AQA AS Level Biology Paper 1, November 2020: Question 7

10 marks · Medium difficulty · Practical Techniques & Data Analysis

Describe binary fission in bacteria, interpret a growth rate graph for Bacillus subtilis, convert units of mass, and suggest environmental variables to increase cell growth rate.

Practise this question

Question

A four-part exam question about bacterial growth. Part 07.1 asks to describe binary fission in bacteria (3 marks). Figure 7 is a line graph showing cell growth rate in fg s⁻¹ on the y-axis against mass immediately after binary fission in fg on the x-axis for Bacillus subtilis. Part 07.2 asks to convert 680 fg into grams with four multiple-choice options (1 mark). Part 07.3 asks to use Figure 7 and given data to determine the mass of a cell immediately after binary fission, showing working (2 marks). Part 07.4 asks to suggest and explain two environmental variables to increase the growth rate of these cells (4 marks).
Question text

07.1 Describe binary fission in bacteria.

[3 marks]

The cell growth rate of the bacterium Bacillus subtilis is proportional to its mass

immediately after binary fission.

Figure 7 shows this relationship.

Figure 7

07.2 The mass of the bacterial cells was measured in femtograms (fg).

1 fg (femtogram) = 1 × 10−15 g

*15* Place a tick ( ) in the box next to the number that is equal to 680 fg

[1 mark]

0.000 000 000 006 8 g

6.8 × 10−13 g

6.8 × 10−15 g

6.8 × 10−17 g 17

A scientist determined the growth rate of a B. subtilis cell by measuring its mass for

5 minutes.

In those 5 minutes, the cell’s mass increased by 90 fg

*0167.*3 Use this information and Figure 7 to determine the mass of this cell immediately after

binary fission.

Show your working.

[2 marks]

Answer fg

07.4 Suggest and explain how two environmental variables could be changed to increase

the growth rate of these cells.

[4 marks]

Suggestion 1

Explanation

Suggestion 2

Explanation

Mark scheme

Show the mark scheme The mark scheme details answers for questions 07.1 through 07.4. For 07.1, points include replication of circular DNA, replication of plasmids, and division of cytoplasm. For 07.2, the correct option is 6.8 x 10⁻¹³. For 07.3, the correct answer is 660 fg, or marks for correct rate/interpolation. For 07.4, pairs of marked points for naming a variable and explaining its correct effect on growth rate (e.g., increased temperature and increased enzyme activity).

Question Marking Guidance Mark Comments

07.1 1. Replication of (circular) DNA; 3 1. Accept nucleoid

1. Reject

2. Replication of plasmids;

chromosome

3. Division of cytoplasm (to produce daughter 1. Reject mitosis

cells);

3. Ignore genetically

identical

07.2 6.8 × 10−13; 1

07.3 Correct answer of 660 = 2 marks;; 2

Accept for 1 mark,

18 (fg minute‾1)

OR

0.30 (fg s‾1)

OR

Correct use of interpolation lines

07.4 Principle of marking pairs: 4 max

Named environmental variable;

Correct effect on growth rate;

Examples

1. Increased (concentration of) glucose;

2. Increased respiration;

3. Increased (concentration of) oxygen;

4. Increased respiration;

5. Increased temperature;

6. Increased enzyme activity;

7. Increased (concentration of) phosphate;

8. Increased ATP/DNA/RNA;

9. Increased (concentration of) nucleotides;

10. Increased DNA synthesis;

TOTAL 10

How to answer it

Bacterial Growth and Binary Fission Study Guide

What this question tests

This question assesses your understanding of prokaryotic cell division (binary fission), standard form conversions involving femtograms (fg), interpreting graphical data with rates, and applying biochemical and physiological knowledge to explain how environmental variables alter metabolic and growth rates in bacteria.

Question 07.1 (3 Marks)

Describe binary fission in bacteria.

✅ Correct Answer Requirements

  • Replication of circular DNA (accept nucleoid).
  • Replication of plasmids.
  • Division of cytoplasm to produce daughter cells.

❌ Common Errors & Examiner Traps

  • The "Mitosis" Trap: Examiners strictly reject references to "mitosis", "spindle fibres", or "chromosomes" since prokaryotes lack a true nucleus and linear chromosomes.
  • Incomplete descriptions that omit plasmid replication or cytoplasmic division.
Mark allocation: 1 mark per valid point listed in the correct answer box. Max 3 marks.
Question 07.2 (1 Mark)

Standard Form Unit Conversion

The mass of the bacterial cells was measured in femtograms (fg). Given that 1 fg = 1 × 10⁻¹⁵ g , identify the number equal to 680 fg .

✅ Correct Answer

6.8 × 10⁻¹³ g

🧠 Exam Technique & Working

Convert 680 fg to grams by multiplying by 1 × 10⁻¹⁵ :

680 × 10⁻¹⁵ = 6.8 × 10² × 10⁻¹⁵ = 6.8 × 10⁻¹³ g

Mark allocation: 1 mark for ticking the correct option box.
Question 07.3 (2 Marks)

Determining Cell Mass Using Graphs and Rates

A scientist determined the growth rate of a B. subtilis cell by measuring its mass for 5 minutes. In those 5 minutes, the cell's mass increased by 90 fg. Use this information and Figure 7 to determine the mass of this cell immediately after binary fission.

✅ Correct Answer

660 fg (2 marks)

📐 Step-by-Step Calculation

  1. Calculate growth rate per minute:
    90 fg ÷ 5 minutes = 18 fg min⁻¹
  2. Convert growth rate to seconds (matching Figure 7 units of fg s⁻¹):
    18 ÷ 60 = 0.30 fg s⁻¹
  3. Use Figure 7: Find 0.30 fg s⁻¹ on the y-axis, follow across to the line, and read down to the x-axis to find the mass immediately after binary fission.

❌ Common Errors

Forgetting to convert minutes to seconds is the most common way students lose the final accuracy mark. If you calculated 18 fg min⁻¹ or 0.30 fg s⁻¹ correctly but failed to read the graph accurately, 1 mark was awarded.

Mark allocation: 2 marks for 660. Alternatively, 1 mark is awarded for calculating intermediate rates ( 18 fg min⁻¹ or 0.30 fg s⁻¹ ) or correct use of interpolation lines.
Question 07.4 (4 Marks)

Suggest and Explain Environmental Variables

Suggest and explain how two environmental variables could be changed to increase the growth rate of these cells.

💡 Marking Pair Principle

Marks are awarded in marking pairs: 1 mark for naming/suggesting a valid environmental variable with an upward change, and 1 mark for explaining its correct biochemical effect on growth rate.

✅ Example Acceptable Answers

  • Suggestion 1: Increase glucose/nutrient concentration.
    Explanation: Increases rate of respiration, providing more ATP for synthesis reactions.
  • Suggestion 2: Increase temperature (up to optimum).
    Explanation: Increases kinetic energy and enzyme-substrate complex formation, increasing metabolic rate.
  • Alternative 3: Increase oxygen concentration.
    Explanation: Increases aerobic respiration and ATP production.
Mark allocation: 4 marks max (2 marks per complete suggestion-explanation pair).

Topics

Biology · 3.2 Cells

Question and mark scheme from the AQA AS Level Biology examination, Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.