AQA GCSE Chemistry Chemistry Paper 1 (Foundation), June 2022: Question 7

10 marks · Standard Demand difficulty · Short Answer

Answer questions on small particles, calculating the volume and surface area to volume ratio of a cubic nanoparticle, and evaluating the use of silver nanoparticles.

Practise this question

Question

Question 7 consists of five parts. Part 07.1 asks which particle is largest among coarse particles, fine particles, and nanoparticles. Part 07.2 shows Figure 12, a cube with side lengths 2 nm, and asks to calculate its volume and simplest surface area to volume ratio given a surface area of 24 nm squared. Part 07.3 asks to complete sentences comparing the surface area to volume ratio and mass needed of nanoparticle catalysts to normal-sized particles. Part 07.4 gives facts about silver and bacteria, asking for one advantage and one disadvantage of socks containing silver nanoparticles. Part 07.5 gives the radius of an atom as 1 x 10^-10 m and a nanoparticle as 1 x 10^-8 m, asking how many times larger the nanoparticle radius is.
Question text

07 This question is about small particles.

07.1 Coarse particles, fine particles and nanoparticles are all small particles.

Which is the largest particle?

[1 mark]

Tick ( ) one box.

Coarse particle

Fine particle

Nanoparticle

07.2 Figure 12 shows a cubic nanoparticle.

Figure 12

The surface area of the cubic nanoparticle is 24 nm2.

Calculate:

• the volume of the cubic nanoparticle

• the simplest surface area : volume ratio of the cubic nanoparticle.

[4 marks]

Volume = nm3

Simplest surface area : volume ratio = : 1

07.3 Catalysts made of nanoparticles are often more effective than catalysts made of

normal sized particles.

Complete the sentences.

[2 marks]

Compared with normal sized particles, the surface area to volume ratio of

nanoparticles is .

This means that the mass of a nanoparticle catalyst needed to have the same effect

as the same catalyst made of normal sized particles is .

07.4 Silver nanoparticles can be added to the material used to make socks.

Some facts about silver and bacteria are:

• silver nanoparticles are small enough to be breathed in

• silver is very expensive

• silver can kill bacteria

• bacteria can cause infections

• bacteria can break down sweat to produce unpleasant smells.

Suggest one advantage and one disadvantage of wearing socks containing

silver nanoparticles.

[2 marks]

Advantage

Disadvantage

07.5 An atom has a radius of 1 × 10−10 m.

A spherical nanoparticle has a radius of 1 × 10−8 m.

How many times larger is the radius of the nanoparticle than the radius of the atom?

[1 mark]

Tick ( ) one box.

2 times

*26* 10 times

100 times

200 times

Mark scheme

Show the mark scheme Mark scheme for Question 7. 07.1: coarse particle (1 mark). 07.2: volume = 2 cubed = 8 nm cubed (2 marks), surface area to volume ratio = 24 : 8, simplified to 3 : 1 (2 marks). 07.3: high(er) / large(r) (1 mark) and lower / less / smaller (1 mark). 07.4: advantage is stops unpleasant smells or foot infections (1 mark); disadvantage is high cost or harmful if breathed in (1 mark). 07.5: 100 times (1 mark). Total: 10 marks.

Question 7

AO /

Question Answers Extra information Mark

Spec. Ref.

07.1 coarse particle 1 AO1

4.2.4.1

AO /

Spec. Ref.

(volume =) 23 allow (volume =) 2×2×2 1 AO2

07.2

4.2.4.1

= 8 (nm3) 1

(surface area : volume)

= 24 : 8 allow correct use of an 1

incorrectly calculated volume

(simplest ratio) = 3 : 1 1

AO /

Spec. Ref.

07.3 high(er) / large(r) 1 AO1

4.2.4.1

lower / less / smaller 1

AO /

Spec. Ref.

07.4 (advantage) AO3

any one from: 1 4.2.4.2

• stops (unpleasant) smells

• can stop (foot) infections allow specific (foot) infections

allow silver can kill bacteria

(disadvantage)

any one from: 1

• high cost (of socks) allow silver is (very) expensive

• could be harmful if breathed in

AO /

Spec. Ref.

07.5 100 times 1 AO2

4.1.1.5

4.2.4.1

Total Question 7 10

How to answer it

Nanoparticles: Properties, Scale & Calculations

What this question tests

This question assesses fundamental knowledge of nanoscience and particle size (AQA Specification 4.2.4), including:

  • Classifying particle sizes: coarse, fine, and nanoparticles.
  • Mathematical skills: calculating the volume of a 3D cube and deriving a simplified surface area to volume ratio (SA:V).
  • Explaining why nanoparticles make highly effective catalysts with smaller required masses.
  • Evaluating the everyday risks and benefits of silver nanoparticles using provided contextual data.
  • Comparing orders of magnitude using standard form notation (powers of 10).
Question 07.1 • 1 Mark

Particle Size Comparison

Identifying the largest particle among coarse, fine, and nanoparticles

✅ Correct Answer

Tick box 1: Coarse particle

1 Mark: Coarse particle identified correctly.

💡 Key Knowledge

Order of particle sizes from largest to smallest:

  • Coarse particles (PM₁₀): 2500 nm to 10 000 nm (often called dust).
  • Fine particles (PM₂.₅): 100 nm to 2500 nm.
  • Nanoparticles: 1 nm to 100 nm (only a few hundred atoms across).
Question 07.2 • 4 Marks

Volume & Surface Area to Volume Ratio Calculation

Calculating properties of a 2 nm × 2 nm × 2 nm cubic nanoparticle

📐 Step-by-Step Calculation

Step 1: Calculate volume

Volume = length × width × height

Volume = 2 nm × 2 nm × 2 nm = 8 nm³

Step 2: Set up the initial ratio

Surface area : Volume = 24 : 8

Step 3: Simplify to the form [n : 1]

Divide both sides by 8:

24 ÷ 8 = 3

Simplest ratio = 3 : 1

✅ Mark Breakdown

  • Mark 1: Formula or substitution seen: 2³ or 2 × 2 × 2
  • Mark 2: Correct volume calculated: 8 (nm³)
  • Mark 3: Unsimplified ratio set up: 24 : 8 (allow error carried forward from incorrect volume)
  • Mark 4: Fully simplified ratio: 3 (given as 3 : 1 on the dotted line)

❌ Common Errors

  • Confusing Area and Volume: Adding the dimensions (2 + 2 + 2 = 6) instead of multiplying them.
  • Incomplete Simplification: Leaving the answer as 24 : 8 or 12 : 4 . Notice the exam answer line already ends in : 1 . You must give a single simplified number on that line!

🧠 Exam Technique

Always inspect the answer line carefully. When the question asks for the simplest ratio in the format ______ : 1 , the right-hand side is already set to 1. Simply calculate:

Surface Area ÷ Volume = 24 ÷ 8 = 3

Question 07.3 • 2 Marks

Nanoparticles as Catalysts

Explaining why smaller masses of nanoparticles are required

✅ Correct Answer

Compared with normal sized particles, the surface area to volume ratio of nanoparticles is higher / larger. [1 mark]

This means that the mass of a nanoparticle catalyst needed to have the same effect as the same catalyst made of normal sized particles is lower / less / smaller. [1 mark]

💡 Key Knowledge

As particle size decreases by a factor of 10, the surface area to volume ratio increases by a factor of 10. Because catalytic reactions take place on the surface, nanoparticles have a huge percentage of their atoms exposed at the surface.

This makes them far more reactive, meaning you need a significantly smaller mass compared to bulk materials to achieve the same catalytic effect.

Question 07.4 • 2 Marks

Silver Nanoparticles in Socks

Evaluating advantages and disadvantages using provided information

✅ Acceptable Answers

Advantage (any one):

  • Stops / reduces unpleasant smells.
  • Can stop / reduce (foot) infections.
  • Kills bacteria.

Disadvantage (any one):

  • High cost of socks / silver is very expensive.
  • Could be harmful / toxic if breathed in.

🧠 Exam Technique: Use the Provided Stem

The prompt provides five bullet points. The examiner is explicitly looking for you to link those facts to a practical benefit and a drawback:

  • "Bacteria can break down sweat to produce unpleasant smells" → Advantage: stops bad smells.
  • "Silver is very expensive" → Disadvantage: increases product cost.
  • "Small enough to be breathed in" → Disadvantage: potential lung hazard if particles shed.
Question 07.5 • 1 Mark

Standard Form & Size Comparison

Comparing an atom (1 × 10⁻¹⁰ m) and a nanoparticle (1 × 10⁻⁸ m)

✅ Correct Answer

Tick box 3: 100 times

1 Mark: Correct multiple chosen.

📐 Working with Powers of Ten

Divide the nanoparticle radius by the atomic radius:

Scale factor = (1 × 10⁻⁸) ÷ (1 × 10⁻¹⁰)

10⁻⁸ ÷ 10⁻¹⁰ = 10^(-8 - (-10)) = 10² = 100

The nanoparticle radius is 100 times larger than the atom radius.

❌ Common Errors

  • Selecting "2 times": Subtracting the exponents (-8 - (-10) = 2) and mistaking the power of 2 for a direct factor of 2.
  • Selecting "10 times": Miscounting the difference in powers of ten. Remember, each step in exponent is a factor of 10 (10¹ = 10, 10² = 100).

Topics

Chemistry · C2: Bonding, Structure and the Properties of Matter · C1: Atomic Structure and the Periodic Table

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.