AQA AS Level Biology Paper 2, June 2022: Question 7

10 marks · Medium difficulty · Practical Techniques & Data Analysis

Produce a scientific drawing of a leaf section, conclude and explain the effect of different factors on cut flower shelf life using table data, and suggest an environmental change to increase shelf life with explanation.

Practise this question

Question

The question contains Figure 8 showing a light micrograph of a vertical leaf section, a box for a scientific drawing, Table 4 showing experimental data regarding stomata, transpiration rate, and shelf life of cut flowers in December and April with standard deviations, followed by three structured parts asking for a drawing, conclusions with explanations based on standard deviations, and an environmental change to increase shelf life.
Question text

07 Figure 8 is a photograph of a vertical section through a leaf observed using an optical

microscope.

Figure 8

07.1 In the box below:

• produce a scientific drawing of the arrangement of tissues shown in Figure 8

• label one of the tissues in your drawing

Do not draw individual cells.

[3 marks]

A scientist investigated factors that affect the shelf life of cut flowers.

A cut flower is the part of the stem with the flower bud attached after it has been cut

from a plant.

The shelf life is the number of days the cut flowers are in good enough condition to be

sold.

He:

• took 12 cut flowers from a rose plant

• determined the mean number of stomata per mm2 on the leaves

• determined the transpiration rate for each cutting

• stored the cut flowers on a shelf in a brightly lit room

• determined the shelf life of the cut flowers.

Table 4 shows his results.

Table 4

Month cut Mean number of Mean transpiration Mean shelf life /

flowers were stomata / mm–2 rate / cm3 day–1 days

obtained (± 2 SD) (± 2 SD) (± 2 SD)

23 22 5

December

(± 2) (± 3) (± 1)

20 15 16

April

(± 3) (± 2) (± 2)

A value of ± 2 SD (standard deviations) from the mean includes over 95% of the data.

07.2 Using information in Table 4, what can you conclude about the effect of different

factors on the mean shelf life of cut flowers?

Explain your conclusions.

[4 marks]

07.3 Other than a change in temperature, give one change the scientist could make to the

environmental conditions to increase the cut flowers’ shelf life.

Explain your answer.

[3 marks]

Mark scheme

Show the mark scheme The mark scheme details points for question 07.1 including drawing tissue bands correctly without individual cells and labeling one tissue. For 07.2, it credits mentioning whether standard deviations overlap for shelf life, transpiration rate, and number of stomata to draw conclusions about significant differences. For 07.3, it accepts reducing light intensity or increasing humidity/reducing air movement to decrease transpiration and increase shelf life.

Question Marking Guidance Mark Comments

1. Four bands (upper epidermis, palisade, 1. and 2. ignore waxy

spongy, lower epidermis); cuticle and vascular

bundle/xylem/phloem

2. Band widths must look similar to photograph; Give benefit of doubt

for use of printed box

as borderlines of

drawing bands.

2. Reject if cells

drawn

2. Reject if lines are

overlapping OR

sketched

2. Ignore stomata and

3 air spaces

07.1

(3 x AO2) 2. Must be at least 3

bands shown

3. Correct label of one tissue;

3. Accept

(upper/lower)

epidermis/palisade

mesophyll/spongy

mesophyll/

vascular bundle/

xylem/phloem

3. Accept cells for

mesophyll

3. Reject stoma

3. Reject waxy cuticle

3. Reject cell

1. SDs do not overlap for (mean) shelf life

OR

SDs do not overlap for (mean) transpiration

rate

OR

2. Accept converse for

SDs do overlap for (mean) number of stomata; December

2. Shelf life significantly longer/different in April; 2. 3. and 4. Accept

equivalent statements

4 to significance in

3. No significant difference in (mean) number of

07.2 terms of chance, e.g.

stomata so unlikely/not linked to shelf life; (4 x AO3)

for 4. ‘difference in

(mean) transpiration

4. Significant difference in (mean) transpiration rate is not due to

rate so (likely) linked with shelf life; chance…’

If no marks awarded,

allow 1 mark max for

(mean) transpiration

rate affects shelf life

Mark in groups of either 1., 2. and 3. OR 4., 5.

and 6.

1. Accept a

1. Reduce light intensity; description of

reducing light

2. Stomata close;

intensity, e.g. use a

3. (So) decreased (rate of) cupboard OR turn

evaporation/transpiration; off lights

4. Increase humidity 3 max

07.3 4. Accept description

(3 x AO3) of reducing air

OR

movement e.g.

Prevent/reduce air movement (around cut close windows

flowers);

5. Accept Ψ symbol

5. Reduces water potential gradient (between for water potential

plant and air);

6. (So) decreased (rate of)

evaporation/transpiration;

How to answer it

Leaf Tissues, Transpiration, and Plant Shelf Life

What this question tests

This sequence assesses your ability to interpret biological drawings and photomicrographs of leaf cross-sections, analyze experimental data involving standard deviations to draw valid conclusions, and apply your knowledge of transpiration factors to control the environmental conditions of cut flowers.

Question 0.7.1 [3 marks]

Biological Drawing of a Leaf Section

✅ Correct Answers

  • Four continuous bands drawn: Upper epidermis, palisade mesophyll, spongy mesophyll, and lower epidermis.
  • Proportional representation: Band widths must closely match the relative proportions seen in Figure 8.
  • Clear labeling: One correct tissue correctly identified (e.g., palisade mesophyll, spongy mesophyll, xylem, phloem, upper/lower epidermis).

💡 Key Knowledge

  • Biological drawings of tissues must never show individual cells unless explicitly requested.
  • Lines must be continuous, thin, sharp, and drawn with a single sweep (no sketching or overlapping lines).
  • Tissues are organized in distinct layers within a Dicotyledonous leaf cross-section.

🧠 Exam Technique

Examiners look for distinct structural layers. Ensure you draw at least 3 distinct bands corresponding to the anatomical features visible in the photomicrograph. Do not waste time drawing individual cells!

❌ Common Errors

  • Drawing individual cells (automatic penalty).
  • Using sketched, hairy, or overlapping lines.
  • Attempting to label individual stomata or waxy cuticles instead of whole tissues.
Question 0.7.2 [4 marks]

Data Analysis: Interpreting Standard Deviations and Conclusions

✅ Correct Answers (Mark Scheme Breakdown)

  • Point 1: Standard deviations (SD) do not overlap for mean shelf life (or mean transpiration rate).
  • Point 2: Shelf life is significantly longer/different in April (16 days vs 5 days in December).
  • Point 3: Standard deviations do overlap for mean number of stomata, indicating no significant difference/no link to shelf life.
  • Point 4: Significant difference in mean transpiration rate means it is likely linked to shelf life.

💡 Key Knowledge

When data sets have overlapping ranges defined by standard deviations (or ±2 SD values representing 95% of data), differences between means are generally not statistically significant. Non-overlapping standard deviations strongly imply a significant difference.

🧠 Exam Technique

Always check the ± values in tables first. When asked what you can conclude, structure your answer by systematically addressing: (1) what the statistical test/SD shows, (2) the direct trend in the data, and (3) linking variables (stomata vs transpiration rate) to shelf life.

❌ Common Errors

  • Vaguely stating "there is a correlation" without mentioning standard deviations or significance.
  • Claiming the number of stomata affects shelf life, missing the fact that their SD values overlap significantly.
Question 0.7.3 [3 marks]

Controlling Environmental Conditions to Extend Shelf Life

✅ Correct Answers (Choose one valid pathway)

  • Pathway A (Light): Reduce light intensity → Stomata close → Decreased rate of evaporation/transpiration.
  • Pathway B (Humidity/Air Flow): Increase humidity OR reduce air movement → Reduces water potential gradient between plant and air → Decreased rate of evaporation/transpiration.

💡 Key Knowledge

Cut flowers lose water via transpiration through their stomata. Minimizing water loss keeps cells turgid and extends shelf life. Factors decreasing transpiration include higher humidity, lower light intensity, and less wind/air flow.

🧠 Exam Technique

This is a multi-step causal question requiring 3 clear marks: (1) The environmental change (e.g., reduce light or increase humidity), (2) The physiological mechanism (e.g., stomata close or water potential gradient reduced), and (3) The ultimate effect (reduced transpiration/water loss).

❌ Common Errors

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  • Mentioning temperature changes, which was explicitly forbidden by the question stem.
  • Failing to link the environmental change to a mechanism (e.g., just saying "put them in the dark" without explaining that stomata close).

Topics

Biology · Practical skills · Required Practicals · 3.3 Organisms exchange substances with their environment · Data analysis · AS practicals (1–6)

Question and mark scheme from the AQA AS Level Biology examination, Paper 2, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.