AQA GCSE Chemistry Chemistry Paper 1 (Higher), 2024: Question 9

12 marks · Standard Demand difficulty · Short Answer

This question covers properties of weak acids, pH changes during dilution, titration procedures, a titration calculation involving moles and concentration, and an explanation of the reactivity of group 2 metals.

Practise this question

Question

A multi-part chemistry question numbered 09. The question asks students to define a weak acid, explain pH changes upon dilution, list steps for a titration, calculate the volume of HCl needed for a specific titration, and explain the reactivity difference between calcium and magnesium. The question includes a chemical equation: NaOH + HCl -> NaCl + H2O.
Question text

09 This question is about acids and their reactions.

Acids can be either weak or strong.

09.1 What is meant by ‘a weak acid’?

[2 marks]

09.2 Explain what happens to the pH of an acid as the acid is diluted with water.

[2 marks]

09.3 A student does a titration to find the volume of acid needed to neutralise an alkali.

The student fills a burette with the acid.

Give three more steps the student must do before adding the acid to the alkali from

the burette.

You should name any equipment used.

[3 marks]

09.4 The student titrated a solution containing 0.0045 moles of sodium hydroxide with

*27* 0.15 mol/dm3 hydrochloric acid.

The equation for the reaction is:

NaOH + HCl → NaCl + H2O

Calculate the volume of hydrochloric acid in cm3 needed in the titration.

[2 marks]

29 Volume of acid = cm3

09.5 A calcium atom is larger than a magnesium atom.

Explain why calcium reacts more vigorously than magnesium with hydrochloric acid of

the same concentration.

[3 marks]

Mark scheme

Show the mark scheme A table showing the mark scheme for question 9, parts 09.1 to 09.5. It provides the required answers, extra information for marking, the number of marks per section, and the AO/Spec references. The total marks for the question are 12.

Question 9

AO /

Question Answers Extra information Mark

Spec. Ref.

09.1 (an acid which) is partially allow (an acid which) is partially 1 AO1

ionised dissociated 4.4.2.4

4.4.2.6

in aqueous solution allow (when dissolved) in water 1

MP2 is dependent on the award

of MP1

AO /

Spec. Ref.

09.2 pH increases 1 AO2

4.4.2.6

(because) the concentration of 1

hydrogen ions decreases

AO /

Spec. Ref.

09.3 use a (volumetric) pipette to add 1 AO1

the alkali 4.4.2.5

RPA2

ignore beaker

any two from:

• into a conical flask

allow named indicator

• add an indicator (to the do not accept add universal

alkali) indicator

• take the initial burette

reading

• use a white tile (under a

conical flask) – – –

AO /

Spec. Ref.

09.4 0.0045 AO2

(volume of HCl = ) 4.3.4

0.15

= 0.030 (dm3) 1 4.4.2.5

RPA2

(conversion 0.030 dm3 =)

30 (cm3) allow correct conversion of an 1

incorrectly determined volume in

dm3

alternative approach

0.15

(concentration = =)

1000

0.00015 (mol/cm3) (1)

0.0045

(volume = =)

0.00015

30 (cm3) (1) allow correct use of an

incorrectly determined

concentration in mol/cm3

AO /

Spec. Ref.

09.5 allow converse arguments in AO2

terms of magnesium 4.1.2.3

4.2.1.2

allow energy level for shell 4.4.1.2

(calcium’s) outer shell / allow calcium has more shells 1

electrons are further from the

nucleus ignore calcium atoms are larger

(so) the outer electrons are less allow (so) the outer electrons 1

strongly attracted to the nucleus are more shielded from the

nucleus

(so) positive ions are formed allow (so) electrons are more 1

more easily easily lost

Total Question 9 12

How to answer it

Acids, Titrations, and Reactivity

What this question tests

  • Definitions: Understanding the difference between strong and weak acids.
  • pH Scale: Explaining how dilution affects the concentration of H⁺ ions.
  • Required Practical 2: Recalling the precise steps for a titration.
  • Quantitative Chemistry: Calculating volumes using moles and concentration.
  • Periodic Table Trends: Explaining reactivity in Group 2 based on atomic structure.
Question 09.1

Defining a Weak Acid

💡 Key Knowledge

Acids release hydrogen ions (H⁺) in solution. The "strength" of an acid refers to how many of its molecules split up into ions.

✅ Correct Answer

  • An acid that is partially ionised (or dissociated).
  • In aqueous solution (or when dissolved in water).
[2 Marks]

❌ Common Errors

Do not confuse "weak" with "dilute". A weak acid is about the percentage of ionisation, not how much water is mixed with it. You must mention "aqueous solution" to get the second mark.

Question 09.2

pH and Dilution

🧠 Exam Technique

When asked to "explain what happens," state the change first, then give the reason using scientific terminology.

✅ Correct Answer

  • The pH increases.
  • Because the concentration of hydrogen ions (H⁺) decreases.
[2 Marks]
Question 09.3

Titration Procedure

Steps before adding acid from the burette

💡 Key Knowledge

Titrations require high precision. You must use a volumetric pipette for the fixed volume (alkali) and a burette for the variable volume (acid).

✅ Correct Answer (Pick Three)

  1. Use a pipette to add a fixed volume of alkali to a conical flask.
  2. Add an indicator (e.g., phenolphthalein or methyl orange) to the alkali.
  3. Place the flask on a white tile to see the colour change clearly.
  4. Take the initial reading on the burette.
[3 Marks]

❌ Common Errors

Never suggest using "Universal Indicator" for a titration. It changes colour gradually. You must use a single-colour change indicator. Also, "beaker" is usually ignored; always use "conical flask" for titrations to allow for swirling.

Question 09.4

Titration Calculation

📐 Step-by-Step Calculation

The Goal: Find the volume of 0.15 mol/dm³ HCl needed to react with 0.0045 moles of NaOH.

1 Check the Ratio: From the equation NaOH + HCl → NaCl + H₂O , the ratio is 1:1. So, 0.0045 moles of NaOH reacts with 0.0045 moles of HCl.

2 Calculate Volume in dm³:
Volume (dm³) = Moles / Concentration
Volume = 0.0045 / 0.15 = 0.03 dm³

3 Convert to cm³:
0.03 dm³ × 1000 = 30 cm³

Final Answer: 30 cm³ [2 Marks]

❌ Calculation Traps

Students often forget to convert dm³ to cm³. Always check the units requested in the answer line! 1 dm³ = 1000 cm³.

Question 09.5

Reactivity Trends (Group 2)

Why is Calcium more reactive than Magnesium?

🧠 Exam Technique

For "reactivity" questions in Groups 1 or 2, always follow this 3-step logic: Distance → Attraction → Ease of loss.

✅ Correct Answer

  • Calcium's outer shell/electrons are further from the nucleus (it has more shells).
  • There is less attraction between the nucleus and the outer electrons.
  • Outer electrons are lost more easily to form a positive ion.
[3 Marks]

💡 Examiner Commentary

Simply saying "Calcium is a larger atom" is not enough for a mark. You must explain why that size matters—specifically mentioning the distance from the nucleus or shielding by inner shells.

Topics

Chemistry · Required Practicals

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.