AQA AS Level Biology Paper 2, November 2020: Question 5

9 marks · Medium difficulty · Short Answer

Investigate starch hydrolysis by amylase, drawing a results table, describing expected results, explaining competitive inhibition, and applying this to stale bread and weight loss.

Practise this question

Question

A four-part biology question starting with 05.1 asking students to draw a results table for an enzyme experiment using amylase and starch. Questions 05.2, 05.3, and 05.4 ask to describe expected results, explain how a competitive inhibitor works, and suggest how retrograde starch in stale bread could reduce weight gain.
Question text

05.1 A student investigated starch hydrolysis using the enzyme amylase.

During the procedure, the student:

• treated the starch to make it soluble

• prepared 10 cm3 of different concentrations (mg dm−3) of starch solution

• added an identical concentration of amylase to each starch solution

• measured the time in minutes to completely hydrolyse starch.

He repeated the procedure and calculated the mean time to completely hydrolyse

starch in each concentration of starch solution.

Draw a table the student could use to record all of his results.

You only need to show completed column headings.

[2 marks]

05.2 Describe the results you would expect the student to obtain.

[1 mark]

05.3 A competitive inhibitor decreases the rate of an enzyme-controlled reaction.

Explain how.

[3 marks]

05.4 When bread becomes stale, the structure of some of the starch is changed. This

changed starch is called retrograded starch.

Scientists have suggested retrograded starch is a competitive inhibitor of amylase in

the small intestine.

Assuming the scientists are correct, suggest how eating stale bread could help to

reduce weight gain.

[3 marks]

Mark scheme

Show the mark scheme A mark scheme table containing four rows corresponding to questions 05.1 through 05.4, detailing the required points for awarding marks such as column headings with units, enzyme kinetics, competitive inhibition mechanisms, and digestion/absorption outcomes.

Question Marking Guidance Mark Comments

05.1 2 Ignore columns

with replicates/

mean

Ignore lines

1. Starch (solution) in first column;

2. Headings for starch concentration/solution and time for 2. Accept

(starch) hydrolysis/digestion with mg dm-3 and brackets for

minutes/mins/min/m/seconds/s; solidus

2. Ignore

reference to

enzyme

2. Reject graph

05.2 1. As starch concentration increases, time to 1 Accept converse

hydrolyse/digest starch increases;

05.3 3 1. Reject same

1. Inhibitor similar shape to substrate; shape

2. Fits/binds to active site; 1. Accept

3. Prevents/reduces enzyme-substrate complex forming; ‘complementary

to active site’

05.4 3 1. Accept no

1. Less hydrolysis of starch; hydrolysis

2. (To) maltose;

3. (So) less absorption (of glucose)

3. Accept

OR description of

(So) more egested (starch/carbohydrate); egestion, eg

lost in faeces

TOTAL 9

How to answer it

Enzyme Action, Inhibition and Practical Skills

What this question tests

This exam question evaluates your understanding of practical data organisation (tables and headings), enzyme kinetics in relation to substrate concentration, the mechanism of competitive inhibition using lock-and-key / induced-fit principles, and the application of biochemical concepts to human digestion and weight management.

Question 05.1 (2 Marks)

Designing a Results Table

✅ Correct Answer / Mark Scheme

  • Mark 1: Starch (solution) as the independent variable in the first column.
  • Mark 2: Clear column headings showing starch concentration ( mg dm⁻³ ) and time for hydrolysis ( minutes , min , or seconds ). Brackets are acceptable (e.g., Starch concentration / mg dm⁻³).

🧠 Exam Technique

  • Always put the independent variable (what you change) in the first column on the left.
  • Include both the variable name and correct units separated by a slash or in brackets.
  • Do not include columns for replicates or means if the question asks for basic completed column headings unless specified, to avoid losing marks on strict formatting rules.

❌ Common Errors

  • Omitting units ( mg dm⁻³ or time units) from the headings.
  • Putting the dependent variable (time) in the first column instead of the independent variable (concentration).
  • Drawing a graph instead of a table.
Total for 05.1: 2 marks
Question 05.2 (1 Mark)

Describing Expected Results

✅ Correct Answer

As starch concentration increases, the time taken to hydrolyse/digest the starch increases (or converse).

💡 Key Knowledge

Higher substrate concentrations require more time for a fixed concentration of enzyme to completely break down all available glycosidic bonds because there is a greater total mass of substrate to process.

Total for 05.2: 1 mark
Question 05.3 (3 Marks)

Mechanism of Competitive Inhibition

✅ Correct Answer / Mark Scheme

  • Mark 1: Inhibitor has a similar shape to the substrate / is complementary to the active site.
  • Mark 2: Inhibitor fits / binds directly into the active site of the enzyme.
  • Mark 3: This prevents or reduces the formation of enzyme-substrate complexes.

🧠 Exam Technique

Be precise with terminology. Examiners penalise phrases like "same shape"—always use "similar shape" or "complementary shape". Ensure you explicitly state that it blocks the active site and stops enzyme-substrate complexes from forming.

❌ Common Errors

  • Stating the inhibitor alters the shape of the active site (which describes a non-competitive inhibitor).
  • Saying the inhibitor has the "same shape" instead of "similar" or "complementary".
Total for 05.3: 3 marks
Question 05.4 (3 Marks)

Applied Enzyme Inhibition in Digestion

✅ Correct Answer / Mark Scheme

  • Mark 1: Less hydrolysis of starch.
  • Mark 2: Less breakdown into maltose (reducing sugar).
  • Mark 3: Less absorption of glucose into the blood stream OR more carbohydrate/starch egested in faeces.

💡 Key Knowledge

Retrograded starch acts as a competitive inhibitor to amylase in the gut. Less digested starch means fewer monosaccharides (glucose) are available for active transport / cotransport across the ileum epithelial cells, lowering net calorie intake and reducing weight gain.

🧠 Exam Technique

Link the molecular inhibition directly back to the stem context (eating stale bread, reduced digestion, less absorption, and ultimate body mass impact).

Total for 05.4: 3 marks

Topics

Biology · Practical skills · Required Practicals · Data analysis · 3.1 Biological molecules · 3.3 Organisms exchange substances with their environment · AS practicals (1–6)

Question and mark scheme from the AQA AS Level Biology examination, Paper 2, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.