AQA AS Level Physics Paper 1, June 2019: Question 5

9 marks · Medium difficulty · Short Answer

Determine the readings on force meters supporting a uniform ruler, analyze whether the forces form a couple, and calculate an added weight and its position using the principle of moments.

Practise this question

Question

A physics exam question about moments consisting of four parts. Figure 8 shows a 100 cm horizontal ruler suspended by two vertical force meters A and B, each attached 12.0 cm from the ends. Figure 9 shows an additional mass W hanging from the ruler between A and B at a distance d from A. Parts 05.1, 05.2, 05.3, and 05.4 require calculations and discussions based on these experimental setups.
Question text

05 A student investigates moments by suspending a 100 cm ruler from two force meters,

A and B. A and B are attached to the ruler 12.0 cm from each end. Their supports

are adjusted to make A and B vertical and the ruler horizontal.

Figure 8 is a simplified diagram of the experiment.

Figure 8

05.1 The ruler is uniform and weighs 1.12 N.

Determine the reading on A.

[1 mark]

reading = N

05.2 The student suggests that the forces exerted on the ruler by A and B act as a couple.

Discuss whether his suggestion is correct.

[2 marks]

05.3 The student hangs a mass of weight W on the ruler between A and B, as shown in

Figure 9.

*18* He adjusts the supports so that A and B are again vertical and the ruler is horizontal.

The mass hangs at a distance d from A.

Figure 9

The reading on A is 0.82 N and the reading on B is 0.62 N.

Determine

• W

• d.

[4 marks]

W = N

20 d = m

05.4 A second student sets up the same apparatus as shown in Figure 9.

She suspends the mass in the same position on the ruler as in question 05.3.

She moves the supports to make A and B vertical but does not make the ruler

horizontal.

*19* Discuss whether the readings on A and B taken by this student are different to those

in question 05.3.

[2 marks]

Mark scheme

Show the mark scheme A mark scheme table detailing answers and guidance for questions 05.1 to 05.4. Question 05.1 expects 0.56 N (1 mark). Question 05.2 requires discussing the definition of a couple (2 marks). Question 05.3 involves calculating W as 0.32 N and d as 0.14 m using equilibrium and moments (4 marks). Question 05.4 discusses whether readings change if the ruler is not horizontal (2 marks).

Question Answers Additional Comments/Guidance Mark

details

05.1 0.56 (N) 1 AO2.1h

Definition of couple as two equal forces acting in opposite Moment of a couple is independent of the point

directions about which moments are taken

05.2 2 AO2.1c

Forces (are equal but) don’t act in opposite directions, Combined moment of the two forces depends

therefore it is not correct on the point about which moments are taken,

therefore not correct.

Use of total upward force = total downward force 1 mark for any attempt to equate upward and

eg 0.87 + 0.62 = 1.12 + W downward forces. Response may be on

diagram.

0.32 (N)

05.3 4 AO2.1d

Attempt to use Principle of Moments

0.14 (m) Allow MP4 if (their W) × (their d) = 0.0448

Readings (on A and B) would be the same/1.44 (N)

(Because) total downwards force/weight is same

05.4 AO3.1b

OR 2

All (perpendicular) distances affected by the same factor

(cos θ)

Total 9

How to answer it

Moments, Equilibrium and Couples

What this question tests

This question assesses your understanding of the conditions for static equilibrium (the principle of moments and resolution of vertical forces), the definition and properties of a couple, and how non-horizontal orientation affects perpendicular distances in balancing problems.

Question 05.1

Uniform Ruler Equilibrium

✅ Correct Answer

0.56 N (or half the total weight since the system is symmetrical)

📐 Calculation Steps

  1. Recognise that because the meter rule is uniform and supported symmetrically at 12.0 cm from each end, forces A and B share the total weight equally.
  2. Calculation: Total weight = 1.12 N. Reading on A = 1.12 / 2 = 0.56 N .
Marks: 1 mark for AO2.1h
Question 05.2

Evaluating a "Couple" Suggestion

✅ Correct Answer

The student's suggestion is incorrect. Although forces A and B are equal in magnitude, they act in the same direction (upwards), whereas a couple requires two equal, parallel forces acting in opposite directions.

💡 Key Knowledge

  • Definition of a couple: A pair of equal and opposite coplanar forces.
  • A couple produces rotation without translation, and its moment is independent of the pivot point. Forces A and B here combine to cause translational equilibrium (balancing total downward weight).

❌ Common Errors

Students often mistake any pair of equal forces in a setup for a couple, forgetting the strict requirement that they must act in opposite directions.

Marks: 2 marks (1 for correct definition/property of a couple, 1 for stating why forces A and B do not form one).
Question 05.3

Finding Suspended Weight W and Distance d

✅ Correct Answer

W = 0.32 N and d = 0.14 m (or 14 cm)

📐 Step-by-Step Calculation

  1. Find W using resolution of vertical forces:
    Total upward force = Total downward force
    Reading A + Reading B = Weight of ruler + W
    0.82 + 0.62 = 1.12 + W
    1.44 = 1.12 + W  ⇒  W = 0.32 N
  2. Find distance d using the Principle of Moments:
    Take moments about the pivot point at support A to eliminate unknown reaction forces:
    Clockwise moments = Anticlockwise moments
    (W × d) + (Weight of ruler × distance from A to center of mass)
    *Note: Ruler is 100 cm long. Support A is at 12.0 cm. Center of mass is at 50.0 cm.*
    Distance from A to center of mass = 50.0 - 12.0 = 38.0 cm (0.38 m).
    Anticlockwise moment about A = Support B force × distance from A to B.
    Distance from A to B = 100.0 - 12.0 (left end offset) - 12.0 (right end offset) = 76.0 cm (0.76 m).
  3. Set up moment equation about A:
    (W × d) + (1.12 × 0.38) = 0.62 × 0.76
    (0.32 × d) + 0.4256 = 0.4712
    0.32 × d = 0.0456  ⇒  d = 0.1425 m ≈ 0.14 m

🧠 Exam Technique

Always take moments about a point where an unknown force acts (like support A) to eliminate it from your calculations. Make sure to convert all centimeter distances into meters consistently to avoid powers-of-ten errors.

Marks: 4 marks total (1 for vertical force balance, 1 for value of W, 1 for attempt at moments, 1 for value of d).
Question 05.4

Non-Horizontal Ruler Discussion

✅ Correct Answer

The readings on A and B would be different from question 05.3 (specifically, they would each be 0.72 N, totaling 1.44 N).

💡 Key Knowledge

  • The total downward force (weight of ruler + W) remains constant at 1.44 N. Therefore, the sum of the vertical upward forces must still equal 1.44 N.
  • Because the mass is in the exact same position relative to the ruler, the symmetry of the total downward load distribution means supports A and B will share the 1.44 N load equally if the new angle changes perpendicular distances by the same scaling factor (cos θ).

❌ Common Errors

Many students incorrectly assume that tilting the ruler changes the total weight acting downwards or alters the reaction forces unpredictably, forgetting that translational equilibrium in the vertical plane (ΣF = 0) still strictly applies.

Marks: 2 marks (1 for stating readings change to 1.44 N split equally / 0.72 N each, 1 for explaining total downward force remains unchanged).

Topics

Physics · 3.4 Mechanics and materials

Question and mark scheme from the AQA AS Level Physics examination, Paper 1, June 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.