AQA GCSE Chemistry Chemistry Paper 1 (Foundation), June 2024: Question 4

10 marks · Low Demand difficulty · Short Answer

Identify properties and uses of nanoparticles, select a transition metal catalyst, and calculate the surface area to volume ratio of a cubic nanoparticle.

Practise this question

Question

Question 4 contains four sub-questions. 04.1 asks for the approximate number of atoms in a nanoparticle, with checkboxes for a few hundred, a few thousand, a few million, and a few billion atoms. 04.2 asks which element (aluminium, iron, or magnesium) is most likely to be used as a catalyst. 04.3 shows a diagram of a wound dressing on an arm and a table listing substances (carbon, silicon dioxide, silver, titanium dioxide) alongside their properties (strong, hard, kills bacteria, blocks light), asking students to draw lines matching sun creams and wound dressings to the best substance. 04.4 shows a cube with dimensions 4 nm by 4 nm by 4 nm, and asks to calculate the surface area, volume, and simplest whole number ratio of surface area to volume using the given formula.
Question text

04 This question is about small particles.

04.1 What is the approximate number of atoms in a nanoparticle?

[1 mark]

Tick ( ) one box.

A few hundred atoms

A few thousand atoms

A few million atoms

A few billion atoms

04.2 Nanoparticles of some elements can be used as catalysts.

Which element is most likely to be used as a catalyst?

Use the periodic table.

[1 mark]

Tick ( ) one box.

Aluminium

Iron

Magnesium 20

04.3 Nanoparticles are used in sun creams and in wound dressings.

A wound dressing is placed next to the skin to prevent infection.

Figure 8 shows a wound dressing.

Figure 8

Table 2 shows some information about substances used in the form of nanoparticles.

Table 2

Substance Property

Carbon Strong

Silicon dioxide Hard

Silver Kills bacteria

Titanium dioxide21 Blocks light

Draw one line from each use to the best substance for that use.

[2 marks]

Use Substance

Carbon

Sun creams Silicon dioxide

Silver

Wound dressings

22 Titanium dioxide

04.4 Figure 9 shows a cubic nanoparticle.

Figure 9

Calculate:

• the surface area of the cubic nanoparticle

• the volume of the cubic nanoparticle

• the simplest whole number ratio of surface area : volume for the cubic nanoparticle.

Use the equation:

surface area of cubic nanoparticle = 6 × surface area of one face

[6 marks]

Surface area of cubic nanoparticle = nm2

Volume of cubic nanoparticle = nm3

Simplest whole number ratio of surface area: volume = :

Mark scheme

Show the mark scheme Mark scheme for Question 4: 04.1 awards 1 mark for 'a few hundred atoms'. 04.2 awards 1 mark for 'iron'. 04.3 awards 1 mark for connecting 'Sun creams' to 'Titanium dioxide' and 1 mark for connecting 'Wound dressings' to 'Silver'. 04.4 awards marks for: surface area calculation (6 × 4² = 96 nm², 2 marks), volume calculation (4³ = 64 nm³, 2 marks), and ratio calculation (96 : 64 simplified to 3 : 2, 2 marks, with error carried forward allowed). Total 10 marks.

Question 4

AO /

Question Answers Extra information Mark

Spec. Ref.

04.1 a few hundred atoms 1 AO1

4.2.4.1

AO /

Spec. Ref.

04.2 iron 1 AO3

4.1.3.2

AO /

Question Answers Mark

Spec. Ref.

04.3 AO3

4.2.4.2

– – –

do not accept more than one line from a box on the left

AO /

Spec. Ref.

04.4 (surface area =) 6 × 42 1 AO2

4.2.4.1

= 96 (nm2) 1

(volume =) 43 1

= 64 (nm3) 1

(ratio =) 96 : 64 allow correct use of incorrectly 1

determined area and/or volume

= 3 : 2 allow correct use of an 1

incorrectly determined ratio

Total Question 4 10

How to answer it

Nanoparticles: Properties, Uses & Calculations

📋 Specification Focus: 4.2.4 (Nanoparticles) & 4.1.3 (Transition Metals)

What this question tests:

  • Recall of the scale and atomic composition of nanoparticles.
  • Linking elements to their chemical functions (catalysis and transition elements).
  • Applying given properties of nanomaterials to real-world uses (silver and titanium dioxide).
  • Step-by-step mathematical calculations: surface area of a 3D cube, volume, and reducing a surface area-to-volume ratio to its simplest whole numbers.

Question 04.1: Particle Scale

Number of atoms in a nanoparticle (1 mark)

✅ Correct Answer

A few hundred atoms

awarded for ticking the first box.

💡 Key Knowledge

Nanoparticles range in size from 1 to 100 nm across. A typical nanoparticle contains only a few hundred atoms, making them larger than individual atoms/small molecules, but vastly smaller than fine particles or macroscopic matter.

❌ Common Errors

Students often tick "a few million" or "a few billion". While a macroscopic grain of sand has trillions of atoms, nanoparticles are unimaginably small and contain only hundreds of atoms.

Question 04.2: Catalysts & Periodic Table

Choosing the catalyst element (1 mark)

✅ Correct Answer

Iron

awarded for ticking "Iron".

🧠 Exam Technique

The prompt says "Use the periodic table". This is your clue to check where these metals sit:

  • Iron is a transition metal (found in the central block). Transition metals and their compounds are classic catalysts (e.g. Haber process).
  • Aluminium (Group 3) and Magnesium (Group 2) are main-group metals and rarely used as elemental catalysts.

Question 04.3: Applications of Nanoparticles

Matching use to substance (2 marks)

✅ Correct Answers

  • Sun creams ➔ Titanium dioxide [1 mark]
  • Wound dressings ➔ Silver [1 mark]

💡 Property-to-Use Matching

Use the data given in Table 2 directly:

  • Sun creams: Need to block UV rays ➔ Property: Blocks light ➔ Titanium dioxide.
  • Wound dressings: Need to prevent infection ➔ Property: Kills bacteria (antimicrobial) ➔ Silver.

❌ Common Errors & Examiner Warning

Rule check: The mark scheme specifically states: "do not accept more than one line from a box on the left". If you draw two lines emerging from "Sun creams", that mark is automatically lost—even if one of your lines points to titanium dioxide!

Question 04.4: Surface Area, Volume & Ratio Calculations

Cube dimensions: 4 nm × 4 nm × 4 nm (6 marks)

📐 Step-by-Step Calculation

Step 1: Calculate Total Surface Area

  • Area of one face = 4 nm × 4 nm = 16 nm²
  • Formula provided: surface area = 6 × surface area of one face
  • Total Surface Area = 6 × 16 = 96 nm²
  • ➔ 2 marks: [1 mark for formula/working 6 × 4², 1 mark for 96]

Step 2: Calculate Volume

  • Volume of a cube = length × width × height = 4³
  • Volume = 4 × 4 × 4 = 64 nm³
  • ➔ 2 marks: [1 mark for working 4³, 1 mark for 64]

Step 3: Determine Simplest Whole Number Ratio (Surface Area : Volume)

  • Initial ratio = 96 : 64 [1 mark]
  • Divide both sides by the greatest common divisor (32):
    96 ÷ 32 = 3
    64 ÷ 32 = 2
  • Simplest whole number ratio = 3 : 2 [1 mark]

🧠 Exam Technique: Error Carried Forward (ECF)

Notice the mark scheme allows "correct use of incorrectly determined area and/or volume". Even if you made an arithmetic slip in Step 1 or Step 2, you can still gain the final 2 marks by correctly stating and simplifying the ratio of your calculated numbers!

❌ Common Errors

  • Reversing the ratio: Writing 2 : 3 instead of 3 : 2 . The question asks for surface area : volume.
  • Forgetting all 6 faces: Calculating only one face ( 16 nm² ) and failing to multiply by 6.
  • Not simplifying: Leaving the answer as 96 : 64 or 48 : 32 . Always divide down until no common factors remain!

Topics

Chemistry · C1: Atomic Structure and the Periodic Table · C2: Bonding, Structure and the Properties of Matter

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Foundation), June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.