AQA A-Level Physics Paper 1, June 2025: Question 25
1 mark · Easy difficulty · Multiple Choice
Identify the momentum and gravitational potential energy of a simple harmonic pendulum bob when its acceleration is zero.
Practise this questionQuestion
Question text
25 A pendulum is oscillating with simple harmonic motion.
Which row gives the momentum of the pendulum bob and its gravitational potential energy
(GPE) when the acceleration of the pendulum bob is zero?
[1 mark]
Momentum GPE
A zero maximum
B maximum minimum
C maximum maximum
D zero minimum
Mark scheme
Show the mark scheme
25 B maximum minimum AO1
How to answer it
SHM: Pendulum Dynamics & Energy Exchanges
What this question tests
Understanding the relationship between displacement, acceleration, velocity/momentum, and potential energy in simple harmonic motion (SHM). Specifically, locating the equilibrium position and identifying key physical quantities at that point.
Question 25 Analysis
Multiple Choice: Identifying Momentum and GPE at Zero Acceleration
✅ Correct Answer: B
Momentum: maximum
GPE: minimum
💡 Key Knowledge
- Defining SHM equation: a = −ω²x . Acceleration is directly proportional to displacement and directed towards the equilibrium position.
- When acceleration a = 0 , displacement x = 0 . This is the equilibrium (centre) position.
- Velocity & Momentum: Speed reaches its peak at the equilibrium position ( v max = ±ωA ), so momentum ( p = mv ) is maximum.
- Energy changes: A pendulum bob is at its lowest vertical height at equilibrium, meaning gravitational potential energy ( E p = mgh ) is at a minimum (and kinetic energy is maximum).
🔧 Step-by-Step Deduction
- Identify where a = 0 :
From a = −ω²x , if a = 0 , then x = 0 . The pendulum is swinging through its lowest central point (the equilibrium position). - Determine Momentum ( p ):
At x = 0 , speed is maximum ( v max ). Since p = mv , momentum must be maximum (eliminates options A and D). - Determine Gravitational Potential Energy ( GPE ):
At the centre of the swing, the bob is at its lowest height ( h min ). Since GPE = mgh , GPE is at a minimum (eliminates option C). - Conclusion: Row B is the only matching option.
🧠 Exam Technique
- Translate words to positions: Whenever an SHM question specifies a condition (e.g. acceleration is zero or velocity is zero), instantly map it to either amplitude ( x = ±A ) or equilibrium ( x = 0 ).
- Use Conservation of Energy: Total energy is constant ( E total = E k + E p ). Maximum kinetic energy (and maximum momentum) always coincides with minimum potential energy. This immediately rules out C and D!
❌ Common Traps & Misconceptions
- Confusing the positions: Thinking acceleration is zero at the extremes/turning points. At the extremes, speed is zero, but acceleration and restoring force are at their maximum.
- Confusing momentum with acceleration: Some students incorrectly assume that when acceleration is zero, the bob is "not moving" ( v = 0 , p = 0 ), leading them to select A. Remember: zero acceleration means constant instantaneous velocity (i.e. the turning point of velocity, where it reaches peak value), not zero velocity!
- Choosing simultaneous maximums: Selecting C (maximum momentum AND maximum GPE) violates conservation of mechanical energy in a simple pendulum.
📊 Mental Diagram Check: The Pendulum Cycle
Extremes (Left / Right, x = ±A ): Height is greatest → GPE = max , KE = 0 , v = 0 , p = 0 , a = max .
Equilibrium (Centre, x = 0 ): Height is lowest → GPE = min , KE = max , v = max , p = max , a = 0 .
Topics
Physics · 3.4 Mechanics and materials · 3.6 Further mechanics and thermal physics (A-level only)
Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.