AQA AS Level Physics Paper 2, June 2025: Question 6

1 mark · Medium difficulty · Multiple Choice

Determine the order of magnitude of the ratio of the speed of an electron to the speed of a proton having the same de Broglie wavelength.

Practise this question

Question

Question 06 asks: 'An electron and a proton have the same de Broglie wavelength. What is (speed of the electron)/(speed of the proton) to an order of magnitude?' Four multiple choice options are presented: A (10^-3), B (10^-2), C (10^1), and D (10^3).

Mark scheme

Show the mark scheme Mark scheme table indicating for question number 6 that the correct answer is option D, corresponding to 10^3, testing assessment objective AO1.

How to answer it

Ratio of Particle Speeds with Equal de Broglie Wavelength

📋 What this question tests
  • Wave-particle duality: Using the de Broglie equation λ = h / p = h / (mv) .
  • Proportional reasoning: Relating momentum and velocity when wavelengths are identical.
  • Data Booklet retrieval & estimation: Recalling or looking up the rest masses of protons and electrons, then evaluating an order of magnitude calculation without getting bogged down in unnecessary precision.
Question 06 (1 Mark)

Full Question Analysis

Multiple Choice Question (AO1)

✅ Correct Answer

D  (10³)

Mark Scheme: 1 mark for option D. AO1 (recall and application of fundamental physical constants and relationships).

💡 Key Knowledge

  • de Broglie wavelength: λ = h / mv
  • If two particles have the same wavelength λ , they must have the same momentum:
    pe = pp ⇒ meve = mpvp
  • Rearranging for the ratio of speeds gives an inverse mass ratio:
    ve / vp = mp / me
  • From the AQA Data Booklet:
    • Rest mass of proton, mp ≈ 1.67 × 10⁻²⁷ kg
    • Rest mass of electron, me ≈ 9.11 × 10⁻³¹ kg

📐 Step-by-Step Calculation

  1. Equate momenta:
    Since λ = h / p and h is constant, equal wavelengths mean equal momenta:
    me × ve = mp × vp
  2. Set up the required ratio:
    The question asks for ve / vp :
    ve / vp = mp / me
  3. Substitute mass values from the Data Booklet:
    ve / vp = (1.67 × 10⁻²⁷ kg) / (9.11 × 10⁻³¹ kg)
  4. Compute to an order of magnitude:
    ve / vp ≈ 1833 ≈ 1.83 × 10³
    To the nearest power of ten (order of magnitude), this is 10³.

🧠 Exam Technique & Intuition

  • Sanity check your answer: A proton is nearly 2000 times heavier than an electron. For a tiny electron to carry the exact same momentum as a massive proton, it must be travelling far faster! Therefore:
    ve >> vp ⇒ ve / vp > 1
  • This qualitative check immediately eliminates options A ( 10⁻³ ) and B ( 10⁻² ) in under 5 seconds!
  • Between 10¹ and 10³ , recall that a proton is ~1800 times heavier than an electron, which points directly to 10³ .

❌ Common Errors

  • Inverting the ratio (choosing A): Confusing ve / vp with me / mp leads directly to ~10⁻³ . Always write down meve = mpvp explicitly.
  • Forgetting mass difference: Guessing option C ( 10¹ ) by underestimating the vast mass difference between leptons and baryons.
  • Wasting time with full calculations: Multiple-choice questions are 1 mark each (~1 minute). Do not calculate to 3 significant figures when order-of-magnitude powers of 10 are all that is required.

Topics

Physics · 3.1 Measurements and their errors · 3.2 Particles and radiation

Question and mark scheme from the AQA AS Level Physics examination, Paper 2, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.