AQA AS Level Physics Paper 2, November 2021: Question 33
1 mark · Medium difficulty · Multiple Choice
Calculate the percentage uncertainty in the calculated value for the resistivity of a metal wire given percentage uncertainties for potential difference, current, diameter, and length.
Practise this questionQuestion
Question text
33 Measurements are taken to determine the resistivity of a uniform metal wire.
The table shows the quantities measured and their percentage uncertainties.
Quantity Percentage uncertainty
potential difference across wire 0.3%
current in wire 5.0%
diameter of wire 4.0%
length of wire 0.2%
What is the percentage uncertainty in the calculated value for the resistivity of the metal of
the wire?
[1 mark]
A 1.6%
B 9.5%
C 13.5%
D 21.5%
Mark scheme
Show the mark scheme
33 C 13.5%
How to answer it
Question 33: Percentage Uncertainty in Resistivity
What this question tests
This question assesses your ability to combine percentage uncertainties when quantities are multiplied or divided in a physics formula, with a specific focus on handling powers (squared terms) for circular cross-sectional areas.
Determining Uncertainty in Resistivity
✅ Correct Answer
C (13.5%)
💡 Key Knowledge
- The formula for resistivity is ρ = (R × A) / L .
- Since resistance R = V / I , substituting gives ρ = (V × π × d²) / (4 × I × L) .
- Rule for uncertainties: When quantities are multiplied or divided, you add their percentage uncertainties.
- Rule for powers: If a quantity is raised to a power n (like d² ), you must multiply its percentage uncertainty by n (i.e., 2 × % uncertainty of d ).
📐 Step-by-Step Calculation
- Identify formula components and their given percentage uncertainties:
- Potential difference ( V ) = 0.3%
- Current ( I ) = 5.0%
- Diameter ( d ) = 4.0%
- Length ( L ) = 0.2%
- Account for the squared term in area ( A = πd²/4 ):
Uncertainty contribution from diameter = 2 × 4.0% = 8.0% . Note that constants like π and 4 contribute zero uncertainty. - Add all percentage uncertainties together:
% uncertainty in ρ = %V + %I + (2 × %d) + %L
% uncertainty in ρ = 0.3% + 5.0% + 8.0% + 0.2% = 13.5%
❌ Common Errors & Examiner Pitfalls
- Forgetting to multiply the diameter uncertainty by 2: Students who forget this often calculate 0.3 + 5.0 + 4.0 + 0.2 = 9.5% , which incorrectly leads to distractor B.
- Radius vs. Diameter confusion: Some students try to convert diameter to radius and get confused with the factor of 2. Always remember: percentage uncertainty in radius equals percentage uncertainty in diameter ( %uncertainty of r = %uncertainty of d ), but because A = πr² , you still multiply that uncertainty by 2 either way!
Topics
Physics · Practical skills · Required Practicals · 3.1 Measurements and their errors · 3.5 Electricity · Uncertainty and evaluation · AS practicals (1–6)
Question and mark scheme from the AQA AS Level Physics examination, Paper 2, November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.