AQA GCSE Biology Biology Paper 1 (Higher), June 2023: Question 6

15 marks · Standard Demand difficulty · Short Answer

Complete the equation, analyze photosynthesis rate against light intensity and wavelength, and evaluate a practical investigating the effect of light colour on photosynthesis.

Practise this question

Question

The question covers photosynthesis in several parts. Part 06.1 requires completing the balanced chemical equation. Figure 8 shows a curve of rate of photosynthesis against light intensity up to 30 thousand lux. Part 06.2 asks which range of lux fits y = mx + c. Figure 9 diagrams an experiment with a lamp shining on leaf discs in sodium hydrogencarbonate solution, accompanied by Table 5 showing time taken for 10 leaf discs to float in blue, green, and red light. Questions 06.3 to 06.7 ask about variables, method, and explanation of why discs float and why hydrogencarbonate is used. Figure 10 shows absorption spectra curves for chlorophyll a and b across wavelengths 400 to 700 nm, paired with Table 6 defining wavelength bands for colours. Questions 06.8 and 06.9 require explaining advantages of multiple pigments and interpreting results for blue versus green light.
Question text

06 This question is about photosynthesis.

06.1 Complete the symbol equation for photosynthesis.

[1 mark]

6 + 6 → C6H12O6 + 6

Figure 8 shows how the rate of photosynthesis changes with light intensity.

Figure 8

06.2 Which part of the graph could be represented by the equation y = mx + c ?

[1 mark]

Tick ( ) one box.

From 0 to 5 000 lux

From 10 000 to 15 000 lux

From 15 000 to 20 000 lux

From 20 000 to 25 000 lux 32

A student investigated the effect of colour of light on the rate of photosynthesis

in leaves.

Figure 9 shows how the investigation was set up.

Figure 9

Table 5 shows the results.

Table 5

Time taken for 10 leaf discs to reach the

Colour of light

surface of the solution in seconds

Blue 115

Green 831

Red 397

06.3 Give one way the student could change the colour of the light shining on

the leaf discs.

*31* [1 mark]

06.4 Give the independent variable and the dependent variable in this investigation.

[2 marks]

Independent variable

Dependent variable

06.5 All of the air had to be removed from the leaf discs before placing them in the beaker.

Suggest one reason why.

[1 mark]

06.6 The leaf discs were placed in a beaker of sodium hydrogencarbonate

(NaHCO3) solution.

Explain why sodium hydrogencarbonate solution was used instead of water.

[2 marks]

06.7 Explain why the leaf discs moved to the surface of the solution during

the investigation.

[2 marks]

There are two types of chlorophyll in leaves.

*33* Figure 10 shows the percentage of different wavelengths of light that the two types of

chlorophyll absorb.

Figure 10

Table 6 shows the colour of different wavelengths of light.

Table 6

Range of

wavelength of 380 − 435 450 − 499 500 − 570 571 − 590 620 − 720

light in nm

Colour of light violet blue green yellow red

06.8 Suggest the advantage to a plant of having two types of chlorophyll.

[1 mark]

06.9 Table 5 is repeated below.

Table 5

Time taken for 10 leaf discs to reach the

Colour of light

*34* surface of the solution in seconds

Blue 115

Green 831

Red 397

The leaf discs in the investigation are green.

Explain the results in Table 5 for blue light and for green light.

Use data from Figure 10 and Table 6.

[4 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 6 with a total of 15 marks. 06.1: H2O and CO2 on left, O2 on right (1 mark). 06.2: 'from 0 to 5 000 lux' ticked (1 mark). 06.3: use coloured bulbs/LEDs or coloured filters (1 mark). 06.4: independent is colour of light (1 mark), dependent is time taken for 10 leaf discs to reach surface (1 mark). 06.5: so discs sink or gas produced is strictly from photosynthesis (1 mark). 06.6: releases carbon dioxide for photosynthesis (2 marks). 06.7: oxygen is produced and trapped in/around discs making them float (2 marks). 06.8: absorb a wider range/more wavelengths of light (1 mark). 06.9: 4 marks for explaining chlorophyll absorbs mostly blue light and least green light, causing faster photosynthesis and shorter rise time for blue light, with quoted data from Figure 10 and Table 6.

Question 6

AO /

Question Answers Extra information Mark

Spec Ref.

06.1 (lhs) H2O + CO2 in either order 1 AO1

4.4.1.1

and

(rhs) O2

AO /

Spec Ref.

06.2 from 0 to 5 000 lux 1 AO3

4.4.1.2

AO /

Spec Ref.

06.3 any one from: 1 AO2

• use (different) coloured 4.4.1.2

bulb(s) / LED(s) RPA6

• use (different) coloured

filter(s) in front of lamp

• put (different) coloured allow named transparent

transparent material(s) over material(s)

lamp / beaker

AO /

Spec Ref.

06.4 independent AO2

allow wavelength of light 4.4.1.1

colour of light 1

4.4.1.2

ignore colour of filter / bulb /

RPA6

lamp

dependent

time (taken for 10 leaf discs to 1

reach the surface of the

solution)

AO /

Spec Ref.

06.5 any one from: allow leaf for disc throughout 1 AO2

4.4.1.1

• so that discs would sink (to allow so the discs do not float

4.4.1.2

the bottom of the beaker)

RPA6

• so any gas (that makes the 25

discs rise) is from

photosynthesis

• air is a gas so any left in discs ignore reference to carbon

would add to the oxygen dioxide

produced by photosynthesis

allow as a control variable

AO /

Spec Ref.

06.6 (sodium hydrogencarbonate) ignore (sodium 1 AO2

provides / releases carbon hydrogencarbonate) contains 4.4.1.1

dioxide carbon dioxide 4.4.1.2

ignore provides water RPA6

(carbon dioxide is used) for 1

photosynthesis

AO /

Spec Ref.

06.7 oxygen was produced in 1 AO1

photosynthesis

oxygen / gas is trapped in / allow bubbles are trapped in / 1 AO2

around disc / leaf around the disc / leaf 4.4.1.1

allow oxygen / gas (makes leaf 4.4.1.2

discs) less dense than solution / RPA6

water

allow the oxygen / gas under the

disc / leaf pushes the disc / leaf

up

AO /

Spec Ref.

06.8 to absorb / use many / more allow to increase the rate of 1 AO2

colours / wavelengths of light photosynthesis 4.4.1.1

4.4.1.2

ignore to absorb as much light

as possible

26 do not accept to absorb all

colours / wavelengths of light

AO /

Spec Ref.

06.9 chlorophyll absorbs most or a 1 AO3

lot of blue light

if neither mark awarded allow

1 mark for chlorophyll

absorbs more blue light (than

green light)

chlorophyll absorbs least or very allow chlorophyll reflects 1

AO3

little or not much green light most of the green light

(so) discs in blue light took the 1 AO2

least time to rise (to surface)

because they photosynthesised

faster / more

or

(so) discs in green light took the

most time to rise (to surface)

because they photosynthesised

slower / less

use of data (from Figure 10 and 1 AO2

Table 6) eg approximately 80% 4.4.1.1

of blue light absorbed 4.4.1.2

Total Question 6 15

How to answer it

Photosynthesis: Rate Factors, Practical Variables & Light Absorption

What this question tests

This question assesses key knowledge and practical skills from AQA Biology Paper 1 (Topic 4.4 Bioenergetics & RPA 6):

  • Recall of the balanced chemical formula equation for photosynthesis.
  • Mathematical interpretation of rate graphs ( y = mx + c linear segments).
  • Scientific method: identifying independent and dependent variables, plus control steps in floating leaf disc assays.
  • Explaining the role of dissolved hydrogen carbonate and gas exchange during photosynthesis.
  • Data synthesis and graph reading: linking chlorophyll absorption peaks across different wavelengths to experimental rates of photosynthesis.
Question 06.1 • 1 Mark

Balanced Chemical Equation for Photosynthesis

Completing the chemical formula

✅ Mark Scheme Answer

LHS (Reactants): CO₂ and H₂O (in either order)

RHS (Products): O₂

Full balanced equation:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

❌ Common Errors

  • Writing names instead of chemical symbols (e.g. writing "carbon dioxide" instead of CO₂ ).
  • Incorrect capitalisation or subscript formatting: writing Co2 or h2o will cost the mark.
  • Writing numbers in front of the molecules when balancing numbers are already provided.
Examiner Insight: All chemical formulas must be strictly correct. The number 6 was already pre-printed on each dashed line, so adding another balancing number or writing word equations resulted in zero marks.
Question 06.2 • 1 Mark

Linear Relationships on Rate Graphs

Identifying where rate obeys y = mx + c

✅ Correct Selection

Tick the box: From 0 to 5 000 lux

💡 Key Knowledge

The equation y = mx + c represents a straight line. Looking at Figure 8:

  • From 0 to 5 000 lux, the curve is essentially a straight line passing through the origin (directly proportional).
  • Above 5 000 lux, the gradient decreases as the curve bends and eventually levels off (plateaus) around 22 000 lux.
Question 06.3 • 1 Mark

Manipulating Light Colour in Experiments

Practical method adjustment

✅ Any ONE valid method:

  • Use different coloured light bulbs or LEDs.
  • Place different coloured filters (or cellophane/plastic) in front of the lamp / between lamp and beaker.
  • Wrap the beaker with different coloured transparent cellophane.

🧠 Exam Technique

Be precise. Stating "use a coloured filter" is much safer than just saying "change the screen". If naming a material, ensure it is transparent or translucent so light can still pass through.

Question 06.4 • 2 Marks

Identifying Experimental Variables

Independent vs Dependent variables

✅ Correct Identifications

Independent variable (1 mark): Colour of light (or wavelength of light)

Dependent variable (1 mark): Time taken for 10 leaf discs to reach the surface of the solution

❌ What Examiners Ignored / Rejected

  • Independent variable: Stating "colour of filter", "colour of lamp", or "bulb" was ignored. You are testing the light itself, not the equipment.
  • Dependent variable: Stating just "rate of photosynthesis" was insufficient because the question asked for the specific variable measured in this investigation. Always write the exact measurement taken!
Question 06.5 • 1 Mark

Pre-treatment of Leaf Discs

Why must air be evacuated?

✅ Any ONE reason:

  • So that the leaf discs would sink to the bottom of the beaker at the start (so they do not already float).
  • To ensure that any gas that makes the discs rise is produced by photosynthesis (not pre-existing trapped air).
  • To standardise starting air content (control variable).

💡 Mechanism Behind the Assay

Spongy mesophyll tissue contains air spaces. Drawing a vacuum replaces these air pockets with the liquid solution, increasing tissue density so discs sink. As photosynthesis proceeds, newly produced gas refills the intercellular spaces, decreasing density until the discs float.

Question 06.6 • 2 Marks

Role of Sodium Hydrogencarbonate (NaHCO₃)

Supplying inorganic carbon

✅ 2-Mark Structure

  1. Sodium hydrogencarbonate provides / releases carbon dioxide (CO₂). [1 mark]
  2. Carbon dioxide is required / used as a reactant for photosynthesis (ensuring CO₂ is not a limiting factor). [1 mark]

❌ Common Misconceptions

  • Writing "it contains carbon dioxide" without stating that it releases/provides it into solution.
  • Claiming it "provides water" or "controls pH" (both rejected for this mark).
Question 06.7 • 2 Marks

Explaining Why Discs Rise

Connecting chemical products to physical movement

✅ Required Points

  • Oxygen gas was produced during photosynthesis. [1 mark]
  • The oxygen/gas bubbles become trapped inside/around the leaf disc, causing it to become less dense than the solution (or buoyancy forces push it upwards). [1 mark]

🧠 Exam Technique

Always name the specific gas: oxygen. Saying "gas is produced" only gets partial credit unless explicitly identified as oxygen formed by photosynthesis.

Question 06.8 • 1 Mark

Evolutionary Advantage of Two Chlorophylls

Chlorophyll a and Chlorophyll b

✅ Correct Answer

To absorb / use a wider range of wavelengths / colours of light (or to increase the total rate of photosynthesis). [1 mark]

❌ Mark Scheme Trap

Do NOT write "to absorb all colours of light" or "all wavelengths of light". Chlorophyll reflects green light (neither absorbs green well), so it does not absorb all light!

Question 06.9 • 4 Marks

Full Evaluation: Blue vs Green Light

Linking Table 5, Table 6, and Figure 10

📐 Data Extraction Checklist

  • Blue light: Wavelength = 450 – 499 nm; Chlorophyll b absorbs ~80%, Chlorophyll a absorbs ~40%. Time to rise = 115 s.
  • Green light: Wavelength = 500 – 570 nm; Absorption for both chlorophylls drops close to 0% (under 5%). Time to rise = 831 s.

✅ Full 4-Mark Model Answer

  1. Blue absorption: Chlorophyll absorbs a high percentage / most of blue light (approx. 450–499 nm). [1 mark]
  2. Green absorption: Chlorophyll absorbs very little / least amount of green light (approx. 500–570 nm) / reflects most green light. [1 mark]
  3. Link to rate: Leaf discs in blue light rose faster (115 s) because they photosynthesised at a higher rate; in green light they took the longest (831 s) because the rate of photosynthesis was much slower. [1 mark]
  4. Data quote: Quote figures from Figure 10 / Table 6 (e.g. Chlorophyll b absorbs ~80% of blue light around 460 nm, but absorption drops to under 5% in green light). [1 mark]

❌ Common Student Pitfalls

  • Inverting the time-rate relationship: Confusing a smaller time (115 s) with a slower rate. 115 seconds means it rose faster, meaning a higher rate of photosynthesis!
  • Forgetting data quotes: The question explicitly says "Use data from Figure 10 and Table 6". Missing numerical absorption percentages or wavelength ranges automatically caps marks at 3/4.
Summary for Revision: Plants look green because chlorophyll absorbs blue and red wavelengths for photosynthesis, while green light is reflected rather than absorbed.

Topics

Biology · Required Practicals · B4: Bioenergetics · Required Practicals

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 1 (Higher), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.