AQA GCSE Chemistry Chemistry Paper 2 (Foundation), June 2023: Question 9

11 marks · Standard Demand difficulty · Short Answer

Analyze energy released by combustion of alcohols, test for carbon dioxide, and examine the reactions and structure of ethanoic acid.

Practise this question

Question

Question 9 presents Table 8 showing six alcohols (ethanol to heptanol), their molecular formulas, and the energy released in kJ/g when 1.00 g is burned. Question 09.1 asks to calculate the mass of ethanol burned to release the same energy as 1.00 g of heptanol. 09.2 requires plotting the data on a grid with 'Energy released in kJ/g' on the y-axis (28 to 43) and 'Number of carbon atoms' on the x-axis (1 to 8). 09.3 asks to estimate the energy released by octanol using the graph. 09.4 and 09.5 ask for the chemical identity of limewater from a box of options and the result when carbon dioxide is bubbled through it. 09.6 asks what ethanol is reacted with to produce ethanoic acid. 09.7 asks to complete the displayed structural formula of the -COOH functional group. 09.8 asks to match compounds (ethanol, sodium carbonate) to their products when reacted with ethanoic acid.
Question text

09 This question is about alcohols and carboxylic acids.

Alcohols are used as fuels.

A student burned 1.00 g of six alcohols and determined the energy released

from each.

Table 8 shows the results.

Table 8

Formula of one molecule of

Alcohol Energy released in kJ/g

the alcohol

Ethanol C2H5OH 29.6

Propanol C3H7OH 33.6

Butanol C4H9OH 36.1

Pentanol C5H11OH 37.7

Hexanol C6H13OH 38.9

Heptanol C7H15OH 39.8

09.1 Calculate the mass of ethanol that must be burned to release the same amount of

energy as burning 1.00 g of heptanol.

[2 marks]

Mass = g

09.2 The energy released in kJ/g varies with the number of carbon atoms in one molecule

of each alcohol.

Plot the data from Table 8 on Figure 835.

[2 marks]

Figure 8

09.3 Estimate the energy released in kJ when 1.00 g of octanol (C8H17OH) is burned.

Use Figure 8.

[1 mark]

Energy released = kJ

Carbon dioxide is produced when alcohols are burned.

Carbon dioxide is identified by bubbling the gas through limewater.

*0359.*4 Complete the sentence.

Choose the answer from the box.

[1 mark]

calcium chloride calcium hydroxide calcium nitrate calcium sulfate

Limewater is an aqueous solution of .

09.5 Give the result of the test when carbon dioxide is bubbled through limewater.

[1 mark]

Ethanoic acid can be produced from ethanol.

09.6 What is reacted with ethanol to produce ethanoic acid?

[1 mark]

Tick ( ) one box.

A halogen

An alkali metal

An oxidising agent

Water

09.7 Ethanoic acid contains the functional group –COOH

Complete the displayed structural formula of this functional group.

[1 mark]

09.8 Ethanoic acid reacts with different compounds.

Draw one line from each compound to a product of the reaction of the compound with

ethanoic acid.

[2 marks]

Product of the reaction

Compound

with ethanoic acid

Carbon dioxide

Ethene

*37* Ethanol

Ethyl ethanoate

Sodium carbonate

Hydrogen

Poly(ethene)

Mark scheme

Show the mark scheme Mark scheme for Question 9 indicates: 09.1 awards 1 mark for 39.8 / 29.6 and 1 mark for 1.34 g; 09.2 awards 2 marks for plotting all six points correctly within half a small square tolerance (1 mark for 4 or 5 points); 09.3 awards 1 mark for 40.6 kJ (accepting 40.4 to 40.8 kJ); 09.4 awards 1 mark for calcium hydroxide; 09.5 awards 1 mark for milky or cloudy; 09.6 awards 1 mark for 'an oxidising agent'; 09.7 awards 1 mark for C=O double bond and C-O single bond; 09.8 awards 1 mark for a line from ethanol to ethyl ethanoate, and 1 mark for sodium carbonate to carbon dioxide.

AO /

Question Answers Extra information Mark

Spec. Ref.

09.1 (mass =) AO2

39.8 1

(× 1) 4.7.2.3

29.6

= 1.34 (g) allow 1.34459459 (g) correctly 1

rounded to at least 2 significant

figures

AO /

Spec. Ref.

09.2 all six points plotted correctly allow a tolerance of ± ½ a small 2 AO2

square

4.7.2.3

allow 1 mark for four or five

points plotted correctly

AO /

Spec. Ref.

09.3 40.6 (kJ) allow a value in the range 1 AO2

40.4 – 40.8 (kJ) 4.7.2.3

allow a value consistent with the

plotted points

AO /

Spec. Ref.

09.4 calcium hydroxide 1 AO1

4.8.2.3

AO /

Spec. Ref.

09.5 (limewater turns) milky / cloudy allow white precipitate (formed) 1 AO1

4.8.2.3

allow calcium carbonate is

produced– HEMISTRY – –

AO /

Spec. Ref.

09.6 an oxidising agent 1 AO1 23

4.7.2.3

AO /

Spec. Ref.

09.7 1 AO1

4.7.2.4

AO /

Question Answers Mark

Spec. Ref.

09.8 AO1

4.7.2.4

do not accept more than one line from a box on the left

– – 8462/2F –

Total Question 9 11

Question 10

How to answer it

Alcohols, Combustion & Carboxylic Acids

REVISION SUMMARY

What this question tests

This question assesses your understanding of organic chemistry fundamentals: comparing energy values released by burning fuels, plotting and extrapolating experimental data on a line graph, chemical tests for carbon dioxide (limewater reaction), structural formulas of carboxylic acid functional groups ( -COOH ), oxidation of alcohols, and characteristic reactions of ethanoic acid with carbonates and alcohols.

Part 09.1 • 2 Marks

Calculating Required Mass of Ethanol

Quantitative comparison of fuel energy release

📐 Step-by-Step Calculation

  1. Find total energy needed: Burning 1.00 g of heptanol produces 39.8 kJ .
  2. Find energy per gram of ethanol: From Table 8, 1.00 g of ethanol yields 29.6 kJ .
  3. Set up calculation:
    Mass = 39.8 kJ ÷ 29.6 kJ/g = 1.34459... g
  4. Round appropriately: 1.34 g (to 3 sig figs).

❌ Common Errors

  • Inverting the division: Calculating 29.6 ÷ 39.8 = 0.74 g . Ethanol releases less energy per gram, so you need more than 1.00 g. Always sanity check your answer!
  • Incorrect rounding: Writing 1.3 without showing a full value first, or truncating to 1.33.
Mark Scheme:
• 1 Mark: 39.8 / 29.6 (or equivalent method)
• 1 Mark: 1.34 (g) (allow answers rounded correctly to at least 2 sig figs, e.g. 1.3 or 1.345)
Parts 09.2 & 09.3 • 3 Marks

Plotting Data & Extrapolating a Trend

Data presentation and predicting values for higher homologues

🧠 Exam Technique: Plotting Points (09.2)

  • Look carefully at the scale:
    • X-axis: 1 large block = 1 carbon atom (each small square = 0.1).
    • Y-axis: 10 small squares = 2 kJ/g, so 1 small square = 0.2 kJ/g.
  • Plot all 6 points using a sharp pencil and neat small crosses (×):
    • Ethanol (2, 29.6) — 3 small squares above 29
    • Propanol (3, 33.6) — 3 small squares above 33
    • Butanol (4, 36.1) — half a square above 36
    • Pentanol (5, 37.7) — 3.5 small squares above 37
    • Hexanol (6, 38.9) — 4.5 small squares above 38
    • Heptanol (7, 39.8) — 1 small square below 40

✅ Extrapolation: Estimating Octanol (09.3)

Extend the smooth curved line of best fit naturally to carbon number 8.

  • Accepted value: 40.6 kJ
  • Allowed range: 40.4 to 40.8 kJ
  • Notice the rate of increase is levelling off as carbon chain length increases. A straight line extrapolation will give too high a value.
Mark Scheme:
• 09.2: 2 marks for all 6 points plotted correctly within ± ½ a small square (1 mark for 4 or 5 points correct).
• 09.3: 1 mark for any value in the range 40.4 to 40.8 kJ (or consistent with student's drawn curve).
Parts 09.4 & 09.5 • 2 Marks

Limewater & Carbon Dioxide Test

Recall of standard inorganic reagents and qualitative gas tests

💡 Key Knowledge (09.4)

Limewater is a dilute aqueous solution of calcium hydroxide: Ca(OH)₂ (aq) .

Do not confuse this with calcium carbonate (limestone/chalk) or calcium oxide (quicklime).

✅ Expected Observation (09.5)

When carbon dioxide is bubbled through limewater, the solution turns:

milky OR cloudy (or forms a white precipitate ).

Why? Insoluble solid calcium carbonate forms:
Ca(OH)₂ (aq) + CO₂ (g) → CaCO₃ (s) + H₂O (l)

Mark Scheme:
• 09.4: calcium hydroxide (1 mark)
• 09.5: (limewater turns) milky / cloudy or white precipitate (1 mark)
Parts 09.6 & 09.7 • 2 Marks

Oxidation of Alcohols & Structural Formula

Ethanol to ethanoic acid conversion and functional group display

💡 Reagent for Oxidation (09.6)

Alcohols are oxidised to carboxylic acids by reacting with an oxidising agent (such as acidified potassium dichromate).

They can also oxidise slowly when exposed to oxygen in the air (microbial oxidation).

🧠 Completing the Displayed Formula (09.7)

You must show all covalent bonds for the carboxylic acid group:

      O
     //
— C
     \
      O — H
  • Draw a double bond ( = ) between the carbon atom and top oxygen.
  • Draw a single bond ( — ) between the carbon atom and bottom oxygen.
Mark Scheme:
• 09.6: Tick box: An oxidising agent (1 mark)
• 09.7: Double bond to top O and single bond to bottom O (1 mark)
Part 09.8 • 2 Marks

Reactions of Ethanoic Acid

Linking reagents to their specific organic and inorganic products

✅ Matching Lines

  • Ethanol ➔ Ethyl ethanoate
    Carboxylic acid + alcohol ➔ ester + water
  • Sodium carbonate ➔ Carbon dioxide
    Acid + carbonate ➔ salt + water + carbon dioxide

❌ Common Errors to Avoid

  • Drawing multiple lines: The question states "Draw one line from each compound". Drawing two lines from one box automatically cancels that mark!
  • Confusing esters with polymers: Linking ethanol to poly(ethene) or ethene. Ethanol + ethanoic acid produces an ester (sweet-smelling ethyl ethanoate).
  • Confusing acid-metal with acid-carbonate: Hydrogen gas is produced when acids react with metals, not carbonates! Carbonates always produce carbon dioxide.
Mark Scheme:
• 1 Mark: Line from Ethanol to Ethyl ethanoate
• 1 Mark: Line from Sodium carbonate to Carbon dioxide

Topics

Chemistry · C7: Organic Chemistry · C8: Chemical Analysis

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 2 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.