AQA GCSE Chemistry Chemistry Paper 1 (Foundation), June 2023: Question 10

11 marks · Standard Demand difficulty · Short Answer

Investigate the temperature change when dissolving ammonium nitrate in water, including identifying variables, plotting data, determining initial temperature by extrapolation, and explaining measurement uncertainty.

Practise this question

Question

Question 10 is an 11-mark multi-part practical question about temperature changes when dissolving ammonium nitrate in water. It presents a 6-step method using a polystyrene cup, followed by 10.1 asking for independent and dependent variables. Table 6 provides mass of ammonium nitrate added (4.0 to 24.0 g) versus lowest temperature reached (18.2 to 10.6 °C). 10.2 provides a grid (Figure 11) for plotting lowest temperature against mass added with a line of best fit. 10.3 asks to extrapolate the line to determine initial water temperature. 10.4 asks how data shows the reaction is endothermic. Table 7 lists 4 repeat trials for 8.0 g with a mean of 16.5 °C. 10.5 asks to explain the ± 0.3 °C uncertainty, and 10.6 asks to identify the type of error (random, systematic, or zero error).
Question text

10 This question is about temperature changes.

A student investigated the change in temperature of a solution when different masses

of ammonium nitrate were dissolved in water.

This is the method used.

1. Measure 200 cm3 of water into a polystyrene cup.

2. Measure the temperature of the water.

3. Add 4.0 g of ammonium nitrate to the water.

4. Stir the solution until all the ammonium nitrate has dissolved.

5. Measure the lowest temperature reached by the solution.

6. Repeat steps 1 to 5 with different masses of ammonium nitrate.

10.1 Give the independent variable and the dependent variable in the investigation.

[2 marks]

Independent variable

Dependent variable

Table 6 shows the results.

Table 6

Mass of ammonium nitrate Lowest temperature of solution

added in grams in ºC

4.0 18.2

8.0 16.2

12.0 15.2

16.0 13.6

20.0 12.4

24.0 31 10.6

10.2 Plot the data from Table 6 on Figure 11.

Draw a line of best fit.

*30* [3 marks]

Figure 11

10.3 Determine the initial temperature of the water.

You should extend your line of best fit on Figure 11.

[2 marks]

Initial temperature of the water = °C

10.4 How do the results show that dissolving ammonium nitrate in water is endothermic?

[1 mark]

The student repeated the experiment three more times.

Table 7 shows the results for 8.0 g of ammonium nitrate.

Table 7

Trial 1 Trial 2 Trial 3 Trial 4 Mean

Lowest temperature

16.2 16.6 16.8 16.4 16.5

of solution in ºC

10.5 The student recorded the mean lowest temperature of the solution for 8.0 g of

ammonium nitrate as 16.5 ± 0.3 ºC.

Explain why the student included ± 0.3 ºC after the mean lowest temperature.

[2 marks]

10.6 What type of error is shown by the results in Table 7?

[1 mark]

Tick ( ) one box.

Random error

Systematic error

Zero error

Mark scheme

Show the mark scheme Mark scheme for Question 10: 10.1 gives 1 mark for independent variable (mass of ammonium nitrate) and 1 mark for dependent variable (lowest temperature reached). 10.2 gives 2 marks for plotting all 6 points correctly within half a small square (1 mark for 4-5 points) and 1 mark for a line of best fit. 10.3 awards 1 mark for extrapolating line to y-axis and 1 mark for correctly reading value at y-intercept. 10.4 awards 1 mark for temperature decreased. 10.5 awards 1 mark for stating ±0.3 °C is the uncertainty and 1 mark for stating it is the range about the mean (16.8 = 16.5 + 0.3 and 16.2 = 16.5 - 0.3). 10.6 awards 1 mark for 'Random error'. Total marks = 11.

AO /

Question Answers Extra information Mark

Spec. Ref.

10.1 (independent variable) AO1

mass (of ammonium nitrate) 1 4.5.1.1

RPA4

(dependent variable)

(lowest) temperature (reached allow change in temperature (of 1

by solution) solution)

AO /

Spec. Ref.

10.2 all 6 points plotted correctly allow a tolerance of ± ½ a small 2 AO2

square

allow 1 mark for 4 or 5 points

plotted correctly

AO3

line of best fit 1

4.5.1.1

RPA4

AO /

Spec. Ref.

10.3 line extrapolated to y-axis 1 AO3

(initial temperature)

value for temperature where allow a tolerance of ± ½ a small 1

AO2

extrapolated line meets y-axis square

4.5.1.1

RPA4

AO /

Spec. Ref.

10.4 temperature decreased ignore correct references to 1 AO1

energy transfer 4.5.1.1

– HEMISTRY – – RPA4

AO /

Spec. Ref.

24 10.5 (0.3 °C) is the uncertainty 1 AO2

4.3.1.4

(because 0.3 °C) is the range allow values are (a maximum of) 4.5.1.1

about the mean value 0.3 (°C) either side of the mean RPA4

allow (because)

16.8 = 16.5 + 0.3

and

16.2 = 16.5 – 0.3

AO /

Spec. Ref.

10.6 random error 1 AO3

4.5.1.1

RPA4

– HEMISTRY – –

Total Question 10 11

Question 11

How to answer it

Dissolving Ammonium Nitrate: Temperature Changes & Practical Skills

What this question tests

Required Practical 4 (Temperature Changes) & Mathematical / Working Scientifically Skills:

  • Identifying independent and dependent variables in an investigation.
  • Accurate graph plotting (scaling, plotting points to ± ½ small square, and drawing a straight line of best fit).
  • Extrapolating a line of best fit to determine an intercept (initial water temperature).
  • Linking experimental observations (temperature drop) to endothermic reactions.
  • Calculating and explaining uncertainty from repeated experimental trials.
  • Categorising experimental errors (distinguishing random error from systematic and zero error).
Question 10.1

Variables in the Investigation

Identifying the independent and dependent variables [2 marks]

✅ Correct Answer

  • Independent variable: Mass of ammonium nitrate (added) [1 mark]
  • Dependent variable: Lowest temperature reached (by the solution) or change in temperature [1 mark]

💡 Key Knowledge

  • Independent Variable: The variable that you deliberately change (the mass added: 4.0 g, 8.0 g, etc.).
  • Dependent Variable: The variable that is measured for each change (the temperature).
  • Control Variables: Factors kept constant to ensure a fair test (e.g., volume of water = 200 cm³).

🧠 Exam Technique

Look at the table headings! In standard AQA tables, the first column is almost always the independent variable, and the second column is the dependent variable.

❌ Common Errors

  • Mixing up the two variables.
  • Writing "temperature" without specifying "lowest temperature" or "temperature change".
  • Giving control variables like "volume of water".
Mark scheme breakdown: 1 mark for independent variable (mass), 1 mark for dependent variable (lowest temperature / change in temperature).
Question 10.2

Plotting Data & Line of Best Fit

Graph plotting on Figure 11 [3 marks]

✅ Correct Answer & Description

  • Points plotted:
    (4.0, 18.2) , (8.0, 16.2) , (12.0, 15.2) ,
    (16.0, 13.6) , (20.0, 12.4) , (24.0, 10.6)
  • All 6 points plotted within ± ½ small square [2 marks]
    (4 or 5 points correct gives 1 mark).
  • Line of Best Fit: A single, straight line drawn with a ruler passing evenly between all points [1 mark].

🧠 Graph Skills Checklist

  • Use a sharp pencil and draw small neat crosses ( × ).
  • Check axis scale: on the y-axis, 10 small squares = 2 °C, so 1 small square = 0.2 °C.
  • On the x-axis, 10 small squares = 5 g, so 2 small squares = 1.0 g.
  • Do not "dot-to-dot" the points; use a clear transparent ruler to balance points on either side.

❌ Common Errors

  • Misreading the scale: Assuming 1 small square = 0.1 °C instead of 0.2 °C.
  • Drawing a thick, fuzzy, or freehand line of best fit instead of using a sharp pencil and ruler.
  • Forcing the line to start at (0, 0) — dissolving 0 g of solute cannot result in 0 °C!
Mark scheme breakdown: 2 marks for plotting (6 points = 2 marks, 4–5 points = 1 mark; tolerance ± ½ small square), 1 mark for a straight line of best fit.
Question 10.3

Extrapolating the Best Fit Line

Determining initial water temperature [2 marks]

✅ Correct Answer

  • Line of best fit extended backwards to cross the y-axis (mass = 0 g) [1 mark].
  • Correct temperature read from y-axis intercept: typically 19.6 °C to 20.0 °C (depending on candidate's drawn line, allowed within ± ½ small square) [1 mark].

💡 Why Extrapolate to 0 g?

When the mass of ammonium nitrate added is 0 g, no reaction has occurred. Therefore, the y-intercept represents the initial starting temperature of the pure water before any solute was added.

🧠 Examiner Insight

The question explicitly instructs: "You should extend your line of best fit on Figure 11." Examiners check the graph paper! If your line does not touch the y-axis on Figure 11, you lose Mark 1, even if you wrote down an estimate on the answer line.

Mark scheme breakdown: 1 mark for extending line to y-axis; 1 mark for reading the intercept accurately (± ½ small square).
Question 10.4

Endothermic Energy Changes

How the results show an endothermic process [1 mark]

✅ Correct Answer

The temperature decreased (or temperature went down / solution got colder) [1 mark].

❌ Common Errors

  • Giving a theoretical definition instead of referring to results: writing "energy was taken in from the surroundings" does not directly answer how the results show it. (The mark scheme states: ignore correct references to energy transfer).
  • Vague statements like "the temperature changed" without stating that it dropped.
Mark scheme breakdown: 1 mark for stating that the temperature decreased / fell.
Question 10.5

Explaining Experimental Uncertainty

Why the result is recorded as 16.5 ± 0.3 °C [2 marks]

📐 Step-by-Step Calculation of Uncertainty

Table 7 values for 8.0 g: Trial 1 = 16.2 °C, Trial 2 = 16.6 °C, Trial 3 = 16.8 °C, Trial 4 = 16.4 °C. Mean = 16.5 °C.

  1. Step 1: Calculate Range
    Range = Maximum value − Minimum value = 16.8 − 16.2 = 0.6 °C
  2. Step 2: Calculate Uncertainty
    Uncertainty = Range ÷ 2 = 0.6 ÷ 2 = 0.3 °C
  3. Step 3: Check Spread About the Mean
    16.5 + 0.3 = 16.8 °C (highest trial) and 16.5 − 0.3 = 16.2 °C (lowest trial).

✅ What to Write for 2 Marks

  • Mark 1: (± 0.3 °C) is the uncertainty.
  • Mark 2: Because 0.3 °C is the range about the mean value (or values are a maximum of 0.3 °C either side of the mean / 16.8 = 16.5 + 0.3 and 16.2 = 16.5 − 0.3 ).

❌ Common Errors

  • Calling ± 0.3 °C an "error" or "mistake" rather than the scientific term uncertainty.
  • Stating it represents the range (0.6 °C is the range; 0.3 °C is half the range or the range around the mean).
Mark scheme breakdown: 1 mark for naming "uncertainty", 1 mark for explaining it as the range / spread about the mean.
Question 10.6

Types of Experimental Error

Identifying error type from repeated trials [1 mark]

✅ Correct Answer

Tick: Random error [1 mark]

💡 Definitions to Remember

  • Random error: Causes readings to be spread unpredictably about the mean (e.g. slight timing differences, draughts, stirring variations). Repeating and calculating a mean reduces their effect.
  • Systematic error: Causes readings to differ from the true value by a consistent amount each time (e.g. scale miscalibration, uninsulated cup losing heat constantly).
  • Zero error: A specific systematic error where a measuring instrument gives a non-zero reading when the true value is zero (e.g. balance not tared).
Mark scheme breakdown: 1 mark for correctly ticking "Random error".

Topics

Chemistry · Required Practicals · C5: Energy Changes · C3: Quantitative Chemistry · Required Practicals

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.