AQA AS Level Physics Paper 2, November 2021: Question 31
1 mark · Medium difficulty · Multiple Choice
Determine the current supplied by a 12 V battery connected in parallel to two components whose current-voltage characteristics are shown on the graph.
Practise this questionQuestion
Question text
31 The graph shows the current–voltage (I–V) characteristics for two components.
The two components are connected in parallel with a 12 V battery that has negligible
internal resistance.
What is the current in the battery?
[1 mark]
A 7.9 mA
B 14.5 mA
C 15.8 mA
D 23.0 mA
Mark scheme
Show the mark scheme
31 D 23.0 mA
How to answer it
Question 3.1: Current-Voltage Characteristics
This question assesses your understanding of parallel circuits, Kirchhoff's First Law (conservation of charge), internal resistance, and how to interpret current-voltage (I-V) characteristic graphs for non-ohmic components.
Question Part 3.1
Multiple Choice Component [1 mark]
✅ Correct Answer
D: 23.0 mA
💡 Key Knowledge
- Parallel Circuits: Components connected in parallel across an ideal power supply (negligible internal resistance) share the same potential difference equal to the supply emf ( 12 V ).
- Kirchhoff's First Law: The total current leaving the battery equals the sum of the currents flowing through each parallel branch ( I_total = I_1 + I_2 ).
- Graph Reading: Find the current value on the y-axis corresponding to V = 12 V for both characteristic curves.
🧠 Exam Technique
- Locate 12 V on the horizontal x-axis.
- Trace vertically up to intersect both the solid curve and the dashed curve.
- Read across to the vertical y-axis to find the current for each component at 12 V .
- Sum the two current values carefully, paying attention to the unit scale.
📐 Step-by-Step Calculation
- Identify supply voltage: V = 12 V
- Read current for component 1 (solid line at 12 V): 14.0 mA
- Read current for component 2 (dashed line at 12 V): 9.0 mA
- Apply parallel current rule:
I_battery = 14.0 mA + 9.0 mA = 23.0 mA
❌ Common Errors & Traps
- Intersection confusion: Students often incorrectly look at where the two lines cross each other ( ~7 V ) instead of evaluating both components at the battery voltage ( 12 V ). This yields distractor option A ( 7.9 mA ).
- Reading only one component: Forgetting to add the currents together, leading to answers like 14.5 mA (distractor B) or 14.0 mA .
- Scale misinterpretation: Misreading the minor grid squares on the y-axis where each small square represents 0.2 mA .
Topics
Physics · 3.5 Electricity
Question and mark scheme from the AQA AS Level Physics examination, Paper 2, November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.