AQA AS Level Biology Paper 1, June 2025: Question 1
6 marks · Medium difficulty · Short Answer
Identify amino acid functional groups, bond type, dipeptide components, and calculate the number of amino acids in an antibody heavy chain using a given ratio.
Practise this questionQuestion
Question text
01.1 Figure 1 shows the structure of the amino acid alanine.
Figure 1
Name the NH2 and COOH groups in the amino acid.
[1 mark]
NH2
COOH
Figure 2 shows the molecule formed from alanine and another amino acid.
Figure 2
01.2 Name the type of bond and the type of molecule formed when the two amino acids in
Figure 2 are joined.
[2 marks]
Type of bond
Type of molecule 3
01.3 Table 1 shows the R groups of six different amino acids.
Table 1
Amino acid R group Amino acid R group
Alanine CH3 Glycine H
Aspartic acid CH2COOH Serine CH2OH
Glutamine (CH2)2CONH2 Valine CH(CH3)2
Use the information in Table 1 to identify the amino acid joined to alanine in
*02Figure 2*.
[1 mark]
01.4 Figure 3 represents the structure of an antibody.
Figure 3
The total number of amino acids in a particular antibody molecule is 1322
The ratio of amino acids in the heavy chains to the amino acids in the light chains is
2.13 : 1
Calculate how many amino acids there are in one heavy chain.
Give your answer to the nearest whole number.
[2 marks]
amino acids
Mark scheme
Show the mark scheme
Question Marking Guidance Mark Comments
NH2 = amine Accept ‘amino’
and 1
01.1 (1 x
COOH = carboxyl; AO1) Accept ‘carboxylic
acid/group’
Both required for 1 mark.
1. (Type of bond) peptide; 2 Answers must be on
01.2 (2 x the correct lines
2. (Type of molecule) dipeptide; AO1)
Serine; 1
01.3 (1 x
AO2)
Correct answer of 450 = 2 marks;; Reject answer of
899.6 (two errors)
449.8 = 1 mark (correct calculation for one heavy
chain but not rounded to nearest whole number) 2
01.4 (2 x
OR AO2)
900 = 1 mark (incorrectly calculated for two heavy
chains but rounded to nearest whole number);
How to answer it
Amino Acids, Peptide Formation & Antibody Structure
What this question tests
This question evaluates core A-Level foundation knowledge on protein biochemistry and quaternary protein structure:
- Identification of functional groups in a generalised amino acid monomer (amine and carboxyl groups).
- Naming the specific covalent bond and resultant condensation product formed between two amino acids.
- Pattern matching and identifying variable R-groups from structural formulae.
- Applying mathematical ratio calculations to quaternary protein structures (specifically, an antibody consisting of 2 heavy and 2 light polypeptide chains).
Functional Groups of an Amino Acid
Identifying the NH₂ and COOH functional groups in alanine
✅ Correct Answer
- NH₂: amine (accept 'amino')
- COOH: carboxyl (accept 'carboxylic acid' or 'carboxylic group')
💡 Key Knowledge
Every amino acid shares an identical backbone attached to a central alpha-carbon (C):
- A basic amine group (-NH₂)
- An acidic carboxyl group (-COOH)
- A single hydrogen atom (-H)
- A variable side-chain: the R group (which in alanine is a methyl group, -CH₃)
🧠 Exam Technique
Spell biochemical functional groups accurately. Ensure you do not confuse the organic chemistry functional group name with related terms like "ammonia" or "amide".
❌ Common Errors
- Writing ammonia or ammonium instead of amine.
- Writing carbon, carbonyl, or hydroxide instead of carboxyl.
- Getting only one correct: no partial credit (0.5 marks) exists here.
Condensation Product & Bond Formation
Naming the bond and the molecule formed between two amino acids
✅ Correct Answer
- Type of bond: peptide [1 mark]
- Type of molecule: dipeptide [1 mark]
💡 Key Knowledge
A condensation reaction between the carboxyl group of one amino acid and the amine group of another results in the loss of a water molecule (H₂O) and the formation of a peptide bond ( -CO-NH- ). Joining two amino acids produces a dipeptide.
🧠 Exam Technique
Pay attention to the prompt labels: answers must be on the designated answer lines. Do not write "peptide" under molecule and "dipeptide" under bond, or both marks are forfeited.
❌ Common Errors
- Writing polypeptide or protein instead of dipeptide (the question specifies that only two amino acids are joined).
- Writing hydrogen bond or glycosidic bond for the bond type.
Identifying Amino Acids from R Groups
Using structural comparison with Table 1
✅ Correct Answer
Serine [1 mark]
💡 Key Knowledge
Figure 2 shows the dipeptide with the backbone:
H₂N-CH(CH₃)-CO-NH-CH(CH₂OH)-COOH
- First amino acid alpha-carbon carries -CH₃ (Alanine).
- Second amino acid alpha-carbon carries -CH₂OH .
- Matching -CH₂OH against Table 1 gives Serine.
🧠 Exam Technique
Locate the peptide link ( -CO-NH- ) first. Look immediately to the right at the adjacent alpha-carbon (C) and isolate the group branching downwards.
❌ Common Errors
- Misreading -CH₂OH as -CH₂COOH (Aspartic acid).
- Writing the formula of the R-group instead of the name of the amino acid requested by the prompt.
Quantitative Quaternary Structure: Antibody Ratio Calculation
Calculating the number of amino acids in ONE heavy chain
✅ Correct Answer
450 [2 marks]
- 449.8 (correct calculation for one heavy chain, but forgot to round to nearest whole number).
- 900 (correctly rounded, but calculated for both heavy chains combined, failing to divide by 2).
📐 Step-by-Step Calculation
1 Find total ratio parts:
Ratio of (all heavy chains) : (all light chains) = 2.13 : 1
Total parts = 2.13 + 1 = 3.13
2 Calculate amino acids in BOTH heavy chains:
Amino acids in heavy chains = (2.13 / 3.13) × 1322 = 899.642...
3 Divide by 2 for ONE heavy chain:
An antibody contains 2 heavy chains (shown clearly in Figure 3).
Amino acids in one heavy chain = 899.642... ÷ 2 = 449.821...
4 Round to nearest whole number:
449.821... rounds to 450.
❌ Common Errors & Examiner Traps
- Stopping at 900: Forgetting that an antibody has two heavy chains. The question asks for one heavy chain.
- Leaving answer as 449.8: Overlooking the instruction: "Give your answer to the nearest whole number."
- Answer of 899.6: Fails to divide by 2 AND fails to round (Mark scheme explicitly notes: "Reject answer of 899.6 (two errors) = 0 marks").
- Incorrect ratio division: Dividing 1322 by 2.13 instead of using part-to-whole (dividing by 3.13).
🧠 Exam Technique: Checking Biological Sense
Always look at the structural diagram provided. Figure 3 illustrates an antibody's characteristic Y-shape consisting of 4 polypeptide chains: 2 identical heavy chains in the centre and 2 shorter light chains on the outside. Always underline words like "one", "both", and rounding requirements.
Topics
Biology · 3.1 Biological molecules · 3.2 Cells
Question and mark scheme from the AQA AS Level Biology examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.