AQA AS Level Biology Paper 1, June 2025: Question 7
9 marks · Medium difficulty · Extended Answer
Identify the carbohydrate transported in phloem, explain features of starch as a storage molecule, and evaluate experimental data on the mass flow hypothesis.
Practise this questionQuestion
Question text
07.1 Name the main carbohydrate transported through the phloem.
[1 mark]
07.2 In the storage tissues of plants, carbohydrates transported through the phloem can be
converted into starch.
Explain three features of starch that make it a good storage molecule.
[3 marks]
Scientists investigated the mass flow hypothesis in geranium plants.
The scientists:
• separated the phloem from the xylem in a part of the stem by placing an
impermeable layer between them
• enclosed a leaf above the separated section, and supplied it with radioactive carbon
dioxide (14CO )
• illuminated the plant for 15 hours
• cut the stem into sections as shown in Figure 9
• measured the radioactivity in the phloem and xylem of each section.
Figure 9
Table 4 shows the scientists’ results.
Table 4
Section of Radioactivity in phloem / Radioactivity in xylem /
tissue counts per minute counts per minute
A 41 100 24 210
B 2 761 755
C 130 74
D 101 47
E 15719 75
07.3 The total radioactivity of the phloem and xylem tissues shown in Table 4 was lower
than the total radioactivity absorbed by the enclosed leaf.
*18Suggest* one reason why.
[1 mark]
07.4 The mass flow hypothesis states that organic substances are transported through the
phloem, from leaves to all parts of plants.
Evaluate whether the information from this investigation supports this hypothesis.
Do not refer to statistical tests or sample size in your answer.
[4 marks]
Mark scheme
Show the mark scheme
Question Marking Guidance Mark Comments
Sucrose; 1
07.1 (1 x
AO1)
1. Insoluble (in water), so doesn’t affect water 1. Accept Ψ for water
potential/osmosis; potential
2. Coiled/spiral/(α-)helix, so compact
OR
Coiled/spiral/(α-)helix so can fit many 3 max
07.2 (molecules) in small area; (3 x
AO1)
3. Many (α-)glucose for respiration;
4. Branched/more ends so fast 4. Ignore surface area
breakdown/hydrolysis; 4. Accept branched
so glucose readily
5. Large (molecule), so can’t leave the cell; released
1. Some sugars converted to cellulose/starch; 1, 2, 3 and 4. Accept
‘organic substance’
2. Some sugars used in respiration; for sugars or any
1 max suitably named
07.3 3. Some sugars not moved down; (1 x organic substance for
AO2) sugars, e.g. glucose
4. Some sugars moved further down than E;
3. Accept some
sugars remain in the
leaf
(In support of mass flow hypothesis)
1. Radioactivity is higher in phloem than xylem;
2. Radioactivity found in sections below leaf so
it moved down stem/plant;
3. Accept leaf
3. Leaf is source produces any named
organic substance
OR
Leaf produces organic substances;
12 4 max
07.4 (Against mass flow hypothesis – max 3) (4 x
AO3)
4. Some radioactivity present in xylem;
5. Only tested in one species
OR
Only tested in geraniums;
6. No evidence for transport above the leaf; 6. Accept other
leaves/fruit/flowers
7. Movement could be due to gravity;
How to answer it
Transport in Plants: Phloem Function & Mass Flow Hypothesis
This question examines core concepts across Biological Molecules (carbohydrate structure and function) and Exchange & Transport (translocation via phloem and the mass flow hypothesis).
- Biochemical Identification: Identifying the soluble transport sugar in flowering plants.
- Structure-to-Function Explanation: Linking specific molecular features of starch to its role as an efficient cellular storage polymer.
- Tracer Experiment Interpretation: Explaining metabolic fates of photosynthetically fixed ¹⁴C.
- Scientific Evaluation (AO3): Formulating balanced arguments for and against a hypothesis based strictly on experimental data, avoiding forbidden evaluation clichés.
Name the Translocated Carbohydrate
Name the main carbohydrate transported through the phloem.
✅ Correct Answer
Sucrose
💡 Key Knowledge
- Why sucrose? Glucose produced in photosynthesis is converted into sucrose because sucrose is a non-reducing disaccharide. It is chemically less reactive and less likely to be metabolised during mass flow transport.
- Starch is completely insoluble and cannot enter or flow through sieve tube elements.
❌ Common Errors
- Writing glucose (glucose is produced during photosynthesis, but translocated as sucrose).
- Writing starch (insoluble storage form, not transport form).
Adaptations of Starch as a Storage Molecule
Explain three features of starch that make it a good storage molecule.
✅ Correct Points (Any Three)
- Insoluble (in water): so does not affect water potential (Ψ) / no osmotic movement into cells.
- Coiled / helical / spiral: so it is compact / packs many molecules into a small volume.
- Branched / has many ends: allows rapid hydrolysis by enzymes to quickly release glucose.
- Polymer of α-glucose: provides readily accessible glucose units for cellular respiration.
- Large molecule: cannot cross the cell-surface membrane / cannot leave the cell.
🧠 Exam Technique: "Feature + Consequence"
Because this question asks you to explain, writing down the feature alone scores 0 marks. You must supply the biological reason using conjunctions like "so" or "because":
- "Insoluble..." → "...so no osmotic effect / doesn't alter water potential."
- "Branched..." → "...so enzymes can act simultaneously on multiple ends for rapid release."
❌ Common Errors
- Writing "it has a large surface area" for branching — examiners explicitly ignore surface area here. Focus on more ends for enzyme action.
- Writing "it is insoluble" without stating its osmotic consequence.
- Stating starch is used directly in respiration (only glucose monomers enter glycolysis).
Discrepancy in Radioactive Counts
Suggest one reason why the total radioactivity in the stem was lower than that absorbed by the leaf.
✅ Correct Suggestions (Any One)
- Some ¹⁴C-sugars were respired by the leaf/plant cells (released as ¹⁴CO₂ gas).
- Some sugars were converted into other molecules (e.g. starch storage or cellulose cell walls) within the leaf.
- Some sugars remained in the leaf and were not translocated downwards during the 15-hour period.
- Some sugars were translocated past section E (into roots) or moved upwards toward shoot tips/buds.
💡 Biological Context
Leaves act as photosynthetic sources. Not 100% of newly fixed triose phosphate is exported into the phloem immediately. The leaf itself requires energy (ATP via respiration) and structural/storage polysaccharides.
❌ Common Errors
- Vague assertions like "it was lost" without specifying a biological destination or process (e.g. respiration, synthesis of starch/cellulose).
- Assuming radioactive decay occurred (carbon-14 has a half-life over 5,700 years; decay does not explain loss over 15 hours).
Evaluating the Mass Flow Hypothesis
Evaluate whether the information from this investigation supports the mass flow hypothesis. Do not refer to statistical tests or sample size.
✅ Arguments In Support (Evidence For)
- Phloem concentration is higher: Radioactivity is significantly higher in phloem than xylem across all sections (e.g. Section A: 41,100 vs 24,210 cpm).
- Downward movement from source: Radioactivity is present in sections B, C, D, and E below the supplied leaf, showing downward translocation away from the source.
- Source role confirmed: Shows the leaf synthesises and exports organic compounds into vascular tissue.
❌ Arguments Against / Limitations (Evidence Against)
- Radioactivity detected in xylem: Notable counts exist in the xylem (e.g. 24,210 in A, 755 in B), indicating transport is not exclusively restricted to phloem.
- Single species tested: Investigation used only geranium plants; results might not apply to all plant species.
- No evidence of upward transport: Mass flow states transport occurs to all parts of the plant, but this setup only tested sections below the leaf (none above towards apical buds/flowers).
- Downward movement could be gravity: The observed flow downwards could be passively influenced by gravity rather than driven by hydrostatic pressure gradients.
🧠 Exam Technique: Structuring an "Evaluate" Answer
- Balance is mandatory: You must state points supporting AND points conflicting with the hypothesis. Notice the mark scheme caps points against at max 3 marks, meaning you cannot achieve 4/4 without at least one supporting point!
- Follow negative constraints: The prompt explicitly commands: "Do not refer to statistical tests or sample size". Mentioning "no standard deviations", "no stats test", or "only one plant tested" (as sample size) scores 0 marks.
- Note: Mentioning "only tested in geraniums / one species" is valid because it addresses phylogenetic generalisability, not numerical sample size.
❌ Common Traps
- Forgetting to check the xylem columns in Table 4 (assuming all counts were in phloem).
- Wasting time writing: "There are no error bars so we don't know if differences are significant" — explicitly disqualified by the question prompt.
Topics
Biology · Practical skills · 3.1 Biological molecules · 3.3 Organisms exchange substances with their environment · Data analysis
Question and mark scheme from the AQA AS Level Biology examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.