AQA GCSE Chemistry Chemistry Paper 2 (Foundation), June 2023: Question 4
9 marks · Low Demand difficulty · Short Answer
Explain observations and mass changes during the thermal decomposition of calcium hydroxide and analyze the energy changes of the reversible reaction.
Practise this questionQuestion
Question text
04 This question is about a reversible reaction.
A student heated calcium hydroxide to produce calcium oxide and water vapour.
This is the method used.
1. Add 2.00 g of calcium hydroxide into a test tube.
2. Heat the test tube and contents for 1 minute using a Bunsen burner.
3. Allow the test tube and contents to cool.
4. Weigh the test tube and contents.
5. Repeat steps 2 to 4 five more times.
04.1 Table 3 gives the appearance of the reactant and of the products.
Table 3
Compound Appearance
Reactant calcium hydroxide white powder
calcium oxide white powder
Products
water vapour colourless gas
The student looked at the test tube and contents during heating.
The student could not tell that a chemical reaction was taking place by looking at the
test tube and contents.
Give two reasons why.
Use the information in Table 3.
[2 marks]
04.2 Accurate results are not produced if solid powders escape from the test tube
during heating.
Suggest why sealing the test tube with a stopper is not a good way of preventing the
*18* solid powders from escaping.
[1 mark]
04.3 The student wanted to calculate the mass of the contents of the test tube after each
minute of heating.
The student weighed the test tube and contents after each minute of heating.
What other measurement is also needed to calculate the mass of the contents of the
test tube?
[1 mark]
Tick ( ) one box.
The change in mass of the contents of the test tube at the end
The mass of the contents of the test tube at the start
The mass of the empty test tube 20
The student heated 2.00 g of calcium hydroxide to produce calcium oxide and
water vapour.
Table 4 shows the results.
Table 4
Total heating time Mass of contents of
in minutes test tube in grams
02.00
11.76
21.64
31.56
41.52
51.51
61.51
04.4 Complete the sentence.
Choose the answer from the box.
Use Table 4.
[1 mark]
3 minutes 4 minutes 5 minutes 6 minutes
The minimum heating time needed for all of the calcium hydroxide to be changed into
calcium oxide and water vapour is .
04.5 Calculate the total mass of water vapour produced by heating the calcium hydroxide.
Use Table 4.
[2 marks]
Mass = g
The word equation for the reaction is:
*20* calcium hydroxide ⇌ calcium oxide + water
The reaction is reversible.
When 4.00 g of calcium hydroxide is completely changed into calcium oxide and
water:
• 3.03 g of calcium oxide is produced
• 5.90 kJ of energy is taken in from the surroundings.
04.6 3.03 g of calcium oxide reacts completely with water to produce 4.00 g of calcium
hydroxide.
How much energy is transferred to the surroundings in this reaction?
[1 mark]
Tick ( ) one box.
Less than 5.90 kJ
5.90 kJ
More than 5.90 kJ
04.7 The forward reaction takes in energy from the surroundings.
Complete the sentence.
Choose the answer from the box.
[1 mark]
combustion endothermic exothermic
The forward reaction is .
Mark scheme
Show the mark scheme
AO /
Question Answers Extra information Mark
Spec. Ref.
04.1 water (vapour) is colourless allow water vapour cannot be 1 AO3
seen 4.6.2.1
(calcium hydroxide and calcium 1
oxide are) both white (powders /
solids)
or
there is no change in the
appearance of the powder /
solids
AO /
Spec. Ref.
04.2 the stopper would be pushed allow test tube may break 1 AO3
out
4.6.2.1
AO /
Spec. Ref.
04.3 the mass of the empty test tube 1 AO2
4.6.2.1
AO /
Spec. Ref.
04.4 5 minutes 1 AO2
4.6.2.1
AO /
Spec. Ref.
04.5 (mass =) 2.00 – 1.51 1 AO2
4.3.1.1
= 0.49 (g) – HEMISTRY – 1 – 4.6.2.1
AO /
Answers Extra information Mark
Question Spec. Ref.
04.6 5.90 kJ 1 AO2
4.6.2.2 13
AO /
Answers Extra information Mark
Question Spec. Ref.
04.7 endothermic 1 AO2
4.6.2.2
– – 8462/2F –
Total Question 4 9
Question 5
How to answer it
Reversible Reactions, Heating to Constant Mass & Energy Changes
- Thermal decomposition: Explaining experimental observations when heating calcium hydroxide.
- Lab safety & apparatus: Understanding gas pressure hazards in closed systems.
- Quantitative practical skills: Identifying necessary measurements and using the concept of "heating to constant mass".
- Conservation of mass: Calculating the mass of gas lost during heating.
- Reversible reactions & energy transfers: Applying energy conservation and defining endothermic reactions.
Visual Evidence of a Chemical Reaction
Explaining why no visible change is observed during heating
✅ Mark Scheme Answers
Any two of the following points (1 mark each):
- Water (vapour) is colourless (allow: cannot be seen).
- Both calcium hydroxide and calcium oxide are white powders / solids (or: there is no change in the appearance of the solid).
🧠 Exam Technique: Use the Table!
The prompt explicitly commanded: "Use the information in Table 3."
Never write generic answers like "atoms are rearranged". Look directly at the table columns: reactant solid is white, product solid is white, and the gas produced is invisible/colourless.
❌ Common Errors
- Writing "a gas was made" without mentioning that it is colourless / invisible.
- Stating that "nothing was produced" (products are formed, they just look identical or escape invisibly).
💡 Key Knowledge
A chemical reaction is usually identified by observations like colour changes, effervescence (bubbles in liquids), or temperature changes. When a white solid breaks down into another white solid and a colourless gas, no visible change occurs in the tube.
Apparatus Hazards: Sealing the Test Tube
Why stoppers must never be used when heating gas-producing reactions
✅ Mark Scheme Answer
Any one of the following (1 mark):
- The stopper would be pushed out / pop off.
- The test tube may break / shatter / burst.
- Allow: pressure would build up inside the tube.
❌ Common Errors
- Vague answers such as "it is dangerous" without specifying why.
- Claiming the rubber stopper would just "melt" (while possible, this does not address the main physical hazard of gas pressure).
Determining Contents Mass
Selecting the missing measurement
✅ Correct Tick Box
☑ The mass of the empty test tube (1 mark)
🧠 Exam Technique: Subtraction Logic
To find the mass of the contents inside a container:
Mass of contents = (Mass of tube + contents) − (Mass of empty tube)
Without knowing what the empty glass test tube weighs, you cannot find the exact mass of powder inside it.
❌ Incorrect Options
- "The change in mass at the end" – this is a calculated result, not a direct measurement needed after each minute.
- "The mass of contents at start" – this was already given in the question as 2.00 g.
Heating to Constant Mass
Determining when decomposition is complete
✅ Correct Answer
The minimum heating time needed is 5 minutes (1 mark)
💡 What is "Heating to Constant Mass"?
Look at Table 4:
- At 4 minutes: 1.52 g
- At 5 minutes: 1.51 g
- At 6 minutes: 1.51 g
The mass stops decreasing at 5 minutes. This proves all water vapour has escaped and the reaction has finished.
❌ Common Error: Choosing 6 minutes
Students often choose 6 minutes because it is the end of the table. However, the question asked for the minimum time. The mass had already reached its final constant value at 5 minutes.
Calculating the Mass of Water Vapour
Applying conservation of mass to open systems
📐 Step-by-Step Calculation
- Identify initial and final constant masses:
Initial mass at 0 minutes = 2.00 g
Final constant mass of solid = 1.51 g - Subtract final mass from initial mass (1 mark):
Mass of water vapour = 2.00 − 1.51 - State final value with correct units (1 mark):
0.49 g
• 1 mark: Evidence of subtraction 2.00 − 1.51
• 1 mark: Correct answer 0.49 (g)
Energy in Reversible Reactions
Conservation of energy and reaction classification
✅ Question 04.6 Answer
Tick box: ☑ 5.90 kJ (1 mark)
✅ Question 04.7 Answer
The forward reaction is endothermic (1 mark)
💡 Key Principle: Reversible Reactions & Energy
For any reversible reaction:
- If the forward reaction is endothermic (takes in energy, +5.90 kJ), the reverse reaction must be exothermic (releases energy, −5.90 kJ).
- Energy cannot be created or destroyed (Law of Conservation of Energy), so the numerical value (5.90 kJ) stays identical!
❌ Common Errors
- Selecting "Less than 5.90 kJ" thinking that energy is "lost" or reaction wasn't 100% efficient.
- Confusing endothermic and exothermic. Remember: Exothermic reactions exit heat (transfer energy to surroundings).
Topics
Chemistry · C3: Quantitative Chemistry · C5: Energy Changes · C6: The Rate and Extent of Chemical Change
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 2 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.