AQA A-Level Physics Paper 2, June 2025: Question 14
1 mark ยท Medium difficulty ยท Multiple Choice
Determine the direction of the electric force on an electron placed in an electric field shown by curved equipotential lines.
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Direction of Electric Force on an Electron
This question tests your understanding of equipotential lines, the relationship between potential gradient and electric field direction, and how the sign of a charge dictates the direction of electrostatic force ( F = qE ).
Question 14: Electric Force on a Negative Charge
Multiple Choice (1 Mark) โ Assessment Objective: AO1
โ Correct Answer: C
The electron experiences an electrostatic force directed along arrow C (towards the higher potential of +20 V, perpendicular to the equipotential line).
๐ก Key Knowledge
- Equipotential surfaces: Lines connecting points of equal potential. Moving along an equipotential line requires zero work ( ฮW = qฮV = 0 ).
- Field lines vs. Equipotentials: Electric field lines always cross equipotential surfaces at 90ยฐ (right angles). Therefore, the force must be along arrow A or C.
- Field Direction: Electric field lines point down the potential gradient, from higher potential to lower potential ( E = -ฮV/ฮx ).
- Force on charges: Positive charges accelerate towards lower potential (in the direction of E); negative charges (electrons) accelerate towards higher potential (opposite to E).
๐ Step-by-Step Logical Deduction
- Identify the geometry: The electron sits on the +15 V equipotential line. The force must act perpendicular to this line.
โ Arrows B and D run parallel (tangent) to the equipotential, so they are immediately ruled out. - Determine the Electric Field direction: The electric field E always points in the direction of the greatest rate of decrease of potential (from +20 V towards +10 V).
โ Therefore, the electric field vector E points along arrow A. - Apply the force equation ( F = qE ):
Because an electron has a negative charge ( q = -e ), the force acts in the direction opposite to the electric field vector.
โ Opposite to arrow A is arrow C. - Alternative intuitive check: Negatively charged particles are naturally attracted towards regions of higher (more positive) electric potential. Therefore, the electron is pulled towards +20 V (arrow C).
๐ง Exam Technique & Shortcuts
Use the "Attraction to Positive" Rule:
Whenever an electron is placed between different potentials, ask yourself: "Where would a negative particle want to go?"
A negative charge always moves towards the region of more positive potential to reduce its electric potential energy ( Eโ = qV ). Moving to +20 V makes qV more negative (lower energy).
โ Common Traps & Mistakes
- Selecting Option A: The most common error. Students correctly deduce that electric field lines go from high potential to low potential, but forget the electron is negatively charged. Option A is the force on a proton.
- Selecting Option B or D: Confusing field lines with equipotentials. No electrostatic force acts tangent to an equipotential surface.
Topics
Physics ยท 3.7 Fields and their consequences (A-level only)
Question and mark scheme from the AQA A-Level Physics examination, Paper 2, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.