C (10³⁶).

The electrostatic repulsion between two protons is approximately 36 orders of magnitude stronger than their gravitational attraction.

💡 Key Knowledge

  • Coulomb's Law: FE = (1 / 4πε₀) × (q₁q₂ / r²)
  • Newton's Law of Gravitation: FG = G × (m₁m₂ / r²)
  • Distance independence: Because both obey an inverse-square law ( ∝ 1/r² ), the separation distance r completely cancels out in the ratio.
  • Constants from Data Booklet:
    • 1 / (4πε₀) ≈ 8.99 × 10⁹ N m² C⁻²
    • G ≈ 6.67 × 10⁻¹¹ N m² kg⁻²
    • Proton charge e = 1.60 × 10⁻¹⁹ C
    • Proton rest mass mp = 1.67 × 10⁻²⁷ kg

📐 Step-by-Step Calculation

  1. Set up the ratio:
    Ratio = FE / FG = [ (1 / 4πε₀) × (e² / r²) ] / [ G × (mp² / r²) ]
  2. Cancel separation r² :
    Ratio = [ (1 / 4πε₀) × e² ] / [ G × mp² ]
    Notice: The given distance of 1 × 10⁻⁹ m is not needed!
  3. Estimate powers of ten (Mental / Quick Check):
    • Numerator power: 10⁹ × (10⁻¹⁹)² = 10⁹ × 10⁻³⁸ = 10⁻²⁹
    • Denominator power: 10⁻¹¹ × (10⁻²⁷)² = 10⁻¹¹ × 10⁻⁵⁴ = 10⁻⁶⁵
    • Power ratio: 10⁻²⁹ / 10⁻⁶⁵ = 10³⁶
  4. Full calculation confirmation:
    Numerator = (8.99 × 10⁹) × (1.60 × 10⁻¹⁹)² ≈ 2.30 × 10⁻²⁸
    Denominator = (6.67 × 10⁻¹¹) × (1.67 × 10⁻²⁷)² ≈ 1.86 × 10⁻⁶⁴
    Ratio = (2.30 × 10⁻²⁸) / (1.86 × 10⁻⁶⁴) = 1.24 × 10³⁶ ≈ 10³⁶

🧠 Exam Technique & Time Savers

  • Spot redundant data: Examiners frequently include values (like the separation 1 × 10⁻⁹ m ) to see if you instinctively spot the cancellation. Don't waste precious minutes squaring and dividing by 1 × 10⁻⁹ twice!
  • Order-of-magnitude estimation: When options differ vastly by powers of 10 ( 10¹⁸, 10²⁸, 10³⁶, 10⁴⁵ ), you only need to track the exponents: 9 - 38 - (-11 - 54) = -29 - (-65) = +36 . This solves the question in under 20 seconds.

❌ Common Errors & Pitfalls

  • Forgetting to square the charges or masses: A common slips is calculating e / mp instead of e² / mp² .
  • Sign errors in exponents: Subtracting negative powers incorrectly in the denominator: -29 - (-65) = +36 , not -94 .
  • Using electron mass instead of proton mass: If you use me = 9.11 × 10⁻³¹ kg , you will get a ratio near 10⁴²–10⁴³ , which might tempt you to select D (10⁴⁵). Ensure you pick the proton mass!

Topics

Physics · 3.7 Fields and their consequences (A-level only)

Question and mark scheme from the AQA A-Level Physics examination, Paper 2, June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.