AQA AS Level Mathematics Paper 2, June 2025: Question 3
4 marks · Medium difficulty · Multi-step Problem
Find the size of the obtuse angle CAB of a triangular prism's cross-section given side lengths 6 cm and 10 cm, prism length 20 cm, and volume 500 cm³.
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Question text
3 ABC is the cross‑section of a triangular prism.
The length of AB is 6 cm and the length of AC is 10 cm as shown in the diagram.
A
6cm 10cm
B C
The prism has length 20 cm and volume 500 cm3
Find the size of the obtuse angle CAB
Give your answer to the nearest degree.
[4 marks]
Mark scheme
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Q Marking instructions AO Marks Typical solution
3 Multiplies the area of their 1.1a M1 500
Area of triangle = = 25
triangle by 20 and equates to 20
500 1
5 ×10×6×sinA =25
PI by 25 or sinA = 2
1 sinA =
Uses absin C with 6 and 10 1.1b B1 6
sin A A = 56 4.°
PI by 30
obtuse angle = 180 − 56 4.
Solves equation of the form 1.1a M1 = 124°
sinA = k 0 < k < 1
Obtains AWRT 124° 3.2a A1
Question 3 Total 4
How to answer it
Trigonometry: Cross-Sectional Area & Obtuse Angles
Core AS-Level Pure Mathematics Skills:
- Volume of a Prism: Linking total volume, uniform cross-sectional area, and length ( Volume = Area × Length ).
- Area of a Triangle: Applying the non-right-angled triangle formula Area = ½ab sin(C) using two sides and an included angle.
- Trigonometric Equations: Solving sin(θ) = k for values in the range 0° to 180°.
- Obtuse Angles: Recognising that sin(θ) = sin(180° - θ) to find the obtuse second quadrant solution.
Question 3 Walkthrough (4 Marks)
AQA AS Mathematics — Pure Core
📐 Step-by-Step Calculation
- Calculate the cross-sectional area of triangle ABC:
Since Volume = Area of cross-section × Length:
500 = Area × 20
Area = 500 / 20 = 25 cm² - Set up the triangle area formula with the given sides:
The sides enclosing angle CAB are AB = 6 cm and AC = 10 cm.
Area = ½ × AB × AC × sin(CAB)
25 = ½ × 6 × 10 × sin(CAB)
25 = 30 sin(CAB) - Solve for sin(CAB):
sin(CAB) = 25 / 30 = 5/6 ≈ 0.8333 - Find the acute reference angle:
CAB = arcsin(5/6) ≈ 56.4427° - Calculate the obtuse angle and round appropriately:
Because angle CAB is specified as obtuse (90° < CAB < 180°):
CAB = 180° - 56.4427° = 123.5573°
Rounding to the nearest degree gives:
CAB = 124°
✅ Final Answer
Angle CAB = 124°
Must be rounded to the nearest whole degree as instructed in the question.
💡 Key Knowledge
- Sine Area Rule: Requires the angle to be strictly between the two known sides (included angle).
- Symmetry of Sine: For any angle θ between 0° and 180°, sin(θ) = sin(180° - θ) . Your calculator always defaults to the acute value when you input arcsin .
🧠 Exam Technique & Mark Breakdown
❌ Common Examiner Traps
- Stopping at the Acute Angle: Students write 56° or 56.4° and stop, completely missing the explicit word "obtuse" in the question. This loses the final accuracy mark.
- Premature Rounding: Rounding 56.44° to 56° first, then doing 180 - 56 = 124° happens to yield 124° here, but rounding early often causes intermediate calculation errors in multi-step questions. Keep unrounded figures stored in your calculator!
- Radian Mode: Ensure your calculator displays a 'D' at the top, not 'R', before starting trigonometry questions requiring degree answers.
Topics
Pure Mathematics · E: Trigonometry
Question and mark scheme from the AQA AS Level Mathematics examination, Paper 2, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.