AQA A-Level Physics Paper 1, June 2024: Question 9

1 mark · Medium difficulty · Multiple Choice

Identify the correct graph showing how the maximum kinetic energy of photoelectrons varies with frequency for two metal plates with different work functions.

Practise this question

Question

Multiple choice question 09 asking to identify the correct graph of maximum kinetic energy Ek(max) against frequency f for two metal plates X and Y, where metal X has a greater work function than metal Y. Four graphs labeled A, B, C, and D show different line combinations with parallel or intersecting lines for metals X and Y.
Question text

09 In two separate experiments, electromagnetic radiation of variable frequency f is incident

on the surfaces of plates made from metals X and Y.

The work function of X is greater than the work function of Y.

Which graph shows how the maximum kinetic energy Ek(max) of photoelectrons emitted

from the surfaces of the plates varies with f ?

[1 mark]

A B

C D

A

B

C

D

Mark scheme

Show the mark scheme Mark scheme for question 09 showing the correct answer is A, displaying a graph where line Y has a lower threshold frequency than line X, and both lines are parallel.

AO1

09 A

How to answer it

Photoelectric Effect: Interpreting Kinetic Energy vs Frequency Graphs

What this question tests

This question assesses your understanding of the photoelectric equation ( Eₖ₍ₘₐₓ⟩ = hf - φ ), specifically how changes in the work function ( φ ) affect the threshold frequency and the graphical representation of maximum kinetic energy against incident frequency.

Question 09

Exam Breakdown

✅ Correct Answer

Graph A is the correct choice.

1 mark awarded for selecting option A.

💡 Key Knowledge

  • The photoelectric equation is arranged in the form of a straight-line equation ( y = mx + c ): Eₖ₍ₘₐₓ⟩ = hf - φ .
  • The gradient of the line is equal to the Planck constant ( h ), meaning all such lines for any metal must be perfectly parallel.
  • The threshold frequency ( f₀ ) is the intercept on the frequency axis, where Eₖ₍ₘₐₓ⟩ = 0 , calculated as f₀ = φ / h .
  • Since metal X has a greater work function than metal Y ( φₓ > φᵧ ), metal X requires a higher threshold frequency ( f₀,ₓ > f₀,ᵧ ).

🧠 Exam Technique

  • Check gradients first: Eliminate any options where the lines are not parallel (eliminates B and D, since h is a universal constant).
  • Analyze intercepts: Look at the threshold frequency axis ( f ). Since φₓ > φᵧ , metal X must intercept the frequency axis further to the right (at a higher frequency value) than metal Y. This points directly to graph A.

❌ Common Errors

  • Confusing work function with threshold: Students sometimes mix up which metal should have a higher intercept. Remember that a larger work function means you need a higher frequency of light to release electrons, shifting the line to the right.
  • Non-parallel lines: Selecting graphs with different steepness (like graph B) demonstrates a fundamental misunderstanding that the Planck constant changes depending on the metal used.

Topics

Physics · 3.2 Particles and radiation

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.