AQA GCSE Chemistry Chemistry Paper 1 (Higher), 2024: Question 5

10 marks · Standard Demand difficulty · Short Answer

Describe the formation of calcium chloride, explain why solid calcium chloride cannot be electrolysed, identify electrolysis products, select the correct half-equation for the positive electrode, and explain the movement of ions during the electrolysis of copper chromate.

Practise this question

Question

A multi-part chemistry question about ionic compounds and electrolysis. It includes a request to describe the formation of calcium chloride, explain why solid calcium chloride cannot be electrolysed, identify the product at the negative electrode, choose a half-equation from a multiple-choice list, and explain the results of an electrolysis experiment involving copper chromate shown in two diagrams (Figure 4 and Figure 5).
Question text

05 This question is about ionic compounds and electrolysis.

Calcium chloride is an ionic compound.

05.1 Calcium and chlorine react to produce calcium chloride.

Describe what happens to calcium atoms and chlorine atoms when the ionic

compound calcium chloride is formed.

[4 marks]

05.2 Solid calcium chloride cannot be electrolysed.

Give one reason why.

[1 mark]

05.3 Name the product formed at the negative electrode when aqueous calcium chloride

solution is electrolysed.

[1 mark]

05.4 What is the half equation for the reaction at the positive electrode when aqueous

calcium chloride solution is electrolysed?

[1 mark]

Tick ( ) one box.

2 Cl¯ → Cl + 2 e–

Cl + 2 e– → 2 Cl¯

4 OH¯ → O + 2 H O + 4 e–

O + 2 H O + 4 e– → 4 OH¯

22 16

05.5 A student investigated the electrolysis of green copper chromate solution.

Figure 4 shows the apparatus.

Figure 4

Figure 5 shows the results.

Figure 5

Copper chromate solution contains the ions Cu2+ and CrO 2–

Explain the results shown in Figure 5.

[3 marks]

Mark scheme

Show the mark scheme A table showing the mark scheme for the five-part question. It provides specific points for describing electron transfer in calcium chloride, the immobility of ions in solids, the identification of hydrogen as the product, the correct half-equation for chloride ions, and the explanation of ion migration based on charge and color for copper chromate.

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 each calcium atom loses two 1 AO2

electrons 4.2.1.2

allow 1 mark for calcium

atoms lose electrons and

(and) each chlorine atom gains chlorine atoms gain electrons 1

one electron

(so) one calcium atom reacts 1

with two chlorine atoms

(to form) Ca2+ ions and Cl- ions 1

or

(to form) calcium ion(s) and allow (to form) ions with full

chloride ion(s) outer shells

allow energy level for shell

AO /

Spec. Ref.

05.2 the ions cannot move allow the ions are in fixed 1 AO1

positions 4.2.2.3

4.4.3.1

4.4.3.2

AO /

Spec. Ref.

05.3 hydrogen allow H2 1 AO2

4.4.3.4

RPA3

AO /

Spec. Ref.

05.4 2 Cl– → Cl + 2 e– 1 AO2

4.1.1.1

4.4.3.4

4.4.3.5

– – – RPA3

AO /

16 Spec. Ref.

allow cathode for negative

05.5 electrode AO3

allow anode for positive 4.4.3.1

electrode

allow attraction for movement

Cu2+ / copper ions are blue 1

and

CrO 2– / chromate ions are

yellow

(because) Cu2+ / copper ions 1

move to the negative electrode

(and also) CrO 2– / chromate 1

ions move to the positive

electrode

Total Question 5 10

How to answer it

Ionic Bonding and Electrolysis Essentials

What this question tests

This question assesses your ability to describe ionic bonding via electron transfer, explain electrical conductivity in different states, apply the rules of aqueous electrolysis, and explain ion migration based on charge and colour.

Part (05.1)

Formation of Calcium Chloride

Describing ionic bonding (4 Marks)

The Perfect Answer

  • Calcium atoms lose two electrons.
  • Each chlorine atom gains one electron.
  • Two chlorine atoms react with every one calcium atom.
  • This forms Ca²⁺ and Cl⁻ ions (with full outer shells).

Exam Technique

When asked to describe bonding, always mention:

  1. Direction: Who loses and who gains?
  2. Number: Exactly how many electrons are moved?
  3. Ratio: How many of each atom are needed to balance the charge?

Common Error: "Sharing"

Never use the word "share" when describing calcium chloride. It is ionic. Sharing only happens in covalent bonding. If you mention sharing, you will likely lose the marks for electron transfer.

Part (05.2)

Conductivity of Solids

Why can't solid calcium chloride be electrolysed? (1 Mark)

Key Knowledge

For electrolysis to happen, the electrolyte must contain mobile ions to carry the charge.

Correct Answer

The ions are in fixed positions (or the ions cannot move).

Common Error: Moving Electrons

Students often say "electrons cannot move." In ionic compounds, conductivity is about ions moving, not electrons. Metals conduct via electrons; ionic liquids conduct via ions.

Part (05.3) & (05.4)

Aqueous Electrolysis Rules

Predicting products and half equations

The "Aqueous Rules"

At the Negative Electrode (-): Hydrogen is produced IF the metal is more reactive than hydrogen (e.g., Calcium).

At the Positive Electrode (+): A Halogen is produced IF halide ions (Cl⁻, Br⁻, I⁻) are present.

Answers

05.3: Hydrogen (H₂)

05.4: 2Cl⁻ → Cl₂ + 2e⁻

Half Equation Tip

The positive electrode is where oxidation (loss of electrons) happens. The electrons must be on the right-hand side of the arrow. 2Cl⁻ → Cl₂ + 2e⁻ shows two negative ions losing their extra electrons to become a neutral molecule.

Part (05.5)

Ion Migration (Copper Chromate)

Explaining the movement of colours (3 Marks)

How to structure this 3-mark answer

You must link the colour to the ion, and then the ion to the electrode.

Step-by-Step Explanation

  1. Identify Colours: Cu²⁺ ions are blue and CrO₄²⁻ ions are yellow.
  2. Negative Electrode: Blue Cu²⁺ ions move to the negative electrode because they are positively charged (opposite charges attract).
  3. Positive Electrode: Yellow CrO₄²⁻ ions move to the positive electrode because they are negatively charged.

Visualizing the Result

The green drop "splits." The blue part moves left (-), and the yellow part moves right (+). This proves that the compound is made of charged particles (ions) that are free to move in the solution.

Topics

Chemistry · C2: Bonding, Structure and the Properties of Matter · C4: Chemical Changes

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.