AQA AS Level Physics Paper 2, June 2025: Question 23
1 mark · Medium difficulty · Multiple Choice
Determine which diagram correctly shows a uniform disc in equilibrium when acted upon by weight, tension, and a couple.
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Mark scheme
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How to answer it
AQA AS Physics • Mechanics • Moments & Equilibrium
Equilibrium of a Suspended Disc Under a Couple
What this question tests
This question tests the two essential conditions required for a rigid body to be in complete static equilibrium:
- Translational Equilibrium: The vector sum of all external forces must equal zero ( ΣF = 0 ).
- Rotational Equilibrium: The sum of clockwise moments about any pivot must equal the sum of anticlockwise moments ( Στ = 0 ).
- Understanding how to identify the moment of a couple and balance it using a single force acting at a perpendicular distance from the centre of mass.
Question 23 Analysis
Multiple Choice • 1 Mark • AO2 (Application of Knowledge)
✅ Correct Answer: Option D
The correct diagram is D, where the thread provides an upward tension of T = 50 N tangential to the left-hand rim of the disc.
Mark Scheme Breakdown:
• 1 mark for selecting D.
• 1 mark for selecting D.
💡 Key Knowledge
- Weight acts downwards through the centre of gravity ( W = 50 N at the centre).
- Couple: A pair of equal and opposite coplanar forces whose lines of action do not coincide.
Torque of couple = Force × perpendicular distance = F × 2r . - For total equilibrium, both linear forces and moments must be individually balanced.
🔨 Step-by-Step Derivation
- Step 1: Balance Vertical Forces (Translational Equilibrium)
The uniform disc has a weight of W = 50 N directed downwards.
The only vertical force balancing weight is the upward tension T in the thread.
ΣFvertical = T - W = 0 ⇒ T = 50 N .
Outcome: Options A ( T = 25 N ) and C ( T = 10 N ) are immediately eliminated. - Step 2: Determine the Direction and Magnitude of the Couple's Torque
Force P = 25 N acts to the left at the top rim.
Force Q = 25 N acts to the right at the bottom rim.
Taking moments about the central axis (radius r ):
• Moment of P = 25 × r (anticlockwise)
• Moment of Q = 25 × r (anticlockwise)
Total anticlockwise torque from couple = 25r + 25r = 50r (anticlockwise). - Step 3: Balance Rotational Moments About the Centre
The weight W acts through the centre, producing zero moment about the centre.
Therefore, the tension T = 50 N must provide a clockwise moment of 50r to achieve rotational equilibrium:
• If T is on the right rim (Option B): Pulling upwards produces an anticlockwise moment ( 50 × r ), adding to the couple. Result = unbalanced ( 100r anticlockwise).
• If T is on the left rim (Option D): Pulling upwards produces a clockwise moment ( 50 × r ), exactly canceling the couple!
🧠 Exam Technique • Elimination Strategy
- Two-stage filter: Always split 2D equilibrium problems into forces first, then moments.
- Filtering by vertical forces ( ΣFy = 0 ) takes 5 seconds and halves your choices (down to B and D).
- Use your finger or pen to simulate rotation: place your finger at the centre of the circle, push up where T acts, and observe which way it turns. You need a clockwise rotation to counteract the couple.
❌ Common Traps & Misconceptions
- Confusing Couple with Single Force: Thinking the tension needs to equal the value of force P or Q ( 25 N ), leading students to pick A.
- Wrong Rotation Sense: Incorrectly assuming an upward pull on the right produces a clockwise moment. It turns the wheel anticlockwise!
- Ignoring Weight: Forgetting that the disc itself has mass and weight ( 50 N ), which acts at the centre of gravity even though it is not explicitly drawn with an arrow.
Topics
Physics · 3.4 Mechanics and materials
Question and mark scheme from the AQA AS Level Physics examination, Paper 2, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.