AQA A-Level Physics Paper 2, June 2023: Question 29

1 mark · Easy difficulty · Multiple Choice

Identify the most appropriate type of radiation to measure the thickness of an aluminium sheet of approximately 0.5 mm.

Practise this question

Question

Question 29 asks: Radiation is used to measure the thickness of an aluminium sheet accurately. The thickness of the sheet is about 0.5 mm. Which type of radiation is most appropriate for the measurement? There are four options: A is alpha, B is beta minus, C is beta plus, and D is gamma.
Question text

29 Radiation is used to measure the thickness of an aluminium sheet accurately.

The thickness of the sheet is about 0.5 mm.

Which type of radiation is most appropriate for the measurement?

[1 mark]

A α

B β−

C β+

D γ

Mark scheme

Show the mark scheme Mark scheme table row for question 29: Key is B (beta minus).

29 B β−

How to answer it

Radiation Gauging for Metal Sheet Thickness

📌 What this question tests

This question assesses your understanding of the penetrating power of ionising radiations (α, β⁻, β⁺, and γ) and how these properties dictate their industrial applications in automated thickness monitoring.

Question 29 • Multiple Choice [1 Mark]

Choosing the Appropriate Radiation for 0.5 mm Aluminium

Radiation source selection for real-time attenuation monitoring

✅ Correct Answer

B — β⁻ (Beta-minus particles)

Award 1 mark for selecting option B.

Beta particles are partially absorbed by thin sheets of aluminium (~0.5 mm to a few mm). A small variation in sheet thickness produces a measurable change in detected count rate.

💡 Key Knowledge

  • Alpha (α): Extremely low penetration. Completely absorbed by a single sheet of paper or a few centimetres of air. It would be 100% blocked by 0.5 mm of aluminium, showing zero count rate regardless of variations.
  • Beta-minus (β⁻): Penetrates several millimetres of aluminium. At 0.5 mm, a significant fraction passes through, making count rate directly sensitive to thickness fluctuations.
  • Beta-plus (β⁺): Positrons rapidly encounter electrons in the metal, undergoing matter-antimatter annihilation to produce 511 keV gamma photons, destroying the predictable attenuation profile.
  • Gamma (γ): Highly penetrating. Almost entirely passes through 0.5 mm of aluminium with negligible absorption; variations in thickness would cause negligible change in count rate.

🧠 Exam Technique & Elimination

Use the principle of attenuation sensitivity:

  1. Step 1: Check extremes. If radiation is completely absorbed (α) or barely absorbed at all (γ), count rate won't correlate sensitively with thickness. Eliminate A and D immediately.
  2. Step 2: Compare β⁻ vs β⁺. Beta-plus (β⁺) emits antiparticles (positrons) which annihilate with atomic electrons almost instantly:
    e⁺ + e⁻ → 2γ
    This converts the beta stream into gamma rays, which penetrate straight through. Standard industrial sources therefore use stable β⁻ emitters (such as Strontium-90). Eliminate C.

❌ Common Misconceptions

  • "Beta is completely blocked by aluminium": A common GCSE oversimplification is that "aluminium stops beta". In reality, standard fast beta particles are stopped by several millimetres of aluminium (e.g., ~3–5 mm). A sheet of 0.5 mm absorbs only a fraction, which is precisely why it works as a detector.
  • Picking β⁺ instead of β⁻: Forgetting that positrons are antimatter and annihilate upon contact with ordinary electrons inside the aluminium foil.
  • Choosing Gamma: Gamma rays require dense materials (several centimetres of lead or thick concrete) to see substantial attenuation. A 0.5 mm foil will not alter the gamma count rate detectably.

Topics

Physics · 3.8 Nuclear physics (A-level only)

Question and mark scheme from the AQA A-Level Physics examination, Paper 2, June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.