AQA A-Level Physics Paper 1, June 2024: Question 3

10 marks · Hard difficulty · Extended Answer

Analyze refraction through two joined prisms, the non-astronomical applications of a diffraction grating, and calculate the line spacing and evaluate diffraction options for a given light spectrum.

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Question

Figure 1 shows two prisms A and B of different refractive indices joined together, with a ray of monochromatic light entering prism A and leaving prism B. Figure 2 is a graph of intensity in arbitrary units against wavelength in nanometers from 300 to 700 nm, showing spectral lines including lines labeled X at approximately 380 nm and Y at approximately 390 nm. The questions follow, asking to complete the ray diagram, deduce relative refractive indices, describe a non-astronomical application of a diffraction grating, calculate the grating spacing G given a first-order diffraction angle of 28.2 degrees for line X, and discuss options regarding second-order spectrum versus doubling the grating lines per metre.
Question text

03 Figure 1 shows two prisms A and B of different refractive indices joined to make

a block.

A ray of monochromatic light is shown entering and then leaving the block.

Figure 1

03.1 Complete, on Figure 1, the path of the ray of light inside the block.

[1 mark]

03.2 Deduce which prism, A or B, has the greater refractive index.

[2 marks]

The block is used with a telescope to investigate stars.

The block can be replaced with a diffraction grating.

03.3 Describe one non-astronomical application of a diffraction grating.

[1 mark]

03.4 Figure 2 shows a spectrum of light. Two lines in the spectrum are labelled X and Y.

Figure 2

The light passes at normal incidence through a diffraction grating. The number of

lines per metre for the grating is G.

The first-order diffraction angle of X is at 28.2° to the normal.

Calculate G.

[3 marks]

7 G = m−1

03.5 A scientist wants to obtain an accurate value for the difference in wavelength between

line X and line Y.

She has two options:

• option 1: to analyse the second-order spectrum from the original grating

• option 2: to analyse the first-order spectrum from a grating with 2G lines per metre.

Discuss which option she should choose.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme provides answers for questions 03.1 through 03.5. For 03.1, it requires the ray through A to link to the ray in B and be horizontal by eye. For 03.2, it requires a consistent conclusion and supported by angles of incidence and refraction at the AB boundary. For 03.3, it gives examples of non-astronomical diffraction grating applications like analyzing chemical composition or laser filtering. For 03.4, it details reading lambda as approximately 380 nm from the graph, using d sin theta = n lambda, and calculating G = 1.2 x 10^6 m^-1. For 03.5, it outlines an argument comparing n=2 versus G'=2G, noting angular separations and potential order overlap issues.

Question Answers Additional comments/Guidelines Mark AO

03.1 ray through A links to ray in B Ignore any arrow directions. 1 AO2

AND

ray in B horizontal by eye

03.2 Answer must be consistent with their Figure 2 AO3

1.

Conclusion consistent with their Figure 1

For a correct diagram expect to see B has

greater refractive index / A has lower

refractive index’

10 Supported by consideration of their angles of incidence and

refraction at AB boundary

For a correct diagram expect to see ‘at AB

boundary angle of incidence > angle of

refraction’ OR ‘at AB boundary the ray bends

towards the normal’.

03.3 how the grating is used must be described 1 AO1

e.g ‘used to determine λ of named light

source’ or ‘used to identify elements in a

sample’

Examples:

To analyse chemical composition (of a

sample)

To stabilise/filter laser light

To provide a monochromatic source/select a

particular wavelength of light

appropriate application described In optical encoders for high-precision motor 11

control

Spread evenly the light from e-readers

Condone:

to identify (some) authentic bank notes

applications asociated with entertainment eg

light shows/diffraction glasses.

application associated with analysis of the

light from the Sun

03.4 Ignore POT error in MP1 & MP2. 3 2 × AO2

1 × AO3

MAX 2 from Accept answer in range 377.5 – 382.5 nm.

• λ read from spectrum = 380 nm

• use of d sin θ=n × (their λ ) ‘Use of’ means clear substitution of n, and

θ

1 their λ or rearrangement of equation to give

• use of G = 𝑛𝑛𝑛𝑛

d 𝑑𝑑 = .

sin 𝜃𝜃

If n not seen, assume that n = 1.

Expect to see 8.04 × 10–7 m for d

to give 1.2 × 106 (m–1)

MP2 and MP3 may be seen together

Calculator value range: 1.251790×106 m-1 to

1.2435547×106 m-1 to 1.235427×106 m-1

03.5 3 3 × AO3

Argument involving sinθ = nGλ or equivalent

comparing effect of n = 2 and G’ = 2G

Appreciation that angular separations would be the same

for both options For MP3, allow maxima are better defined in

option 2

Discussion suggesting option 2 / 2G should be used, as

n = 2 spectrum could overlap with other orders obscuring

absorption lines

Alternative for MP3: idea that 2G should be

used as the second-order spectrum would be

dimmer – allow reverse argument that 2G first

order would be brighter.

Total 10

How to answer it

Optics, Refraction & Diffraction Gratings Study Guide

AQA A-Level Physics

What this question tests

This exam question tests your core understanding of wave optics, specifically refraction across boundaries, Snell's law principles, practical applications of diffraction gratings, multi-step grating calculations (involving lines per metre G and slit spacing d), and analytical evaluation of experimental options.

Question 03.1: Ray Tracing Through Prisms

Complete the path of the ray of light inside the block. [1 mark]

✅ Correct Answer

The ray passing through prism A must link smoothly to the ray entering prism B at the internal boundary, and exit horizontally to the right across the vertical face of prism B.

💡 Key Knowledge

  • A normal line is perpendicular to the boundary surface.
  • Light entering a medium with a higher refractive index bends towards the normal.
Mark scheme note: Ray through A links to ray in B, and ray in B is horizontal by eye. Arrow directions are ignored.

Question 03.2: Refractive Index Deduction

Deduce which prism, A or B, has the greater refractive index. [2 marks]

✅ Correct Answer

Prism B has the greater refractive index (or prism A has the lower refractive index).

🧠 Exam Technique

To secure both marks, your written deduction must directly match your optical drawing in 03.1. Explicitly state that at the AB boundary, the angle of incidence is greater than the angle of refraction, demonstrating that the ray bends towards the normal upon entering prism B.

Mark scheme note: 1 mark for a conclusion consistent with Figure 1, and 1 mark supported by consideration of angles of incidence and refraction at the AB boundary.

Question 03.3: Applications of Diffraction Gratings

Describe one non-astronomical application of a diffraction grating. [1 mark]

✅ Correct Answer

Used to determine the wavelength of a named light source, or used to analyse the chemical composition of a sample by observing its atomic line spectra.

❌ Common Errors

Vague statements like "to look at light" or general mentions of "lasers" without explaining how the grating is utilised will fail to score. You must link the grating to its function (e.g., dispersing light into constituent wavelengths).

Mark scheme note: Must describe how the grating is used (e.g., to determine wavelength of a light source, or to identify elements in a sample).

Question 03.4: Calculating Lines per Metre (G)

The first-order diffraction angle of X is at 28.2 degrees to the normal. Calculate G. [3 marks]

📐 Step-by-Step Calculation

  1. Read wavelength from graph (Line X): Looking at Figure 2, peak X occurs at 380 nm (Acceptable range: 377.5 nm to 382.5 nm). Convert to metres: 380 × 10⁻⁹ m .
  2. Recall grating equation: d sin θ = n λ . Here, order n = 1 and angle θ = 28.2° .
  3. Rearrange for slit spacing (d): d = (n λ) / sin θ = (1 × 380 × 10⁻⁹) / sin(28.2°) = 8.04 × 10⁻⁷ m .
  4. Calculate lines per metre (G): G = 1 / d = 1 / (8.04 × 10⁻⁷) = 1.24 × 10⁻⁶ m⁻¹ (Acceptable range from mark scheme: 1.24 × 10⁻⁶ m⁻¹ to 1.25 × 10⁻⁶ m⁻¹ ).

❌ Common Calculation Traps

Powers of 10: Forgetting to convert nanometres ( nm ) to metres ( m ) using ×10⁻⁹ is the most frequent source of lost marks.

Mark scheme note: Max 2 marks if calculation uses correct substitution but makes a unit conversion error. Final answer expected around 1.2 × 10⁶ m⁻¹ .

Question 03.5: Evaluating Experimental Options

Discuss which option she should choose to obtain an accurate value for the difference in wavelength between line X and line Y. [3 marks]

✅ Correct Answer

She should choose option 2 (analysing the first-order spectrum with a grating of 2G lines per metre).

💡 Key Knowledge & Argumentation

  • Comparing effects: Using n = 2 (option 1) vs doubling the grating density 2G (option 2) yields equivalent angular separations for the diffraction pattern based on d sin θ = n λ .
  • Order overlap mitigation: Option 2 uses the first-order spectrum ( n = 1 ), avoiding spectral lines from higher orders overlapping with each other, which would obscure absorption or emission lines. Alternatively, second-order spectra can suffer from reduced brightness/dimmer images.
Mark scheme note: 3 marks awarded for: (1) an equation-backed comparison ( sin θ = n G λ ), (2) appreciation that angular separations are equal for both options, and (3) concluding that option 2 is superior because higher orders ( n = 2 ) risk overlapping orders obscuring lines.

Topics

Physics · Optional topics · 3.3 Waves · 3.9 Astrophysics (A-level only)

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.