AQA A-Level Physics Paper 1, June 2025: Question 2

10 marks · Medium difficulty · Extended Answer

Explain transverse and stationary wave properties on a wire, and calculate wire properties to determine which wire and tension allows the first five harmonics to be produced within a given frequency range.

Practise this question

Question

Exam question 02 consisting of four parts. Question 02.1 asks to state what is meant by a transverse wave. Figure 2 shows an experimental setup with a vibration generator connected to a variable-frequency AC supply, driving a wire stretched over a pulley to a suspended weight W. Question 02.2 asks to explain how a stationary wave is produced on the wire. Figure 3 shows a section of wire oscillating with five points marked: nodes P1, P3, P5 and antinodes P2, P4. Question 02.3 asks how the phase of the particles varies between P1 and P5. Question 02.4 gives data for two wires A and B (mass per 2.00 m), supply frequency range 1 to 50 Hz, length 1.50 m, and weights 1.0 N or 5.0 N, asking for the mass per unit length and a justified choice of wire and weight to produce the first five harmonics.
Question text

02.1 State what is meant by a transverse wave.

[2 marks]

Figure 2 shows apparatus that is used to investigate stationary waves on a

stretched wire.

Figure 2

A block of weight W is used to keep the wire under tension.

The frequency of the ac supply is varied until a stationary wave is produced on

the wire.

02.2 Explain how a stationary wave is produced on the wire.

[1 mark]

02.3 Figure 3 shows a small section of the wire at one instant.

Five points on the wire are labelled P1 to P5.

The dashed line represents the position of the wire when the ac supply is turned off.

Figure 3

Describe how the phase of the oscillating particles varies along the wire

between P1 and P5.

[2 marks]

02.4 A student investigates stationary waves on a wire using the apparatus in Figure 2.

The investigation requires the student to produce the first five harmonics on the wire.

The student needs to choose one of two wires, A or B, for the investigation.

The mass of a 2.00 m length of wire A is 1.32 g.

The mass of a 2.00 m length of wire B is 2.94 g.

The ac supply can produce signals in the range 1 Hz to 50 Hz.

The length of the wire that vibrates between the vibration generator and the pulley

is 1.50 m.

The student needs to choose one value for weight W for the investigation.

W can be either 1.0 N or 5.0 N.

Determine, in kg m−1, the mass per unit length of each wire.

Go on to suggest which wire and which value of W the student should use to produce

*05*the first five harmonics.

[5 marks]

mass per unit length of A = kg m–1

mass per unit length of B = kg m–1

wire = W = N

Mark scheme

Show the mark scheme Mark scheme for Question 2 with total of 10 marks. 02.1 awards 2 marks for oscillations at right angles to energy transfer. 02.2 awards 1 mark for waves travelling in opposite directions and superposing. 02.3 awards 2 marks for stating particles between P1 and P3 are in phase with each other and in antiphase with particles between P3 and P5. 02.4 awards 5 marks: mass per unit length for wire A is 6.60 x 10^-4 kg/m and B is 1.47 x 10^-3 kg/m; calculating fundamental frequency f1; finding 5f1; comparing to the 50 Hz limit; concluding Wire B and W = 1.0 N.

02.1 Idea that the oscillations (of particles in the wave) are at Allow ‘oscillates’ for ‘oscillations’. Do not 2 AO1

right angles 1 accept ‘vibrations’.

Allow ‘displacement’ for ‘oscillations’

Credit a correctly labelled diagram

Do not allow a contradiction in 1

to the direction of energy transfer 2

2 is contingent on 1 .

Do not allow direction of (wave) motion/travel

Treat any reference to polarisation as neutral.

If no other mark given: award max 1 when

answer suggests that amplitude is

perpendicular to the direction of energy

transfer.

Question Answers Additional comments/Guidance Mark AO

02.2 Idea that waves (from vibration generator and reflected If a reflected wave is referred to, the 1 AO1

wave) travel in opposite directions (along the wire) and presence of an incident wave can be

superpose assumed.

Do not accept ‘interfere’ for ‘superpose’

Do not accept reference to ‘phase

(difference)’unless correct, ie a valid

comment would be ‘phase difference is time

dependent’.

02.3 Idea that particles in wave between P1 and P3 are in phase 2 AO2

OR If no other mark given: award max 1 for ‘P1

and P3 and P5 are nodes’ and ‘P2 and P4

between P3 and P5 are in phase 1

are antinodes’ provided that there is no

reference to a phase relationship between the

nodes.

Reject: ’completely out of phase’ or ‘out of

Idea that particles between P1 and P3 are in antiphase with

phase’ for antiphase; allow ‘π out of phase’ or

particles between P3 and P5

‘180 degrees out of phase’.

OR

idea that P2 and P4 are in antiphase 2

02.4 Determines mass per unit length for either wire and answer A μ = 6.60 × 10−4 kg m−1 5 1 × AO1

seen on answer line 1 −3 −1

B μ = 1.47 × 10 kg m 4 × AO3

Allow incorrect values of mass per unit length

to be carried forward from 1 to the rest of

the answer except 5 .

Expect to see values from:

Determines frequency of first harmonic f1 for one wire and

value of W 2 W / A A B B

N f1 / Hz 5f1/Hz f1 / Hz 5f1 / Hz

Evidence of use of 5f1 to determine the frequency range 1.0 13.0 65.0 8.7 43.5

OR

evidence of required frequency ≤10 Hz 3 5.0 29.0 145 19.4 97.0

Comparison between the fifth-harmonic (frequency) For 4 , look for some idea that their selected

and 50 Hz. 4 fifth-harmonic frequency is the greatest that

does not exceed 50 Hz or that first-harmonic

is greatest that does not exceed 10 Hz.

Allow reference to ‘range’ for values of

frequency.

4 does not require a value for the fifth

harmonic.

Wire B and W = 1.0 N 5 B can be identified by its mass or mass per

unit length.

MP5 is a standalone mark and can be

awarded without further evidence.

Alternative 2 , 3 and 4 For alternative 2 expect to see one from:

W / A B

2 Calculates a wavelength (or half wavelength) for 50 Hz

N wavelength wavelength

and any one combination of wire and weight. / m / m

3 Evidence of maximum wavelength (or half wavelength) 1.0 0.78 0.52

of fifth harmonic is 1.5/(5/2) or 0.6m (or 1.5/2 or 0.3 m).

5.0 1.74 1.17

4 compares between their combination wavelength and

their fifth harmonic maximum wavelength.

If alternative methods are used: 2 is for

using the frequency formula, 3 is for a

calculation that allows the comparison; 4 is

for the comparison.

Total 10

How to answer it

Investigating Stationary Waves on a Stretched Wire

OVERVIEW

What this question tests

  • Wave fundamentals: Accurate definition of a transverse wave using precise scientific terminology.
  • Wave interference: Describing the formation of stationary waves via superposition of counter-propagating waves.
  • Phase relationships: Differentiating between nodes, antinodes, and identifying phase/antiphase particle motion in stationary waves.
  • Experimental design & harmonics: Applying the fundamental frequency formula f = (1 / 2L) × √(T / μ) , calculating mass per unit length, and constraining variables to fit within an apparatus frequency limit (1 Hz – 50 Hz).
PART 02.1

Definition of a Transverse Wave

2 Marks • Assessment Objective: AO1

✅ Model Answer

Oscillations (or displacements) of particles are perpendicular / at right angles [1 mark]
to the direction of energy transfer [1 mark].

Mark 2 is strictly contingent on Mark 1.

💡 Key Knowledge

  • Waves transfer energy without transferring matter.
  • In transverse waves (e.g., waves on a string, EM waves), particle oscillations are at 90° to energy propagation.
  • In longitudinal waves (e.g., sound), oscillations are parallel to energy propagation.

🧠 Exam Technique

Always state "direction of energy transfer" instead of simply "direction of the wave". Examiners penalise ambiguous phrasing such as "direction of wave motion" or "wave travel".

❌ Common Errors

  • Writing vibrations instead of oscillations or displacement.
  • Stating "amplitude is perpendicular" (amplitude is a scalar maximum value, not the motion itself).
  • Saying "perpendicular to the wave" without mentioning energy transfer.
PART 02.2

Formation of a Stationary Wave

1 Mark • Assessment Objective: AO1

✅ Model Answer

Two waves of the same frequency/wavelength travelling in opposite directions (the incident wave from the generator and the reflected wave from the fixed end/pulley) superpose (or combine/add together).

1 mark: Requires both opposite directions and superposition.

❌ Common Errors

  • Using the word interfere instead of superpose. The mark scheme explicitly notes: Do not accept 'interfere' for 'superpose'.
  • Forgetting to state that the reflected wave travels in the opposite direction to the incident wave.
PART 02.3

Phase Variation Between Points P₁ and P₅

2 Marks • Assessment Objective: AO2

✅ Model Answer

  • Particles in the same loop (e.g., between P₁ and P₃, OR between P₃ and P₅) are in phase [1 mark].
  • Particles in adjacent loops (between P₁ and P₃ compared to between P₃ and P₅, or points P₂ and P₄) are in antiphase (or π radians / 180° out of phase) [1 mark].
Max 1 mark if a candidate only identifies P₁, P₃, P₅ as nodes and P₂, P₄ as antinodes without stating phase relationships.

💡 Key Knowledge: Stationary Wave Phase Rules

  • Within one loop (between two adjacent nodes): All vibrating particles are completely in phase (they reach maximum displacement at the same instant), although their amplitudes differ.
  • In adjacent loops: Particles are in antiphase (moving in opposite directions at any given moment).
  • Nodes (P₁, P₃, P₅): Zero amplitude at all times.

❌ Common Errors

  • Vague phrasing like "completely out of phase" or "out of phase" without specifying antiphase, 180°, or π radians.
  • Treating it like a progressive wave and assuming phase varies continuously with distance Δφ = (2π / λ) × Δx .
PART 02.4

Experimental Choice: Wire and Weight Selection

5 Marks • Assessment Objectives: 1 × AO1, 4 × AO3

📐 Step-by-Step Calculations

Step 1: Calculate mass per unit length (μ) for both wires

Convert masses to kg:
Mass of wire A = 1.32 g = 1.32 × 10⁻³ kg
Mass of wire B = 2.94 g = 2.94 × 10⁻³ kg

μ = mass / length = m / 2.00 m

  • Wire A: μA = (1.32 × 10⁻³ kg) / 2.00 m = 6.60 × 10⁻⁴ kg m⁻¹
  • Wire B: μB = (2.94 × 10⁻³ kg) / 2.00 m = 1.47 × 10⁻³ kg m⁻¹
Award [1 mark] for correctly calculating μ for both wires.

Step 2: Apply the fundamental frequency equation

The length of vibrating wire is L = 1.50 m , so 2L = 3.00 m .

f₁ = (1 / 2L) × √(T / μ) = (1 / 3.00) × √(W / μ)

To produce the first five harmonics, the 5th harmonic ( f₅ = 5f₁ ) must NOT exceed the signal generator's maximum frequency of 50 Hz:

5f₁ ≤ 50 Hz  ⇒  f₁ ≤ 10 Hz

Step 3: Test the combinations of wire and weight

Wire Weight W First Harmonic f₁ (Hz) 5th Harmonic 5f₁ (Hz) Fits within 50 Hz limit?
A (6.60 × 10⁻⁴ kg m⁻¹) 1.0 N 13.0 Hz 65.0 Hz ❌ Too high (> 50 Hz)
A (6.60 × 10⁻⁴ kg m⁻¹) 5.0 N 29.0 Hz 145 Hz ❌ Too high (> 50 Hz)
B (1.47 × 10⁻³ kg m⁻¹) 5.0 N 19.4 Hz 97.0 Hz ❌ Too high (> 50 Hz)
B (1.47 × 10⁻³ kg m⁻¹) 1.0 N 8.7 Hz 43.5 Hz ✅ Fits (≤ 50 Hz)

✅ Final Answers & Mark Breakdown

  • mass per unit length of A: 6.60 × 10⁻⁴ kg m⁻¹
  • mass per unit length of B: 1.47 × 10⁻³ kg m⁻¹ [1 mark]
  • Calculates f₁ for at least one wire/weight combination [1 mark].
  • Shows condition 5f₁ or f₁ ≤ 10 Hz [1 mark].
  • Compares 5th harmonic to 50 Hz [1 mark].
  • Selects Wire B and W = 1.0 N [1 mark standalone].

❌ Common Calculation Traps

  • Length Confusion: Dividing mass by 1.50 m instead of 2.00 m when calculating μ. The sample weighed was 2.00 m!
  • Unit Conversion: Forgetting to convert grams to kilograms ( × 10⁻³ ), giving values of μ off by a factor of 1000.
  • Overlooking the 5th Harmonic: Only checking if f₁ ≤ 50 Hz rather than 5f₁ ≤ 50 Hz . All combinations have f₁ < 50 Hz , but only one allows the 5th harmonic to be reached!

Topics

Physics · Practical skills · Required Practicals · 3.3 Waves · AS practicals (1–6) · Data analysis

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.