AQA GCSE Biology Biology Paper 1 (Higher), June 2023: Question 6
15 marks · Standard Demand difficulty · Short Answer
Complete the equation, analyze photosynthesis rate against light intensity and wavelength, and evaluate a practical investigating the effect of light colour on photosynthesis.
Practise this questionQuestion
Question text
06 This question is about photosynthesis.
06.1 Complete the symbol equation for photosynthesis.
[1 mark]
6 + 6 → C6H12O6 + 6
Figure 8 shows how the rate of photosynthesis changes with light intensity.
Figure 8
06.2 Which part of the graph could be represented by the equation y = mx + c ?
[1 mark]
Tick ( ) one box.
From 0 to 5 000 lux
From 10 000 to 15 000 lux
From 15 000 to 20 000 lux
From 20 000 to 25 000 lux 32
A student investigated the effect of colour of light on the rate of photosynthesis
in leaves.
Figure 9 shows how the investigation was set up.
Figure 9
Table 5 shows the results.
Table 5
Time taken for 10 leaf discs to reach the
Colour of light
surface of the solution in seconds
Blue 115
Green 831
Red 397
06.3 Give one way the student could change the colour of the light shining on
the leaf discs.
*31* [1 mark]
06.4 Give the independent variable and the dependent variable in this investigation.
[2 marks]
Independent variable
Dependent variable
06.5 All of the air had to be removed from the leaf discs before placing them in the beaker.
Suggest one reason why.
[1 mark]
06.6 The leaf discs were placed in a beaker of sodium hydrogencarbonate
(NaHCO3) solution.
Explain why sodium hydrogencarbonate solution was used instead of water.
[2 marks]
06.7 Explain why the leaf discs moved to the surface of the solution during
the investigation.
[2 marks]
There are two types of chlorophyll in leaves.
*33* Figure 10 shows the percentage of different wavelengths of light that the two types of
chlorophyll absorb.
Figure 10
Table 6 shows the colour of different wavelengths of light.
Table 6
Range of
wavelength of 380 − 435 450 − 499 500 − 570 571 − 590 620 − 720
light in nm
Colour of light violet blue green yellow red
06.8 Suggest the advantage to a plant of having two types of chlorophyll.
[1 mark]
06.9 Table 5 is repeated below.
Table 5
Time taken for 10 leaf discs to reach the
Colour of light
*34* surface of the solution in seconds
Blue 115
Green 831
Red 397
The leaf discs in the investigation are green.
Explain the results in Table 5 for blue light and for green light.
Use data from Figure 10 and Table 6.
[4 marks]
Mark scheme
Show the mark scheme
Question 6
AO /
Question Answers Extra information Mark
Spec Ref.
06.1 (lhs) H2O + CO2 in either order 1 AO1
4.4.1.1
and
(rhs) O2
AO /
Spec Ref.
06.2 from 0 to 5 000 lux 1 AO3
4.4.1.2
AO /
Spec Ref.
06.3 any one from: 1 AO2
• use (different) coloured 4.4.1.2
bulb(s) / LED(s) RPA6
• use (different) coloured
filter(s) in front of lamp
• put (different) coloured allow named transparent
transparent material(s) over material(s)
lamp / beaker
AO /
Spec Ref.
06.4 independent AO2
allow wavelength of light 4.4.1.1
colour of light 1
4.4.1.2
ignore colour of filter / bulb /
RPA6
lamp
dependent
time (taken for 10 leaf discs to 1
reach the surface of the
solution)
AO /
Spec Ref.
06.5 any one from: allow leaf for disc throughout 1 AO2
4.4.1.1
• so that discs would sink (to allow so the discs do not float
4.4.1.2
the bottom of the beaker)
RPA6
• so any gas (that makes the 25
discs rise) is from
photosynthesis
• air is a gas so any left in discs ignore reference to carbon
would add to the oxygen dioxide
produced by photosynthesis
allow as a control variable
AO /
Spec Ref.
06.6 (sodium hydrogencarbonate) ignore (sodium 1 AO2
provides / releases carbon hydrogencarbonate) contains 4.4.1.1
dioxide carbon dioxide 4.4.1.2
ignore provides water RPA6
(carbon dioxide is used) for 1
photosynthesis
AO /
Spec Ref.
06.7 oxygen was produced in 1 AO1
photosynthesis
oxygen / gas is trapped in / allow bubbles are trapped in / 1 AO2
around disc / leaf around the disc / leaf 4.4.1.1
allow oxygen / gas (makes leaf 4.4.1.2
discs) less dense than solution / RPA6
water
allow the oxygen / gas under the
disc / leaf pushes the disc / leaf
up
AO /
Spec Ref.
06.8 to absorb / use many / more allow to increase the rate of 1 AO2
colours / wavelengths of light photosynthesis 4.4.1.1
4.4.1.2
ignore to absorb as much light
as possible
26 do not accept to absorb all
colours / wavelengths of light
AO /
Spec Ref.
06.9 chlorophyll absorbs most or a 1 AO3
lot of blue light
if neither mark awarded allow
1 mark for chlorophyll
absorbs more blue light (than
green light)
chlorophyll absorbs least or very allow chlorophyll reflects 1
AO3
little or not much green light most of the green light
(so) discs in blue light took the 1 AO2
least time to rise (to surface)
because they photosynthesised
faster / more
or
(so) discs in green light took the
most time to rise (to surface)
because they photosynthesised
slower / less
use of data (from Figure 10 and 1 AO2
Table 6) eg approximately 80% 4.4.1.1
of blue light absorbed 4.4.1.2
Total Question 6 15
How to answer it
Photosynthesis: Rate Factors, Practical Variables & Light Absorption
What this question tests
This question assesses key knowledge and practical skills from AQA Biology Paper 1 (Topic 4.4 Bioenergetics & RPA 6):
- Recall of the balanced chemical formula equation for photosynthesis.
- Mathematical interpretation of rate graphs ( y = mx + c linear segments).
- Scientific method: identifying independent and dependent variables, plus control steps in floating leaf disc assays.
- Explaining the role of dissolved hydrogen carbonate and gas exchange during photosynthesis.
- Data synthesis and graph reading: linking chlorophyll absorption peaks across different wavelengths to experimental rates of photosynthesis.
Balanced Chemical Equation for Photosynthesis
Completing the chemical formula
✅ Mark Scheme Answer
LHS (Reactants): CO₂ and H₂O (in either order)
RHS (Products): O₂
Full balanced equation:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
❌ Common Errors
- Writing names instead of chemical symbols (e.g. writing "carbon dioxide" instead of CO₂ ).
- Incorrect capitalisation or subscript formatting: writing Co2 or h2o will cost the mark.
- Writing numbers in front of the molecules when balancing numbers are already provided.
Linear Relationships on Rate Graphs
Identifying where rate obeys y = mx + c
✅ Correct Selection
Tick the box: From 0 to 5 000 lux
💡 Key Knowledge
The equation y = mx + c represents a straight line. Looking at Figure 8:
- From 0 to 5 000 lux, the curve is essentially a straight line passing through the origin (directly proportional).
- Above 5 000 lux, the gradient decreases as the curve bends and eventually levels off (plateaus) around 22 000 lux.
Manipulating Light Colour in Experiments
Practical method adjustment
✅ Any ONE valid method:
- Use different coloured light bulbs or LEDs.
- Place different coloured filters (or cellophane/plastic) in front of the lamp / between lamp and beaker.
- Wrap the beaker with different coloured transparent cellophane.
🧠 Exam Technique
Be precise. Stating "use a coloured filter" is much safer than just saying "change the screen". If naming a material, ensure it is transparent or translucent so light can still pass through.
Identifying Experimental Variables
Independent vs Dependent variables
✅ Correct Identifications
Independent variable (1 mark): Colour of light (or wavelength of light)
Dependent variable (1 mark): Time taken for 10 leaf discs to reach the surface of the solution
❌ What Examiners Ignored / Rejected
- Independent variable: Stating "colour of filter", "colour of lamp", or "bulb" was ignored. You are testing the light itself, not the equipment.
- Dependent variable: Stating just "rate of photosynthesis" was insufficient because the question asked for the specific variable measured in this investigation. Always write the exact measurement taken!
Pre-treatment of Leaf Discs
Why must air be evacuated?
✅ Any ONE reason:
- So that the leaf discs would sink to the bottom of the beaker at the start (so they do not already float).
- To ensure that any gas that makes the discs rise is produced by photosynthesis (not pre-existing trapped air).
- To standardise starting air content (control variable).
💡 Mechanism Behind the Assay
Spongy mesophyll tissue contains air spaces. Drawing a vacuum replaces these air pockets with the liquid solution, increasing tissue density so discs sink. As photosynthesis proceeds, newly produced gas refills the intercellular spaces, decreasing density until the discs float.
Role of Sodium Hydrogencarbonate (NaHCO₃)
Supplying inorganic carbon
✅ 2-Mark Structure
- Sodium hydrogencarbonate provides / releases carbon dioxide (CO₂). [1 mark]
- Carbon dioxide is required / used as a reactant for photosynthesis (ensuring CO₂ is not a limiting factor). [1 mark]
❌ Common Misconceptions
- Writing "it contains carbon dioxide" without stating that it releases/provides it into solution.
- Claiming it "provides water" or "controls pH" (both rejected for this mark).
Explaining Why Discs Rise
Connecting chemical products to physical movement
✅ Required Points
- Oxygen gas was produced during photosynthesis. [1 mark]
- The oxygen/gas bubbles become trapped inside/around the leaf disc, causing it to become less dense than the solution (or buoyancy forces push it upwards). [1 mark]
🧠 Exam Technique
Always name the specific gas: oxygen. Saying "gas is produced" only gets partial credit unless explicitly identified as oxygen formed by photosynthesis.
Evolutionary Advantage of Two Chlorophylls
Chlorophyll a and Chlorophyll b
✅ Correct Answer
To absorb / use a wider range of wavelengths / colours of light (or to increase the total rate of photosynthesis). [1 mark]
❌ Mark Scheme Trap
Do NOT write "to absorb all colours of light" or "all wavelengths of light". Chlorophyll reflects green light (neither absorbs green well), so it does not absorb all light!
Full Evaluation: Blue vs Green Light
Linking Table 5, Table 6, and Figure 10
📐 Data Extraction Checklist
- Blue light: Wavelength = 450 – 499 nm; Chlorophyll b absorbs ~80%, Chlorophyll a absorbs ~40%. Time to rise = 115 s.
- Green light: Wavelength = 500 – 570 nm; Absorption for both chlorophylls drops close to 0% (under 5%). Time to rise = 831 s.
✅ Full 4-Mark Model Answer
- Blue absorption: Chlorophyll absorbs a high percentage / most of blue light (approx. 450–499 nm). [1 mark]
- Green absorption: Chlorophyll absorbs very little / least amount of green light (approx. 500–570 nm) / reflects most green light. [1 mark]
- Link to rate: Leaf discs in blue light rose faster (115 s) because they photosynthesised at a higher rate; in green light they took the longest (831 s) because the rate of photosynthesis was much slower. [1 mark]
- Data quote: Quote figures from Figure 10 / Table 6 (e.g. Chlorophyll b absorbs ~80% of blue light around 460 nm, but absorption drops to under 5% in green light). [1 mark]
❌ Common Student Pitfalls
- Inverting the time-rate relationship: Confusing a smaller time (115 s) with a slower rate. 115 seconds means it rose faster, meaning a higher rate of photosynthesis!
- Forgetting data quotes: The question explicitly says "Use data from Figure 10 and Table 6". Missing numerical absorption percentages or wavelength ranges automatically caps marks at 3/4.
Topics
Biology · Required Practicals · B4: Bioenergetics · Required Practicals
Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 1 (Higher), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.