AQA AS Level Physics Paper 2, November 2021: Question 31

1 mark · Medium difficulty · Multiple Choice

Determine the current supplied by a 12 V battery connected in parallel to two components whose current-voltage characteristics are shown on the graph.

Practise this question

Question

A graph displays current I in mA against voltage V in V for two components, represented by a solid line and a dashed line, with voltage ranging from 0 to 12 V and current up to 15 mA. Below the graph, text states that the two components are connected in parallel with a 12 V battery of negligible internal resistance, and asks for the total current in the battery with four multiple-choice options: A 7.9 mA, B 14.5 mA, C 15.8 mA, and D 23.0 mA.
Question text

31 The graph shows the current–voltage (I–V) characteristics for two components.

The two components are connected in parallel with a 12 V battery that has negligible

internal resistance.

What is the current in the battery?

[1 mark]

A 7.9 mA

B 14.5 mA

C 15.8 mA

D 23.0 mA

Mark scheme

Show the mark scheme The mark scheme indicates that the correct answer for question 31 is D, corresponding to 23.0 mA.

31 D 23.0 mA

How to answer it

Question 3.1: Current-Voltage Characteristics

What this question tests

This question assesses your understanding of parallel circuits, Kirchhoff's First Law (conservation of charge), internal resistance, and how to interpret current-voltage (I-V) characteristic graphs for non-ohmic components.

Question Part 3.1

Multiple Choice Component [1 mark]

✅ Correct Answer

D: 23.0 mA

Mark Awarded: 1 / 1

💡 Key Knowledge

  • Parallel Circuits: Components connected in parallel across an ideal power supply (negligible internal resistance) share the same potential difference equal to the supply emf ( 12 V ).
  • Kirchhoff's First Law: The total current leaving the battery equals the sum of the currents flowing through each parallel branch ( I_total = I_1 + I_2 ).
  • Graph Reading: Find the current value on the y-axis corresponding to V = 12 V for both characteristic curves.

🧠 Exam Technique

  • Locate 12 V on the horizontal x-axis.
  • Trace vertically up to intersect both the solid curve and the dashed curve.
  • Read across to the vertical y-axis to find the current for each component at 12 V .
  • Sum the two current values carefully, paying attention to the unit scale.

📐 Step-by-Step Calculation

  1. Identify supply voltage: V = 12 V
  2. Read current for component 1 (solid line at 12 V): 14.0 mA
  3. Read current for component 2 (dashed line at 12 V): 9.0 mA
  4. Apply parallel current rule:
    I_battery = 14.0 mA + 9.0 mA = 23.0 mA

❌ Common Errors & Traps

  • Intersection confusion: Students often incorrectly look at where the two lines cross each other ( ~7 V ) instead of evaluating both components at the battery voltage ( 12 V ). This yields distractor option A ( 7.9 mA ).
  • Reading only one component: Forgetting to add the currents together, leading to answers like 14.5 mA (distractor B) or 14.0 mA .
  • Scale misinterpretation: Misreading the minor grid squares on the y-axis where each small square represents 0.2 mA .

Topics

Physics · 3.5 Electricity

Question and mark scheme from the AQA AS Level Physics examination, Paper 2, November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.