AQA AS Level Mathematics Paper 1, June 2025: Question 12
3 marks · Easy difficulty · Multi-step Problem
Use the factorial definition of combinations to find an unknown value in a factorial expression and evaluate the ratio of two consecutive combinations.
Practise this questionQuestion
Question text
12 (a) It is given that
40 40!
C18 =
18!p!
Write down the value of p
[1 mark]
12 (b) Use the result from part (a) to show that
C18 23
40 =
C17 q
where q is an integer to be found.
[2 marks]
Mark scheme
Show the mark scheme
Q Marking instructions AO Marks Typical solution
12(a) Writes 22 1.1b B1 22
Subtotal 1
12(b) Sets up correct factorial 3.1a M1 40! 40! 40! 17 23!!
expressions as part of a division ÷ = ×
18 22!! 17 23!! 18 22!! 40!
or multiplication
17 23!!
Completes a reasoned 1.1b R1 =
23 18 22!!
argument to obtain 23
18 =
Subtotal 2
How to answer it
Binomial Coefficients & Factorial Notation
This question assesses your foundational understanding of the formal factorial definition of the combination formula ⁿCᵣ and your algebraic skill in simplifying ratios of factorials without relying on a calculator.
- The definition: ⁿCᵣ = n! / (r!(n - r)!)
- Division of algebraic fractions involving factorials
- Factorial cancellation rules: n! = n × (n - 1)!
Question 12 (a)
Finding the unknown value in a factorial combination formula [1 Mark]
💡 Key Knowledge
The standard formula for combinations is:
ⁿCᵣ = n! / (r!(n - r)!)
Comparing ⁴⁰C₁₈ = 40! / (18! p!) directly with the formula:
- n = 40
- r = 18
- p = n - r = 40 - 18
📐 Calculation
- Identify the formula component: p = 40 - 18
- Subtract to find p: p = 22
✅ Correct Answer
p = 22
❌ Common Errors
- Writing 22! instead of 22. The question states p! , so p = 22 .
- Arithmetic slip when calculating 40 - 18 (e.g. obtaining 32 or 28).
Question 12 (b)
Simplifying a ratio of consecutive binomial coefficients [2 Marks]
💡 Key Knowledge
To divide fractions, multiply by the reciprocal:
(A / B) ÷ (C / D) = (A / B) × (D / C)
Unpack factorials using their recursive property:
- 23! = 23 × 22!, so 23! / 22! = 23
- 18! = 18 × 17!, so 17! / 18! = 1 / 18
🧠 Exam Technique: "Show that" Proofs
Because the numerator 23 is already given in the question, you must show full, convincing algebraic working:
- Write out both expressions fully using factorials.
- Invert the second fraction and multiply.
- Explicitly show the cancellation of 40! and how 23!/22! reduces to 23 and 17!/18! reduces to 18.
- State the final integer: q = 18.
📐 Step-by-Step Calculation
- Set up the expressions using the formula:
⁴⁰C₁₈ = 40! / (18! 22!)
⁴⁰C₁₇ = 40! / (17! (40 - 17)!) = 40! / (17! 23!) - Set up the division and change to multiplication:
⁴⁰C₁₈ / ⁴⁰C₁₇ = (40! / (18! 22!)) ÷ (40! / (17! 23!))
= (40! / (18! 22!)) × ((17! 23!) / 40!) - Cancel common terms:
Cancel 40!: = (17! 23!) / (18! 22!)
Expand the larger factorials: = (17! × 23 × 22!) / (18 × 17! × 22!) - Simplify the fraction:
= 23 / 18 - Identify the integer q:
Comparing 23 / 18 to 23 / q gives q = 18.
✅ Final Solution & Marks
⁴⁰C₁₈ / ⁴⁰C₁₇ = 23 / 18 ⇒ q = 18
R1 (1.1b): Completes a reasoned argument to obtain 23/18 (or explicitly writes q = 18).
❌ Common Errors
- Using a calculator directly: Evaluating ⁴⁰C₁₈ and ⁴⁰C₁₇ as huge decimal numbers or integers scores 0 marks. The command word is "Use the result from part (a) to show that...".
- Jumping steps: Writing the initial fraction and immediately jumping to 23/18 without showing the cancellation of factorials loses the reasoning mark (R1).
- Forgetting to identify q: Always conclude by making sure your answer explicitly matches the requested form.
Topics
Pure Mathematics · D: Sequences and series
Question and mark scheme from the AQA AS Level Mathematics examination, Paper 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.