AQA AS Level Physics Paper 2, June 2024: Question 10
1 mark · Medium difficulty · Multiple Choice
Identify the correct pair of graphs showing the variation of elastic strain energy with extension and tension for a wire obeying Hooke's law.
Practise this questionQuestion
Question text
10 A wire obeys Hooke’s law.
When the wire is extended by ΔL, the elastic strain energy is Es and the tension in the wire
is T.
Which pair of graphs shows the variation of Es with ΔL and the variation of Es with T?
[1 mark]
A
B
C
D
Mark scheme
Show the mark scheme
10 D
How to answer it
Elastic Strain Energy and Hooke's Law Graphs
This question assesses your understanding of the mathematical relationships governing elastic deformation, specifically how elastic strain energy ( E_s ) relates to extension ( ΔL ) and tension ( T ) for a wire obeying Hooke's law.
Question 10
Analyzing Graph Variations for Hooke's Law
✅ Correct Answer: D
Both graphs must show a curved, non-linear relationship (specifically a parabola/power-law curve) passing through the origin.
💡 Key Knowledge
- Hooke's law: T = k ΔL (where k is the spring constant).
- Elastic strain energy is the area under a force-extension graph: E_s = ½ T ΔL .
- Substituting T = k ΔL gives E_s = ½ k (ΔL)² .
- Substituting ΔL = T / k gives E_s = ½ T² / k .
🧠 Exam Technique
Instead of guessing, derive the algebraic equations linking the variables on the axes. Look at the power of the independent variable on the horizontal axis to determine if the graph should be a straight line (power of 1) or a curve (power of 2).
❌ Common Errors
Students frequently fall into the trap of assuming that because tension is directly proportional to extension ( T ∝ ΔL ), energy must also be directly proportional to extension or tension in a linear fashion, leading them to mistakenly choose option A.
📐 Step-by-Step Derivation
- Graph 1 ( E_s vs ΔL ): Since E_s = ½ k (ΔL)² , E_s is proportional to (ΔL)² . This represents a square law relationship, which plots as an upward-curving parabola.
- Graph 2 ( E_s vs T ): Since E_s = ½ T² / k , E_s is proportional to T² . This also represents a square law relationship, yielding an upward-curving parabola.
- Conclusion: Both graphs must be curved, confirming option D as the correct selection.
Topics
Physics · 3.4 Mechanics and materials
Question and mark scheme from the AQA AS Level Physics examination, Paper 2, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.