AQA AS Level Biology Paper 2, November 2020: Question 2

7 marks · Medium difficulty · Short Answer

Describe phosphodiester bond formation, calculate maximum amino acids from base ratios and an equation, name proteins associated with DNA, and describe strand separation during semi-conservative replication.

Practise this question

Question

A four-part exam question about DNA structure and replication. Question 02.1 asks to describe how a phosphodiester bond is formed between two nucleotides within a DNA molecule (2 marks). Question 02.2 provides an equation relating guanine, adenine, thymine, and cytosine bases and asks to calculate the maximum number of amino acids coded by the gene (2 marks). Question 02.3 asks to name the protein associated with DNA in a chromosome (1 mark). Question 02.4 asks to describe how the separation of strands occurs during semi-conservative DNA replication (2 marks).
Question text

02.1 Describe how a phosphodiester bond is formed between two nucleotides within a DNA

molecule.

[2 marks]

02.2 The two DNA strands of a particular gene contain 168 guanine bases between them.

The relationship between the numbers of guanine bases (G), adenine bases (A),

thymine bases (T) and cytosine bases (C) in these two strands of DNA is shown in the

following equation.

G = 4(A + T) – C

Use this information and your understanding of DNA structure to calculate the

maximum number of amino acids coded by this gene.

Show your working.

[2 marks]

Answer

02.3 Name the protein associated with DNA in a chromosome.

[1 mark]

02.4 In the process of semi-conservative DNA replication, the two strands within a DNA

molecule are separated. Each then acts as a template for the formation of a new

complementary strand.

Describe how the separation of strands occurs.

[2 marks]

Mark scheme

Show the mark scheme The mark scheme for questions 02.1 to 02.4. Question 02.1 awards max 2 marks for condensation reaction/loss of water, between phosphate and deoxyribose, catalysed by DNA polymerase. Question 02.2 awards 2 marks for the correct answer 70, with intermediate marks for finding A=42 and T=42, total bases 420, or template strand bases 210. Question 02.3 awards 1 mark for Histone. Question 02.4 awards 2 marks for DNA helicase and breaking hydrogen bonds between base pairs.

Question Marking Guidance Mark Comments

02.1 2 max 3. Reject if DNA

1. Condensation (reaction)/loss of water; polymerase joins

AT/GC OR

2. (Between) phosphate and deoxyribose;

complementary

3. (Catalysed by) DNA polymerase; nucleotides/bases OR

forms hydrogen bonds

02.2 Correct answer for 2 marks = 70;; 2

Accept for 1 mark,

A = 42 and T = 42

OR

420 (total bases in gene)

OR

210 (bases in template strand)

02.3 Histone; 1

02.4 1. DNA helicase; 2

2. Breaks hydrogen bonds between base pairs/ AT

and GC/complementary bases

2. Reject hydrolysis

OR

of hydrogen bonds

Breaks hydrogen bonds between polynucleotide

strands;

TOTAL 7

How to answer it

DNA Structure and Replication Study Guide

What this question tests

This question assesses your core knowledge of nucleic acid chemistry, base-pairing rules, chromosome packaging proteins, and the enzymatic mechanisms involved in semi-conservative DNA replication. You will be tested on precision of biological terminology (e.g., condensation reactions, specific enzyme names) and multi-step quantitative problem-solving linking DNA base sequences to polypeptide amino acid lengths.

Question 02.1 (2 marks max)

Describing Phosphodiester Bond Formation

✅ Correct Answer

  • Condensation reaction (involving the loss of water).
  • Forms between a phosphate group and a deoxyribose sugar.
  • Catalysed by the enzyme DNA polymerase.

💡 Key Knowledge

Nucleotides link together in a condensation reaction between the phosphate group attached to the 5' carbon of one nucleotide pentose sugar and the hydroxyl (OH) group attached to the 3' carbon of the next nucleotide.

🧠 Exam Technique

To secure both available marks, you must explicitly state what type of chemical reaction occurs and name the two specific molecular components joined together. Keep your wording concise and direct.

❌ Common Errors

Students frequently lose marks by stating that DNA polymerase joins complementary bases or forms hydrogen bonds. Remember: DNA polymerase joins adjacent nucleotides along the backbone via phosphodiester bonds, whereas DNA helicase/RNA polymerase handle bases and hydrogen bonding.

Mark scheme notes: 2 marks max. Any two valid points from the guidance secure full credit.
Question 02.2 (2 marks)

DNA Base Ratio Calculation & Amino Acid Yield

✅ Correct Answer

70

📐 Step-by-Step Calculation

  1. Recall Chargaff's rules and DNA structure: In double-stranded DNA, Adenine equals Thymine ( A = T ) and Guanine equals Cytosine ( G = C ). Therefore, substitute C with G in the given equation since total G equals total C across the complementary strands.
  2. Solve for A and T: The equation is given as G = 4(A + T) - C . Since G = C , we can write G = 4(A + T) - G , which simplifies to 2G = 4(A + T) , or G = 2(A + T) .
  3. Input known values: We are given G = 168 . Therefore, 168 = 4(A + T) - C . Because G = C , C = 168 .
  4. Rearranging: 168 + 168 = 4(A + T) → 336 = 4(A + T) → A + T = 84 . Since A = T , A = 42 and T = 42 .
  5. Find total bases: Total bases = G + C + A + T = 168 + 168 + 42 + 42 = 420 total bases.
  6. Calculate template strand length: A gene is double-stranded, so the template strand contains half the total bases: 420 / 2 = 210 bases.
  7. Calculate amino acid count: Each amino acid is coded for by a triplet of 3 bases (codon). Number of amino acids = 210 / 3 = 70 .

❌ Common Errors

A major trap is dividing the total number of bases in the gene by 3 without accounting for the fact that only one strand acts as the template for transcription. Always remember to halve the total base count to find the template strand length!

Mark scheme notes: Correct final answer of 70 scores 2 marks directly. Partial credit (1 mark) is awarded for intermediate milestones: A = 42 and T = 42 , total bases = 420, or template strand bases = 210.
Question 02.3 (1 mark)

Proteins Associated with DNA

✅ Correct Answer

Histone(s)

💡 Key Knowledge

Eukaryotic DNA is wound around alkaline proteins called histones to help package and condense DNA tightly into chromosomes within the nucleus. Prokaryotic DNA, by contrast, is naked and not associated with histones.

🧠 Exam Technique

This is a straightforward recall question worth 1 mark. Do not over-elaborate; simply state the correct protein name clearly.

Mark scheme notes: Accept "Histone". Reject generic answers like "chromosome" or "protein" without the specific biological term.
Question 02.4 (2 marks max)

Strand Separation in DNA Replication

✅ Correct Answer

  • Action of the enzyme DNA helicase.
  • Breaks the hydrogen bonds between complementary base pairs (or between the two polynucleotide strands).

💡 Key Knowledge

Before semi-conservative replication can begin, the double helix must "unzip". DNA helicase moves along the molecule, breaking the relatively weak hydrogen bonds holding the complementary nitrogenous bases (A-T and C-G) together without disrupting the strong covalent phosphodiester backbone.

🧠 Exam Technique

To capture both marks, ensure you name the specific enzyme (1 mark) and explicitly state that hydrogen bonds are broken (1 mark).

❌ Common Errors

Students frequently lose the second mark by stating that DNA helicase causes hydrolysis of hydrogen bonds. Examiners strictly reject the word "hydrolysis" in this context because hydrogen bonds are broken physically by enzyme action, not chemically hydrolysed.

Mark scheme notes: 2 marks max. 1 mark for DNA helicase; 1 mark for breaking hydrogen bonds between base pairs / polynucleotide strands.

Topics

Biology · 3.1 Biological molecules · 3.4 Genetic information, variation and relationships between organisms

Question and mark scheme from the AQA AS Level Biology examination, Paper 2, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.