AQA GCSE Chemistry Chemistry Paper 1 (Foundation), June 2022: Question 7
10 marks · Standard Demand difficulty · Short Answer
Answer questions on small particles, calculating the volume and surface area to volume ratio of a cubic nanoparticle, and evaluating the use of silver nanoparticles.
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Question text
07 This question is about small particles.
07.1 Coarse particles, fine particles and nanoparticles are all small particles.
Which is the largest particle?
[1 mark]
Tick ( ) one box.
Coarse particle
Fine particle
Nanoparticle
07.2 Figure 12 shows a cubic nanoparticle.
Figure 12
The surface area of the cubic nanoparticle is 24 nm2.
Calculate:
• the volume of the cubic nanoparticle
• the simplest surface area : volume ratio of the cubic nanoparticle.
[4 marks]
Volume = nm3
Simplest surface area : volume ratio = : 1
07.3 Catalysts made of nanoparticles are often more effective than catalysts made of
normal sized particles.
Complete the sentences.
[2 marks]
Compared with normal sized particles, the surface area to volume ratio of
nanoparticles is .
This means that the mass of a nanoparticle catalyst needed to have the same effect
as the same catalyst made of normal sized particles is .
07.4 Silver nanoparticles can be added to the material used to make socks.
Some facts about silver and bacteria are:
• silver nanoparticles are small enough to be breathed in
• silver is very expensive
• silver can kill bacteria
• bacteria can cause infections
• bacteria can break down sweat to produce unpleasant smells.
Suggest one advantage and one disadvantage of wearing socks containing
silver nanoparticles.
[2 marks]
Advantage
Disadvantage
07.5 An atom has a radius of 1 × 10−10 m.
A spherical nanoparticle has a radius of 1 × 10−8 m.
How many times larger is the radius of the nanoparticle than the radius of the atom?
[1 mark]
Tick ( ) one box.
2 times
*26* 10 times
100 times
200 times
Mark scheme
Show the mark scheme
Question 7
AO /
Question Answers Extra information Mark
Spec. Ref.
07.1 coarse particle 1 AO1
4.2.4.1
AO /
Spec. Ref.
(volume =) 23 allow (volume =) 2×2×2 1 AO2
07.2
4.2.4.1
= 8 (nm3) 1
(surface area : volume)
= 24 : 8 allow correct use of an 1
incorrectly calculated volume
(simplest ratio) = 3 : 1 1
AO /
Spec. Ref.
07.3 high(er) / large(r) 1 AO1
4.2.4.1
lower / less / smaller 1
AO /
Spec. Ref.
07.4 (advantage) AO3
any one from: 1 4.2.4.2
• stops (unpleasant) smells
• can stop (foot) infections allow specific (foot) infections
allow silver can kill bacteria
(disadvantage)
any one from: 1
• high cost (of socks) allow silver is (very) expensive
• could be harmful if breathed in
AO /
Spec. Ref.
07.5 100 times 1 AO2
4.1.1.5
4.2.4.1
Total Question 7 10
How to answer it
Nanoparticles: Properties, Scale & Calculations
What this question tests
This question assesses fundamental knowledge of nanoscience and particle size (AQA Specification 4.2.4), including:
- Classifying particle sizes: coarse, fine, and nanoparticles.
- Mathematical skills: calculating the volume of a 3D cube and deriving a simplified surface area to volume ratio (SA:V).
- Explaining why nanoparticles make highly effective catalysts with smaller required masses.
- Evaluating the everyday risks and benefits of silver nanoparticles using provided contextual data.
- Comparing orders of magnitude using standard form notation (powers of 10).
Particle Size Comparison
Identifying the largest particle among coarse, fine, and nanoparticles
✅ Correct Answer
Tick box 1: Coarse particle
💡 Key Knowledge
Order of particle sizes from largest to smallest:
- Coarse particles (PM₁₀): 2500 nm to 10 000 nm (often called dust).
- Fine particles (PM₂.₅): 100 nm to 2500 nm.
- Nanoparticles: 1 nm to 100 nm (only a few hundred atoms across).
Volume & Surface Area to Volume Ratio Calculation
Calculating properties of a 2 nm × 2 nm × 2 nm cubic nanoparticle
📐 Step-by-Step Calculation
Step 1: Calculate volume
Volume = length × width × height
Volume = 2 nm × 2 nm × 2 nm = 8 nm³
Step 2: Set up the initial ratio
Surface area : Volume = 24 : 8
Step 3: Simplify to the form [n : 1]
Divide both sides by 8:
24 ÷ 8 = 3
Simplest ratio = 3 : 1
✅ Mark Breakdown
- Mark 1: Formula or substitution seen: 2³ or 2 × 2 × 2
- Mark 2: Correct volume calculated: 8 (nm³)
- Mark 3: Unsimplified ratio set up: 24 : 8 (allow error carried forward from incorrect volume)
- Mark 4: Fully simplified ratio: 3 (given as 3 : 1 on the dotted line)
❌ Common Errors
- Confusing Area and Volume: Adding the dimensions (2 + 2 + 2 = 6) instead of multiplying them.
- Incomplete Simplification: Leaving the answer as 24 : 8 or 12 : 4 . Notice the exam answer line already ends in : 1 . You must give a single simplified number on that line!
🧠 Exam Technique
Always inspect the answer line carefully. When the question asks for the simplest ratio in the format ______ : 1 , the right-hand side is already set to 1. Simply calculate:
Surface Area ÷ Volume = 24 ÷ 8 = 3
Nanoparticles as Catalysts
Explaining why smaller masses of nanoparticles are required
✅ Correct Answer
Compared with normal sized particles, the surface area to volume ratio of nanoparticles is higher / larger. [1 mark]
This means that the mass of a nanoparticle catalyst needed to have the same effect as the same catalyst made of normal sized particles is lower / less / smaller. [1 mark]
💡 Key Knowledge
As particle size decreases by a factor of 10, the surface area to volume ratio increases by a factor of 10. Because catalytic reactions take place on the surface, nanoparticles have a huge percentage of their atoms exposed at the surface.
This makes them far more reactive, meaning you need a significantly smaller mass compared to bulk materials to achieve the same catalytic effect.
Silver Nanoparticles in Socks
Evaluating advantages and disadvantages using provided information
✅ Acceptable Answers
Advantage (any one):
- Stops / reduces unpleasant smells.
- Can stop / reduce (foot) infections.
- Kills bacteria.
Disadvantage (any one):
- High cost of socks / silver is very expensive.
- Could be harmful / toxic if breathed in.
🧠 Exam Technique: Use the Provided Stem
The prompt provides five bullet points. The examiner is explicitly looking for you to link those facts to a practical benefit and a drawback:
- "Bacteria can break down sweat to produce unpleasant smells" → Advantage: stops bad smells.
- "Silver is very expensive" → Disadvantage: increases product cost.
- "Small enough to be breathed in" → Disadvantage: potential lung hazard if particles shed.
Standard Form & Size Comparison
Comparing an atom (1 × 10⁻¹⁰ m) and a nanoparticle (1 × 10⁻⁸ m)
✅ Correct Answer
Tick box 3: 100 times
📐 Working with Powers of Ten
Divide the nanoparticle radius by the atomic radius:
Scale factor = (1 × 10⁻⁸) ÷ (1 × 10⁻¹⁰)
10⁻⁸ ÷ 10⁻¹⁰ = 10^(-8 - (-10)) = 10² = 100
The nanoparticle radius is 100 times larger than the atom radius.
❌ Common Errors
- Selecting "2 times": Subtracting the exponents (-8 - (-10) = 2) and mistaking the power of 2 for a direct factor of 2.
- Selecting "10 times": Miscounting the difference in powers of ten. Remember, each step in exponent is a factor of 10 (10¹ = 10, 10² = 100).
Topics
Chemistry · C2: Bonding, Structure and the Properties of Matter · C1: Atomic Structure and the Periodic Table
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.